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Number Systems Test - 23

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Number Systems Test - 23
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  • Question 1
    1 / -0
    The value of $$(10)^{0} \times (20)^{0}\times (30)^{0}$$ is:
    Solution
    $$(10)^{0} \times (20)^{0} \times (30)^{0} = 1\times 1\times 1 = 1$$

    So, option $$A$$ is correct.
  • Question 2
    1 / -0
    The expression $$((2)^{0} + (3)^{0} + (5)^{0})^{0}$$ is equal to _____
    Solution
    $$((2)^{0} + (3)^{0} + (5)^{0})^{0} = (1 + 1 + 1)^{0}$$
                                           $$= 3^{0}$$
                                           $$= 1$$

    So, option $$B$$ is the correct answer.
  • Question 3
    1 / -0
    Which of the following is equal to $$1$$?
    Solution
    $$\textbf{Step 1: Simplify the following expressions.}$$

                  $$(a)\ 3^0+3^0=1+1=2\neq 1$$

                  $$(b)\ 3^0-3^0=1-1=0\neq 1$$
     
                  $$(c)\ 3^0=1$$

                  $$(d)\ (3^3)^0+(3^0)^3=9^0+1^3=1+1=2\neq 1$$

    $$\textbf{Hence, Option C is correct.}$$
  • Question 4
    1 / -0
    Simplify: $$\left((9)^{0} + (11)^{0} + (13)^{0}\right) \div (23)^{0}$$
    Solution
    $$\left((9)^{0} + (11)^{0} + (13)^{0}\right) \div (23)^{0}$$
    $$= (1 + 1 + 1) \div 1$$
    $$= 3\div 1$$
    $$= 3$$
    So, option $$B$$ is correct.
  • Question 5
    1 / -0
    What are rational numbers?
    Solution
    A number of the form $$\dfrac {p}{q}$$ where $$p$$ and $$q$$ are any integers and $$q\neq 0$$ is called a rational number.

    Ex:- Consider $$\dfrac{2}{3}$$ here $$2,3$$ are co-primes so the number $$\dfrac{2}{3}$$ is a rational  number
  • Question 6
    1 / -0
    The value of $$((6)^{0} + (16)^{0}) \div ((7)^{0} + (17)^{0})$$ is _____
    Solution
    $$((6)^{0} + (16)^{0}) \div ((7)^{0} + (17)^{0})$$
    $$ = (1 + 1)\div (1 + 1)$$
    $$= 2\div 2$$
    $$= 1$$
    So, option $$C$$ is correct.
  • Question 7
    1 / -0
    The value of $$(100)^{0}$$ is _____.
    Solution
    According to the law of power of $$0$$,
    $$(100)^{0} = 1$$.

    So, option $$A$$ is correct.
  • Question 8
    1 / -0
    Evaluate: $$({(10)^0} + (12)^{0})\times (18)^{0}$$
    Solution
    $$((10)^{0} + (12)^{0})\times (18)^{0} = (1 + 1) \times 1$$
    $$= (2)\times 1$$
    $$= 2$$
    So. option $$C$$ is correct.
  • Question 9
    1 / -0
    $$\dfrac {7}{9}$$ is a/an _______ number.
    Solution
    $$\dfrac{7}{9}$$ is of the form  $$\dfrac {p}{q}$$ form , hence it is rational no.

  • Question 10
    1 / -0
    $$\sqrt {23}$$ is not a ...... number.
    Solution
    As per the theorem, the square root of any prime number is irrational. $$\sqrt {23}$$ is a prime number, so is not a rational number. It is irrational.
    Therefore, $$D$$ is the correct answer.
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