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Constructions Test - 4

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Constructions Test - 4
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Weekly Quiz Competition
  • Question 1
    1 / -0

    With the help of a ruler and a compass, it is possible to construct an angle of ____.

    Solution

    With the help of a ruler and a compass, we can construct an angle which is a multiple of 150. Since 7.50 is multiple of 150, so, we can construct it.

  • Question 2
    1 / -0

    With the help of a ruler and a compass, it is not possible to construct an angle of ____.

    Solution

    With the help of a ruler and a compass, it is not possible to construct an angle which is not a multipe of 150. Since 400 ia not a multiple of 150, so, we cannot construct it.

  • Question 3
    1 / -0

    Two or more circles are congruent, if they have same_________.

    Solution

    Two circles are congruent if they are of same size. The size can be measured as the radii, diameter. So, if two circles have same radii or diameter, then those circles are congruent.

  • Question 4
    1 / -0

    Two or more circles are concentric if they have same_______.

    Solution

    Concentric circles are those which have same centres but different radii or diameters.

  • Question 5
    1 / -0

    If two circles touches internally then distance between their centers is equal to_________.

    Solution

    Consider, two circles with Centre A & B touches internally at point P,

    Now distance between their Centre i.e. AB can be given as,    AB= AP - BP, where,

    AP= radius of circle A ;  BP= radius of circle B 

    Thus, we can say that the distance between the centers of two circles touching internally is equal to the difference of their radii.

  • Question 6
    1 / -0

    Radius of a circle is ________ to tangent.

    Solution

    Consider a circle with Centre O and radius 'r', AB is the tangent on circle O touching the circle at point P. Join OP such that OP becomes the radius of circle O. Now let us take a point Q , other than P, on the tangent AB. Join OQ.  Since Q is a point on tangent AB, other than the point of contact P, so Q will be outside the circle.

    Let OQ intersect the circle at R.

    Then OQ = OR + RQ

    ⟹OQ > OR

    ⟹OQ > OP ( OR=OP=RADIUS)

    Thus, OP is the shortest distance among all line segments which is thus perpendicular from O on AB.

    Hence, OP is perpendicular to AB.

  • Question 7
    1 / -0

    Two radii of same circle are always ___________to each other.

    Solution

    The radius of any circle is defined as the distance of any point on the circumference of the circle from the Centre of the circle. Since, Centre of any circle is only one. 

    Thus, any radius will always be drawn from Centre , hence, both radii will meet and inclined at an angle.

  • Question 8
    1 / -0

    A quadrilateral can be drawn if the measures of its ___________.

    Solution

    At first we will have to draw the diagonal and then by taking end points of diagonals as the Centre we can draw the arcs corresponding to the length of the four sides given. Therefore, the measures of four sides and one diagonal is necessary for the construction of a quadrilateral.

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