Surface Areas and Volumes Test

Result

Surface Areas and Volumes Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

The total surface area of a cube is 96cm².

A
27cm³

B
64 cm³

C
512 cm³

D
cm³
Question 2
1 / -0

The lateral surface area of a cube is 256 m² The volume of the cube is

A
512 m³.

B
64 m³.

C
256 m³.

D
216 m³.

Solution

Explanation:

LSA of cube = 4 ×side²

256 = 4 side²

Side² = 256/4

=64

Side = 8m

Volume of cube = side³

= 8³

=8×8×8

=512m³
Question 3
1 / -0

The difference between the total surface area of a cube of side 4 cm and its lateral surface area is

A
16 cm².

B
24 cm².

C
32 cm².

D
20 cm².

Solution

Explanation:

TSA of cube - LSA of cube

= 6a² - 4a²

= 2a²

= 2 ×4×4

= 32 cm²
Question 4
1 / -0

The volume of a cube whose diagonal is 8√3 cm is

A
64 cm³.

B
256 cm³.

C
128 cm³.

D
512 cm³.
Question 5
1 / -0

The number of 6 m cubes that can be formed from another cuboid measuring 18m × 12m × 9m is

A
10.

B
15.

C
9.

D
12.

Solution

Explanation:

Volume of cube = a³

=6×6×6= 216

Volume of cuboid =l*b*h

=18×12×9

Number of cube = volume of cuboid /volume of cube

= 1944/216 = 9
Question 6
1 / -0

The length of the longest rod that can be placed in a room 12 m long, 9 m broad and 8 high is

A
20 m.

B
17 m.

C
18 m.

D
15 m.

Solution

Explanation:

Diagonal of cuboid

= √ ( L² + B² + C² )

= √ ( 12² + 9² + 8² )

= √ 289

= 17 m

Thus, longest rod that could be placed would be along diagonal.i.e 17 m
Question 7
1 / -0

The edge of a cube whose volume is equal to the volume of a cuboid of dimensions 36 cm × 75 cm × 80 cm is

A
42 cm.

B
60 cm.

C
48 cm.

D
36 cm.

Solution

Explanation:

Volume of cube = volume of cuboid

Volume of cube = 36×75×80

Edge³ = 216000 cm³

Edge = (216000)^1/3

= 60 cm
Question 8
1 / -0

A rectangular pit of dimensions 30m × 15m × 12m is dug and the earth taken out is disposed off in a carrier which can carry a maximum load of 3540m³ of earth. The least number of rounds the carrier had to make to dispose off the earth dug out is

A
10.

B
12.

C
20.

D
15.

Solution

Explanation:

Volume of pit = 30×15×12=5400 m²

Number of round = Volume of pit ÷ volume of carrier

= 5400 ÷ 540 = 10
Question 9
1 / -0

A granary is in the shape of a cuboid of size 16 m × 12 m × 9 m. If a bag of grain occupies a space of 0.48 m³,then the maximum number of bags that can be stored in the granary is

A
3000.

B
1800.

C
2400.

D
3600.

Solution

Explanation:

Volume of granary = 16 ×12 × 9

=1728m³

Volume of one bag = 0.48 m³

Number of bags

= volume of granary ÷ volume of bag

= ( 1728)÷ 0.48

=3600

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Re-Attempt Weekly Quiz Competition

Surface Areas and Volumes Test - 1

Result

Surface Areas and Volumes Test - 1

Score

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Rank

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SHARING IS CARING

Question 1

27cm3

64 cm3

512 cm3

cm3

Question 2

512 m3.

64 m3.

256 m3.

216 m3.

Solution

Question 3

16 cm2.

24 cm2.

32 cm2.

20 cm2.

Solution

Question 4

64 cm3.

256 cm3.

128 cm3.

512 cm3.

Question 5

10.

15.

9.

12.

Solution

Question 6

20 m.

17 m.

18 m.

15 m.

Solution

Question 7

42 cm.

60 cm.

48 cm.

36 cm.

Solution

Question 8

10.

12.

20.

15.

Solution

Question 9

3000.

1800.

2400.

3600.

Solution

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27cm³

64 cm³

512 cm³

cm³

512 m³.

64 m³.

256 m³.

216 m³.

16 cm².

24 cm².

32 cm².

20 cm².

64 cm³.

256 cm³.

128 cm³.

512 cm³.