Surface Areas and Volumes Test

Result

Surface Areas and Volumes Test - 17

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Find the surface area of a cube whose edge is $$15\ cm$$

A
$$1350\ {cm}^{2}$$

B
$$1300\ {cm}^{2}$$

C
$$1050\ {cm}^{2}$$

D
$$1250\ {cm}^{2}$$

Solution

The edge of the cube$$=15cm$$ i.e., $$a=15cm$$
Surface area of the cube $$=6{a}^{2}=6\times {(15)}^{2}=1350{cm}^{2}$$
Question 2
1 / -0

If $$l = 150 cm, b = 1 m$$ and $$h = 2 m$$ then, the volume of the cuboid is

A
$$3,00,000$$ cu. m.

B
$$3,00,00,000$$ cu. cm.

C
$$30,00,000$$ cu. cm.

D
$$30,000$$ cu. m.

Solution

Volume of a cuboid with dimensions as $$l,\ b,\ and\ h=lbh$$
Converting all the given dimensions to centimeters.
Hence, volume of the given cuboid $$=150 \times 100 \times 200 =30,00,000$$ cu.cm
Question 3
1 / -0

The number of surface areas in right circular cylinder is

A
$$1$$

B
$$2$$

C
$$3$$

D
$$4$$

Solution

As shown in figure of right circular cylinder, we have $$3$$ Surface areas they are :
Top Circular base area$$= \pi r^2$$
Lateral Surface area $$=2 \pi r$$
Bottom Circular base area $$=\pi r^2$$
hence, option $$C$$ is correct.
Question 4
1 / -0

Find the volume of a sphere of radius $$2.1\;cm$$.

A
$$34.8\;cm^3$$

B
$$35.8\;cm^3$$

C
$$38.8\;cm^3$$

D
$$36.8\;cm^3$$

Solution

Volume of sphere$$ =$$ $$\dfrac { 4 }{ 3 } \pi { r }^{ 2 }=\dfrac { 4 }{ 3 } \times \dfrac { 22 }{ 7 } \times 2.1\times 2.1\times 21$$

$$=$$ $$38.8$$ $${ cm }^{ 3 }$$
Question 5
1 / -0

The surface area of a cube of side is $$27\ \text{cm}$$ is:

A
$$2916{\ \mathrm{cm}}^{2}$$

B
$$729{\ \mathrm{cm}}^{2}$$

C
$$4374{\ \mathrm{cm}}^{2}$$

D
$$19683{\ \mathrm{cm}}^{2}$$

Solution

Surface area of a cube of side $$a$$ is given by, $$S=6\ a^2$$
The side of cube is given , $$a=27\ \mathrm{cm}$$
Total surface area of given cube of side $$a = 6{a}^{2}=6\times 27^2\ \mathrm{cm}^2 $$
$$= 4374\ \mathrm{cm}^{2} $$
Question 6
1 / -0

Volume of a cuboid whose $$l=3.5$$ m, $$b =2.5$$ m and $$h =1.5$$ m is

A
$$13.12$$ cu m

B
$$13.215$$ cu m

C
$$13.125$$ cu m

D
$$13.521$$ cu m

Solution

Since, volume of cuboid $$=$$ length $$\times$$ breadth $$\times$$ height

Here, length $$=$$ $$3.5$$ m, breadth $$=$$ $$2.5$$ m and height $$=$$ $$1.5$$ m

$$\therefore$$ Volume of cuboid $$=$$ $$3.5\times 2.5\times 1.5 = 13.125 m^3 $$
Question 7
1 / -0

The radius of the cylinder whose lateral surface area is $$704{cm}^{2}$$ and height $$8$$ cm is:

A
$$6$$ cm

B
$$4$$ cm

C
$$8$$ cm

D
$$14$$ cm

Solution

Curved surface area of a cylinder of radius "$$R$$" and height "$$h$$" $$ = 2\pi Rh$$
Hence, Curved surface area of the given cylinder $$ = 2\times \dfrac {22}{7} \times r \times 8 = 704 $$
$$ \therefore r = 14 $$ cm
Radius of the base of the cylinder is $$ 14 $$ cm
Question 8
1 / -0

The radius of a sphere of lead is $$8$$cm. The number of spheres of radius $$5$$mm made by melting it will be

A
$$6000$$ approx

B
Greater than $$4000$$ and less than $$5000$$

C
Greater than $$3000$$ and less than $$4000$$

D
Less than $$3000$$

Solution

Number of spheres = $$\dfrac { volume\quad of\quad sphere\quad of\quad radius\quad 80mm\quad (8cm) }{ Volume\quad of\quad sphere\quad of\quad radius\quad 5\quad mm } \quad =\quad \dfrac { \dfrac { 4\pi }{ 3 } \quad *\quad { 80 }^{ 3 } }{ \dfrac { 4\pi }{ 3 } \quad *\quad { 5 }^{ 3 } } \quad =\quad \dfrac { 512000 }{ 125 } \quad =\quad 4096$$
(Greater than $$4000$$ and less than $$5000$$)
Question 9
1 / -0

The volume of a sphere of diameter 2p cm is given by

A
$$ \displaystyle \pi p^{2}cm ^{3} $$

B
$$ \displaystyle \pi p^{3}cm ^{3} $$

C
$$ \displaystyle 4 \pi p^{2}cm ^{3} $$

D
$$ \displaystyle \frac{4}{3}\pi p^{3}cm ^{3} $$

Solution

GIven the diameter of sphere is 2p
Then radius of sphere=$$\frac{2p}{2}=p cm$$
Then volume of sphere=$$\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi (p)^{3}=\frac{4}{3}\pi p^{3}cm^{3}$$
Question 10
1 / -0

If the radius of a sphere is doubled what is the ratio of the volume of the first sphere to that of the second?

A
$$2:8$$

B
$$1:2$$

C
$$1:3$$

D
$$1:8$$

Solution

Let the radius be $$r$$ If the radius is doubled the new radius will be $$2r$$ Therefore
Ratio of volumes $$=\displaystyle \dfrac{4}{3}\pi r^{3}:\dfrac{4}{3}\pi \left ( 2r \right )^{3}$$
$$=\displaystyle r^{3}:8r^3$$
$$=\displaystyle 1:8$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Surface Areas and Volumes Test - 17

Result

Surface Areas and Volumes Test - 17

Score

-

Rank

-

SHARING IS CARING

Question 1

$$1350\ {cm}^{2}$$

$$1300\ {cm}^{2}$$

$$1050\ {cm}^{2}$$

$$1250\ {cm}^{2}$$

Solution

Question 2

$$3,00,000$$ cu. m.

$$3,00,00,000$$ cu. cm.

$$30,00,000$$ cu. cm.

$$30,000$$ cu. m.

Solution

Question 3

$$1$$

$$2$$

$$3$$

$$4$$

Solution

Question 4

$$34.8\;cm^3$$

$$35.8\;cm^3$$

$$38.8\;cm^3$$

$$36.8\;cm^3$$

Solution

Question 5

$$2916{\ \mathrm{cm}}^{2}$$

$$729{\ \mathrm{cm}}^{2}$$

$$4374{\ \mathrm{cm}}^{2}$$

$$19683{\ \mathrm{cm}}^{2}$$

Solution

Question 6

$$13.12$$ cu m

$$13.215$$ cu m

$$13.125$$ cu m

$$13.521$$ cu m

Solution

Question 7

$$6$$ cm

$$4$$ cm

$$8$$ cm

$$14$$ cm

Solution

Question 8

$$6000$$ approx

Greater than $$4000$$ and less than $$5000$$

Greater than $$3000$$ and less than $$4000$$

Less than $$3000$$

Solution

Question 9

$$ \displaystyle \pi p^{2}cm ^{3} $$

$$ \displaystyle \pi p^{3}cm ^{3} $$

$$ \displaystyle 4 \pi p^{2}cm ^{3} $$

$$ \displaystyle \frac{4}{3}\pi p^{3}cm ^{3} $$

Solution

Question 10

$$2:8$$

$$1:2$$

$$1:3$$

$$1:8$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.