Surface Areas and Volumes Test

Result

Surface Areas and Volumes Test - 35

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A parcel has to be packed with length $$1$$ m, width $$0.1$$ m and height $$0.05$$ m. Find the volume of the parcel in cubic cm.

A
$$\displaystyle { 6050\ cm }^{ 3 }$$

B
$$\displaystyle { 7000\ cm }^{ 3 }$$

C
$$\displaystyle { 5000\ cm }^{ 3 }$$

D
$$\displaystyle { 1300\ cm }^{ 3 }$$

Solution

Given dimensions of the parcel are, length $$= 1$$ m or $$100$$ cm, width $$= 0.1$$ m or $$10$$ cm and height $$= 0.05$$ m or $$5$$ cm
Therefore, volume of the parcel $$=$$ length $$\times$$ width $$\times$$ height
$$\displaystyle =\left( 100\times 10\times 5 \right) { cm }^{ 3 }$$
$$\displaystyle =5000{\ cm }^{ 3 }$$
Question 2
1 / -0

Find the total surface area of a cuboid given $$l =10\ cm,$$ $$h = 4\ cm$$ and $$w = 13\ cm$$.

A
$$444{ \ cm }^{ 2 }$$

B
$$222{\ cm }^{ 2 }$$

C
$$333{ \ cm }^{ 2 }$$

D
$$111{ \ cm }^{ 2 }$$

Solution

$$\begin{aligned}{}{\text{Area}} &= 2(lw + wh + hl)\\ &= 2 \left( {10 \times 13 + 13 \times 4 + 4 \times 10} \right)\\& = 2 \left( {130 + 52 + 40} \right)\\& = 2 \times 222\\ &= 444\ c{m^2}\end{aligned}$$
Question 3
1 / -0

Find the surface area of a cuboid with dimensions $$ 4 \times 2.5 \times 2$$ (in inches)

A
$$\displaystyle 46{ \text{ in.} }^{ 2 }$$

B
$$\displaystyle 12{\text{ in.} }^{ 2 }$$

C
$$\displaystyle 26\text{ in.}^{ 2 }$$

D
$$\displaystyle 14{\text{ in.} }^{ 2 }$$

Solution

According to the given dimensions let,
$$l=4\text{ in.}$$
$$w=2.5\text{ in.}$$
$$h=2\text{ in.}$$

By using the formula of total surface area of a cuboid we get,
$$\begin{aligned}{}{\rm{Area}} &= 2(lw + wh + hl)\\ &= 2\left( {4 \times 2.5 + 2.5 \times 2 + 4 \times 2} \right)\\ &= 2\left( {10 + 5 + 8} \right)\\ &= 2 \times 23\\ &= 46\text{ in.}^2\end{aligned}$$
Question 4
1 / -0

Find the volume of a cuboid whose length is $$100\ m,$$ breadth is $$0.2\ m$$ and height is $$0.15\ m.$$

A
$$3\ { m }^{ 3 }$$

B
$$1.25\ { m }^{ 3 }$$

C
$$4\ { m }^{ 3 }$$

D
$$5\ { m }^{ 3 }$$

Solution

Volume of the cuboid whose length is $$l,$$ breadth is $$b$$ and height is $$h$$ is given by,
$$V=l\times b\times h$$

Given:
$$l= 100\ m$$
$$b= 0.2\ m$$
$$h= 0.15\ m$$

So,
$$V=100\times 0.2\times 0.15$$
$$=20\times 0.15$$
$$=3\ m^3$$

Hence, option $$A$$ is correct.
Question 5
1 / -0

Find the volume of the cuboid having length, breadth and height as $$12$$ cm, $$15$$ cm and $$30$$ cm.

A
$$\displaystyle 6000{ cm }^{ 3 }$$

B
$$\displaystyle 5400{ cm }^{ 3 }$$

C
$$\displaystyle 4200{ cm }^{ 3 }$$

D
$$\displaystyle 5000{ cm }^{ 3 }$$

Solution

Volume of the cuboid $$=$$ length $$\times$$ breadth $$\times$$ height
Therefore, length $$= 12$$ cm, breadth $$= 15$$ cm, height $$= 30$$ cm
Volume of the cuboid $$\displaystyle \\ = 12\times 15\times 30=5400{ cm }^{ 3 }\\ $$
Question 6
1 / -0

Find the surface area of a cuboid:

A
$$\displaystyle 110$$ unit $$^{ 2 }$$

B
$$\displaystyle 120$$ unit $$^{ 2 }$$

C
$$\displaystyle 130$$ unit $$^{ 2 }$$

D
$$\displaystyle 140$$ unit $$^{ 2 }$$

Solution

Surface area $$= 2 ($$Length $$\times$$ width $$+$$ Length $$\times$$ height $$+$$ Width $$\times$$ height$$)$$

Length $$= 5$$ units; Height $$= 5$$ units; Width $$= 4$$ units

$$\displaystyle =2\times \left( 5\times 4+5\times 5+4\times 5 \right) $$

$$\displaystyle =2\times \left( 20+25+20 \right) $$

$$\displaystyle =2\times 65$$

$$\displaystyle= 130$$ unit $$^{ 2 }$$
Question 7
1 / -0

Michael has a box measured $$2.1$$ meters in length, $$1.9$$ meters in height and $$2.5$$ meters in width. What is the surface area of his box can hold?

A
$$\displaystyle 18.21{ m }^{ 2 }$$

B
$$\displaystyle 20.21{ m }^{ 2 }$$

C
$$\displaystyle 27.98{ m }^{ 2 }$$

D
$$\displaystyle 18.08{ m }^{ 2 }$$

Solution

Surface area $$=$$ $$2 \times$$ $$($$Length $$\times$$ width $$+$$ Length $$\times$$ height $$+$$ Width $$\times$$ height$$)$$
Length $$= 2.1$$ m; Height $$= 1.9$$ m; Width $$= 2.5$$ m
$$\displaystyle =2\times \left( 5.25+3.99+4.75 \right) $$
$$\displaystyle =2\times 13.99$$
$$\displaystyle =27.98$$ $${ m }^{ 2 }$$
Question 8
1 / -0

The edge of the cube measures $$9$$ cm. Find its surface area.

A
$$\displaystyle 418{ cm }^{ 2 }$$

B
$$\displaystyle 446{ cm }^{ 2 }$$

C
$$\displaystyle 486{ cm }^{ 2 }$$

D
$$\displaystyle 441{ cm }^{ 2 }$$

Solution

Given, edge $$= 9 \text{ cm}$$
Total surface area of a cube $$=6\times \text{side}^2$$
$$= 6\times 9\times 9$$
$$= 486 \text{ cm}^2$$
Question 9
1 / -0

Find the surface area of the cuboid:

A
$$\displaystyle 300.1{ mm }^{ 2 }$$

B
$$\displaystyle 320.5{ mm }^{ 2 }$$

C
$$\displaystyle 316.4{ mm }^{ 2 }$$

D
$$\displaystyle 305.2{ mm }^{ 2 }$$

Solution

Surface area of the cuboid $$=$$ $$\displaystyle 2\times \left( lw+lh+hw \right) $$
$$\displaystyle =2\times \left( 8\times 2.1+8\times 14+2.1\times 14 \right) $$
$$\displaystyle =2\times \left( 16.8+112+29.4 \right) $$
$$\displaystyle =2\times 158.2$$
$$\displaystyle =316.4$$ $${ mm }^{ 2 }$$
Question 10
1 / -0

The volume of a cylinder is $$616$$ cubic feet and height $$4$$ feet. Find its curved surface area. (Use $$\displaystyle \pi ={ 22 }/{ 7 }$$)

A
$$\displaystyle 88{ ft }^{ 2 }$$

B
$$\displaystyle 198{ ft }^{ 2 }$$

C
$$\displaystyle 79{ ft }^{ 2 }$$

D
$$\displaystyle 176{ ft }^{ 2 }$$

Solution

Volume of a cylinder $$=$$ $$\displaystyle \pi { r }^{ 2 }h$$

$$\Rightarrow \displaystyle 616=\frac { 22 }{ 7 } \times { r }^{ 2 }\times 4$$

$$\Rightarrow \displaystyle \frac { 616\times 7 }{ 22\times 4 } ={ r }^{ 2 }$$

$$\Rightarrow \displaystyle { r }^{ 2 }=49$$

$$\Rightarrow \displaystyle r=\sqrt { 49 } =7ft$$

Curved surface area $$=$$ $$\displaystyle 2\pi rh$$

$$\displaystyle =2\times \frac { 22 }{ 7 } \times 7\times 4$$

$$\displaystyle =176$$ square feet

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Surface Areas and Volumes Test - 35

Result

Surface Areas and Volumes Test - 35

Score

-

Rank

-

SHARING IS CARING

Question 1

$$\displaystyle { 6050\ cm }^{ 3 }$$

$$\displaystyle { 7000\ cm }^{ 3 }$$

$$\displaystyle { 5000\ cm }^{ 3 }$$

$$\displaystyle { 1300\ cm }^{ 3 }$$

Solution

Question 2

$$444{ \ cm }^{ 2 }$$

$$222{\ cm }^{ 2 }$$

$$333{ \ cm }^{ 2 }$$

$$111{ \ cm }^{ 2 }$$

Solution

Question 3

$$\displaystyle 46{ \text{ in.} }^{ 2 }$$

$$\displaystyle 12{\text{ in.} }^{ 2 }$$

$$\displaystyle 26\text{ in.}^{ 2 }$$

$$\displaystyle 14{\text{ in.} }^{ 2 }$$

Solution

Question 4

$$3\ { m }^{ 3 }$$

$$1.25\ { m }^{ 3 }$$

$$4\ { m }^{ 3 }$$

$$5\ { m }^{ 3 }$$

Solution

Question 5

$$\displaystyle 6000{ cm }^{ 3 }$$

$$\displaystyle 5400{ cm }^{ 3 }$$

$$\displaystyle 4200{ cm }^{ 3 }$$

$$\displaystyle 5000{ cm }^{ 3 }$$

Solution

Question 6

$$\displaystyle 110$$ unit $$^{ 2 }$$

$$\displaystyle 120$$ unit $$^{ 2 }$$

$$\displaystyle 130$$ unit $$^{ 2 }$$

$$\displaystyle 140$$ unit $$^{ 2 }$$

Solution

Question 7

$$\displaystyle 18.21{ m }^{ 2 }$$

$$\displaystyle 20.21{ m }^{ 2 }$$

$$\displaystyle 27.98{ m }^{ 2 }$$

$$\displaystyle 18.08{ m }^{ 2 }$$

Solution

Question 8

$$\displaystyle 418{ cm }^{ 2 }$$

$$\displaystyle 446{ cm }^{ 2 }$$

$$\displaystyle 486{ cm }^{ 2 }$$

$$\displaystyle 441{ cm }^{ 2 }$$

Solution

Question 9

$$\displaystyle 300.1{ mm }^{ 2 }$$

$$\displaystyle 320.5{ mm }^{ 2 }$$

$$\displaystyle 316.4{ mm }^{ 2 }$$

$$\displaystyle 305.2{ mm }^{ 2 }$$

Solution

Question 10

$$\displaystyle 88{ ft }^{ 2 }$$

$$\displaystyle 198{ ft }^{ 2 }$$

$$\displaystyle 79{ ft }^{ 2 }$$

$$\displaystyle 176{ ft }^{ 2 }$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.