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Surface Areas and Volumes Test - 7

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Surface Areas and Volumes Test - 7
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  • Question 1
    1 / -0

    The ratio of the radii of two spheres whose volumes are in the ratio 64 : 27 is

    Solution

    volume of sphere 1 : volume of sphere2

          4/3πr1³  : 4/3πr2³

           r1³ : r2³ =64 :27

           r1 : r2 = 4 : 3

  • Question 2
    1 / -0

    Given that the surface area of a spherical shot put is 616cm2. its diameter is

    Solution

    Given,

    Surface area of sphere= 4πr²=616

    4× 22/7 ×r² =616

    r²= 49

    r= 7 cm

    so diameter = 2 ×7= 14 cm

  • Question 3
    1 / -0

    If a spherical balloon grows to twice its radius when inflated, then the ratio of the volume of the inflated balloon to the original balloon is

    Solution

    = volume of the inflated balloon : volume of the original balloon

             =     4/3π(2r)³  :  4/3π(r)³

             =                 8  :  1

  • Question 4
    1 / -0

    If the total surface area of a hemisphere is 1848 cm2, then the diameter is 

    Solution

    Total surface area of hemisphere= 1848 cm²

    2 π r² + π r²  = 1848

    3π r² =1848

           r²= (1848 ×7)/22×3

           r²= 196

           r=14 cm

    so, diameter is 28 cm

  • Question 5
    1 / -0

    The total surface area of a cone of radius 7 m and slant height 10 m is

    Solution

    TSA of cone = πr(l+ r)

                           =22/7×7 ( 10+7)

                           =22 × 17

                           = 374 m²

  • Question 6
    1 / -0

    The volume of a cone is 1570 cm3. If it is 15 cm high then its base area is

    Solution

    Volume of cone = 1/3 × π × r² × h

     1570   = 1/3× π  × r² × 15

     π r² = 314 cm2 

    Base area is 314 cm²

  • Question 7
    1 / -0

    If the slant height of a cone of base radius 7 cm is 25 cm, then its height is

    Solution

    l² = r² + h²

    h² = l² - r²

    = 25² - 7²

    = 625 - 49

     = 576

    h = √576

    h= 24 cm

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