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Probability Test - 7

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Probability Test - 7
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  • Question 1
    1 / -0

    A and B throw a pair of dice. If A throws 9, then B’s chance of throwing a higher number is

    Solution

    Given that ‘A’ throws 9 and B throws a higher number than 9
    That is B throws 10 or 11 or 12
    Total number of outcomes on throwing 2 dices = 6 × 6 = 36
    Favourable outcomes are: {(4,6) (5,5), (6,4), (5,6), (6,5), (6,6)}
    Number of favourable outcomes = 6
    ∴ Probability of B throwing a number greater than 9 = 6/36 = 1/6

  • Question 2
    1 / -0

    A child has a block in the shape of a cube with one letter written on each face as shown in the following.

    A A B A C D

    The cube is thrown once. Then, the probability of getting ‘A’ is

    Solution

    Number of possible outcomes = 6
    Number of 'A's on the block = 3
    Therefore, the the probability of getting ‘A’  = 3/6= 1/2

  • Question 3
    1 / -0

    The probability of an event (other than sure and impossible event) lies between

    Solution

    The probability of an event (other than sure and impossible event) lies between 0 and 1 . The probability of any event can never be less than 0 and more than 1.

  • Question 4
    1 / -0

    The probability expressed as a percentage of a particular occurrence can never be

    Solution

    The percentage that expresses our uncertainty about an event can never be less than 0. The uncertainty about any event can be expressed as a percentage between 0 and 100 we can now make the following simple observation.

  • Question 5
    1 / -0

    If P(A) denotes the probability of an event A, then

    Solution

     The probability of any event is a number between 0 and 1.(Mathematicians write this as:

    "0 ≤ P(A) ≤ 1" where P(A) denote the probability of an event (A) 

  • Question 6
    1 / -0

    A card is drawn from a deck of 52 cards. The even E is that card is not an ace of hearts. The number of outcomes favourable to E is

    Solution

    Total possible outcomes = 52

    Event of drawing an ace of hearts (not E) =1

    Therefore, Event of not drawing an ace of hearts (E) i.e. the number of outcomes favourable to E = 52 - 1 = 51

  • Question 7
    1 / -0

    The probability of getting a rotten egg in a lot of 400 is 0.035. The number of rotten eggs in the lot is

    Solution

    Let the number of rotten eggs be x.

    Total number of eggs = 400

    The probability of getting a rotten egg = 0.035 = x/400

    Therefore , x = 0.035 x 400 = 14

    So,the number of rotten eggs =14

  • Question 8
    1 / -0

    One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number which is a multiple of 5, is

    Solution

    Number of possible outcomes = 40

    Multiples of five between 1 to 40 = {5,10,15,20,25,30,35,40} = 8

    Therefore, number of favourable outcomes = 8

    So, the probability that the selected ticket has a number which is a multiple of 5 = 8/40= 1/5

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