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Coordinate Geometry Test - 18

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Coordinate Geometry Test - 18
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  • Question 1
    1 / -0
    Any point on the $$x$$-axis is of the form:
    Solution
    In the $$xy$$-plane, any point on the $$x$$-axis will have $$y =0$$.
    Hence, any point on the $$x$$-axis is of the form $$(x,0)$$.

    Therefore, option $$C$$ is correct.
  • Question 2
    1 / -0
    Without plotting the point indicate the quadrant in which the point will lie, if ordinate is $$5$$ and abscissa is $$3$$?
    Solution
    Given ordinate or $$y$$-coordinate $$= 5$$ 
    and abscissa or $$x$$-coordinate $$=3$$
    $$\therefore$$  $$(x ,y)$$ = $$(3,5)$$ 
    Since, both the coordinates are positive
    The point will lie in $$Quadrant-I$$
  • Question 3
    1 / -0
    Which of the given points lie on $$y$$-axis?
    $$A (1, 1), B (1, 0), C (0, 1), D (0, 0), E (0, 1), F ( 1, 0), G (0, 5), H ( 7, 0), I (3, 3)$$.
    Solution
    If a point is on $$y$$-axis , then the $$x$$ co-ordinate of that point should be zero.
    Here, the $$x$$-coordinate is zero at:
    $$C(0,1)$$,
    $$D(0,0)$$,
    $$E(0,1)$$
    and $$G(0,5)$$.
    Therefore, these points lies on the $$y$$-axis.

    Hence, option $$C$$ is correct.
  • Question 4
    1 / -0
    Write the name of the quadrant in which the point $$( - 3, 5)$$ lies.
    Solution
    The point $$(-3,5)$$ lies at second quadrant

  • Question 5
    1 / -0
    Without plotting the point, indicate the quadrant in which the given point will lies whose ordinate is $$-5$$ and abscissa is $$3$$?
    Solution
    Given: The abscissa is $$+3$$ & ordinate is $$-5$$

    We know that in $$ I^{st}$$ quadrant, both the abscissa and ordinate are positive. 

    In $$II^{nd}$$ quadrant, the abscissa is negative and the ordinate is positive.

    In $$III^{rd}$$ quadrant, the abscissa is negative and the ordinate is negative.

    In $$IV^{th}$$ quadrant, the abscissa is positive and the ordinate is negative. 

    $$\\ \therefore$$ The point lies in the $$IV^{th}$$ quadrant. 

  • Question 6
    1 / -0
    In which quadrant the point $$(2,-3)$$ will lie?
    Solution
    Given point is $$(2,-3)$$
    Since $$x-$$coordinate is positive and $$y-$$coordinate is negative, the given point will lie in the fourth quadrant.

    Hence, option D is correct.
  • Question 7
    1 / -0
    Without plotting the points indicate the quadrant in which the point will lie, if abscissa is $$-5$$ and ordinate is $$-3$$?
    Solution
    In $$\text{I}$$ quadrant, abscissa and ordinates are positive.
    In $$\text{II}$$ quadrant, abscissa is negative and ordinate is positive.
    In $$\text{III}$$ quadrant, both abscissa and ordinate are negative.
    In $$\text{IV}$$ quadrant, abscissa is positive and ordinate is negative.
    Here, the given abscissa is $$-5$$ and ordinate is $$-3$$. Both are negative.
    Thus, they lie in $$\text{III} $$ quadrant.
    Hence, option $$C$$ is correct.

  • Question 8
    1 / -0
    Any point on the line $$y = x $$ is of the form
    Solution


    $${\textbf{Step - 1: Plot and identify points in the Cartesian plane.}}$$

                     $${\text{The given equation is}}$$ $$x = y.$$

                     $${\text{So, if}}$$ $$x = 1$$ $${\text{and}}$$ $$y = 1.$$

                     $${\text{If}}$$ $$x = -5$$ $${\text{and}}$$ $$y = -5.$$

                     $${\text{If}}$$ $$x = 0$$ $${\text{and}}$$ $$y = 0.$$

    $${\textbf{Step - 2: By Induction.}}$$

                      $$x = a$$ $${\text{and}}$$ $$y = a.$$

                      $${\text{So, any point P on the line}}$$ $$x = y$$ $${\text{will be of the form}}$$ $$\text{P} (a, a).$$  

    $${\textbf{ Hence the correct option (A) (a, a).}}$$

  • Question 9
    1 / -0
    State whether True or False:
    A point whose $$y$$-coordinate is zero and $$x$$-coordinate is $$5$$ will lie on the $$y$$-axis.
    Solution
    The given point has $$y$$-coordinate as zero and $$x$$-coordinate as $$5$$.
    So, the point is $$(5,0)$$ and it lies on $$x$$-axis and not $$y$$-axis.
    Thus, the given statement is false.
    Therefore, option $$B$$ is correct.
  • Question 10
    1 / -0
    The points $$(- 5,2)$$ and $$(2, - 5)$$ lie in the :
    Solution
    $$\therefore$$ The point $$(-5,2)$$ lies at quadrant $$II$$ and point $$(2,-5)$$ lies at quadrant $$IV$$

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