Gravitation Test

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Gravitation Test - 18

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Question 1
1 / -0

The weight of an object:

A
is the quantity of the matter it contains

B
refers to its inertia

C
is the same as its mass but is expressed in different unit

D
is the force with which it is attracted towards the earth

Solution

The weight of an object is the force with which it is attracted towards the earth.
Question 2
1 / -0

As we go from the equator to the poles, the value of g :

A
Remains the same

B
Decreases

C
Increases

D
Decreases upto altitude of $$45^o$$

Solution

The gravitational acceleration due to the earth is $$g=\dfrac{GM}{R^2}$$, where $$M$$ is the mass of the earth and $$R$$ is the radius of the earth.
Our planet earth is not an absolute sphere. It has an orange-like structure - flattened at the poles, bulged at the equator. So the radius of the earth is more in the equatorial region as compared to that of the polar region. So, $$R_{equatorial} > R_{poles}$$.
$$\therefore g_{poles}>g_{equator}$$
Question 3
1 / -0

Which of the following statement is true?

A
g is same at all places on the surface of earth.

B
g has its maximum value at the equator.

C
g is less at the earth's surface than at a height above it or a depth below it.

D
g is greater at the poles than at the equator.

Solution

The value of g is maximum at poles and minimum at equator.

Due to the non spherical shape of the earth, the radius of the earth varies at different points on the earth's surface. The radius of the earth at the equator is more than that at the poles.

We know that the formula for calculating the acceleration due to gravity, is given by,

$$g = \dfrac{GM_e}{R_e^2}$$

Since $$R_{equator} > R_{poles}$$

Hence, $$g_{equator}<g_{poles}$$
Question 4
1 / -0

Which of the following physical quantities has no unit?

A
Relative density

B
Density

C
Pressure

D
Thrust

Solution

Quantities such as pressure, density and thrust have units. But relative density is a ratio i.e.,

relative density $$= \dfrac{\text{Density of substance}}{\text{Density of reference substance}}$$.

Thus, relative density does not have a unit.
Question 5
1 / -0

Acceleration of a body projected upwards with a certain velocity is:

A
$$9.8 m/s^2$$

B
$$-9.8 m/s^2$$

C
zero

D
$$\dfrac{9.8}{6}\ m/s^2$$

Solution

Due to the gravitational force acting on the body , towards the center of the earth , a body thrown upwards experiences a negative acceleration (or, a deceleration) of $$9.8 m/s^2 $$.
Question 6
1 / -0

When a body is going upwards vertically the acceleration due to gravity is taken as

A
Positive

B
Negative

C
Both A and B

D
Uncertain

Solution

Generally, the positive direction is assumed to be of the direction of motion and rest of the parameters are adjudged by direction of motion. So, if an object is moving vertically upwards, the direction of motion is positive for upwards journey. Hence, the acceleration due to gravity is taken as negative as its direction is downward.
Question 7
1 / -0

If gravitational mass of a body on the moon be denoted by $$M_m$$ and that on the earth be $$M_e$$, then:

A
$$M_m = \dfrac{1}{6}M_e$$

B
$$M_m = M_e$$

C
$$M_m = 2{M_e}$$

D
$$M_m = 6M_e$$

Solution

Mass is independent of the place where it is measured. Weight can be different at different places with different gravitational field
Question 8
1 / -0

Where will it be profitable to purchase one kilogram sugar?

A
At poles

B
At equator

C
At $$45^o$$ latitude

D
At $$40^o$$ latitude

Solution

As the value of g is minimum at the equator for the same value of mass because of spherical shape of earth. A weight of 1 kg sugar is measured less at the equator.
Question 9
1 / -0

Relative density $$\displaystyle = \frac{\text{density of substance}}{x}$$
Then x is :

A
Density of substance

B
Density of water

C
Density of bottle

D
Density of gas

Solution

Relative density $$\displaystyle = \frac{\text{density of substance}}{\text{density of water}}$$
Relative density is defined as the ratio of the density of a substance to the density of water.
Question 10
1 / -0

A book of mass 20 g is placed on a table. Find the thrust exerted by the book on the table. (Take acceleration due to gravity as $$10 m s^{-2})$$.

A
0.1 N

B
0.2 N

C
0.3 N

D
0.4 N

Solution

Mass of book $$(m)=20 g$$ $$=\frac {20}{1000}kg=\frac {1}{50} kg$$
Acceleration due to gravity (g) $$=10 m s^{-2}$$
$$\Rightarrow T=\frac {1}{50}\times 10=\frac {1}{5}N=0.2 N$$.
Therefore, the thrust acting on the table by the book is 0.2 N.

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Gravitation Test - 18

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Gravitation Test - 18

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Question 1

is the quantity of the matter it contains

refers to its inertia

is the same as its mass but is expressed in different unit

is the force with which it is attracted towards the earth

Solution

Question 2

Remains the same

Decreases

Increases

Decreases upto altitude of $$45^o$$

Solution

Question 3

g is same at all places on the surface of earth.

g has its maximum value at the equator.

g is less at the earth's surface than at a height above it or a depth below it.

g is greater at the poles than at the equator.

Solution

Question 4

Relative density

Density

Pressure

Thrust

Solution

Question 5

$$9.8 m/s^2$$

$$-9.8 m/s^2$$

zero

$$\dfrac{9.8}{6}\ m/s^2$$

Solution

Question 6

Positive

Negative

Both A and B

Uncertain

Solution

Question 7

$$M_m = \dfrac{1}{6}M_e$$

$$M_m = M_e$$

$$M_m = 2{M_e}$$

$$M_m = 6M_e$$

Solution

Question 8

At poles

At equator

At $$45^o$$ latitude

At $$40^o$$ latitude

Solution

Question 9

Density of substance

Density of water

Density of bottle

Density of gas

Solution

Question 10

0.1 N

0.2 N

0.3 N

0.4 N

Solution

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