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Gravitation Test - 32

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Gravitation Test - 32
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  • Question 1
    1 / -0
    When an object is immersed in water, it displaces $$20\,kg$$ of water. How much is the buoyant force acting on the object in Newtons?
    Solution
    According to the Archimedes principle, the buoyant force acting on an object immersed in liquid is equal to the weight of liquid it displaces. Hence the buoyant force acting on the given object=$$20kg\times 10m/s^2=200N$$
  • Question 2
    1 / -0
    What is the relation between thrust and pressure?
    Solution
    Hence pressure=$$P=\dfrac{Thrust}{Area}$$
    $$\implies Pressure\propto Thrust$$
  • Question 3
    1 / -0
    Thrust is which type of force:
    Solution
    Since thrust is a force, it is a vector quantity having both a magnitude and a direction. The engine does work on the gas and accelerates the gas to the rear of the engine; the thrust is generated in the opposite direction from the accelerated gas.
    The force which is perpendicular to the surface on which it is acted is called a thrust.
  • Question 4
    1 / -0
    Always an attractive force is acted between two bodies and this force depends upon the masses of the bodies and the distance between them. This force is:
    Solution
    Newton's gravitational law states that there is always an attractive force between two bodies in universe and this force is directly proportional to the product of masses of two bodies and inversely proportional to square of the distance between the bodies ,this force is called universal gravitational force
                 $$F\propto\dfrac{mm'}{{r}^{2}}$$
    where $$m$$  and  $$m'$$ are the masses of bodies and $$r$$ is the distance between them.
       therefore the given condition describes the universal gravitation.
  • Question 5
    1 / -0

    If the densities of two substances are equal, then what is the relative density of one substance with respect to another?
    Solution
    Relative density is defined as the ratio of density of substance to density of given reference material.
    $$\therefore$$  Relative density    $$d_R  =\dfrac{d_1}{d_2} = \dfrac{d}{d} = 1$$              $$(\because d_1 = d_2=d)$$
  • Question 6
    1 / -0
    A ball is dropped off a high building and strikes the ground with an impact velocity of 30 m/s. The height of the building is :
    Solution
    Given: 
    Initial velocity of the ball     $$u = 0$$
    Final velocity of the ball when it reaches the ground       $$v = 30  m/s$$
    Acceleration = Gravitational acceleration $$g = 10 \space m/s^2$$
    Height $$h = ?$$
    Using       $$v^2  - u^2 = 2g h$$                    where  $$a = g = 10 m/s^2$$
    $$\therefore$$  $$30^2 - 0^2  = 2 \times 10 \times h$$             
    $$\Rightarrow h = 45 \space m$$ 
  • Question 7
    1 / -0
    Fill in the blank. 
    As per Archimedes principle the buoyant force on a submerged object is equal to_______ of liquid displaced by object. 
    Solution
    According to the Archimedes principle, the buoyant force of a submerged object is equal to the weight of the liquid displaced.
    $$\therefore$$ Buoyant force     $$B = \rho gV$$    where $$\rho$$ and $$V$$ is the density of liquid and volume of liquid displaced respectively.
  • Question 8
    1 / -0
    What do you mean by Thrust or Buoyant force?
    Solution
    Thrust or Buoyant force is defined as the upward force exerted by liquid on the body when it is immersed in the liquid.
    $$F_b = \rho\times V\times g$$
  • Question 9
    1 / -0
    What is known as thrust?
    Solution
    The force which is perpendicular to the surface on which it is acts is called a thrust.
    A perpendicular force is also called 'normal' or 'orthogonal' to that surface.
    Hence correct answer is option A.
  • Question 10
    1 / -0
    Why does a mug full of water feel lighter inside water?
    Solution
    When a mug full of water is placed into water, it experiences an upward thrust. This upward thrust is known as the buoyant force. According to the Archimedes' principle,  this force is equal to the weight of the fluid that the body displaces. 

    Hence, the net force experienced by the mug will be, 
    $$F_{net} = F_{weight} - F_{upthrust}$$

    As a result, it appears lighter when placed inside water.


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