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Gravitation Test - 35

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Gravitation Test - 35
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  • Question 1
    1 / -0
    The ratio of the value of gravitational constant $$G$$ between Earth and Moon system and Earth and Sun system is:
    Solution
    According to Newton's law of gravitation, every body in the universe attracts every other body with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
    $$F=\propto \dfrac{Mm}{r^2}$$

    $$F=G \dfrac{Mm}{r^2}$$
    Gravitational constant $$G$$ is the proportionality constant which has fixed value $$6.67408 × 10^{-11} m^3 kg^{-1} s^{-2}$$.
    Therefore, the ratio of the value of gravitational constant $$G$$ between Earth and Moon system and Earth and Sun system is equal to 1. (Because it has the same value)
  • Question 2
    1 / -0
    Unit of acceleration due to gravity is:
    Solution
    Acceleration due to gravity is the acceleration of a body due the gravitational force.
    $$F=mg$$
    $$g=\frac{F}{m}$$
    $$SI$$ units of acceleration due to gravity is $$ms^{-2}$$
  • Question 3
    1 / -0
    A satellite is moving around the Earth in a circular orbit with a velocity $$V$$. If the gravitational force of the Earth were to suddenly disappear, then the satellite would
     
    Solution
    The satellite is held in orbit because of two forces : gravitational force and centrifugal force. When the gravitational force disappears, there is no force to hold it in orbit. So it moves in the direction of its velocity, which is tangential to the circular path it was following earlier.
  • Question 4
    1 / -0
    Buoyant force acting on an object is equal to the ___
    Solution
    Buoyant force acting on an object is equal to weight of liquid displaced by the solid i.e. 
    Buoyant force $$F_B$$:
    $$ F_B = { V }_{ dis}\times { \rho  }_{ l }\times g$$
    here $${ V }_{ dis }$$ is the volume of displaced water. 
    $${ \rho  }_{ l }$$ is density of liquid
    $$g$$ is acceleration due to gravity.
  • Question 5
    1 / -0
    Let M denotes the mass of earth and let R denotes its radius. The ratio g/G at earth's surface is?
    Solution
    Gravity at the surface of earth $$g=\displaystyle\frac{GM}{R^2}$$
    $$\displaystyle\frac{g}{G}=\frac{M}{R^2}$$.
  • Question 6
    1 / -0
    Why does a ship made of steel float on water while an oil-pin of steel sinks down?
    Solution

  • Question 7
    1 / -0
    What will be the weight of a person on earth, who weights 9N on the moon?
    Solution

  • Question 8
    1 / -0
    Gravitation on moon is $$\dfrac{1}{6}$$th of that on earth . When a balloon filled with hydrogen is released on moon then this:
    Solution
    There is no atmosphere on the moon. On earth, air provides enough Buoyant Force. So,that the balloon rises up. Thus, on moon, only gravity acts on it and so it will fall down with acceleration $$= \dfrac{g}{6}$$
  • Question 9
    1 / -0
    A body is brought from the earth to the moon is ___
    Solution

    When we leave the surface of the earth our body weight decreases, mass remains the same, this is due to the gravitational pull on the moon. The gravitational pull is less on the moon than the earth, hence the weight is less. The size of the moon is smaller, only one six of the earth, that is why our weight on the moon is less

  • Question 10
    1 / -0
    How much will a person with 72 N weight on Earth,weight on the moon?
    Solution
    We know,

    $$ g_{earth} = \dfrac{GM}{R^{2}} $$ where, M = mass of planet (earth)

    As moon is lighter than the earth i.e, approx 
    mass of moon $$ = \dfrac{1}{6} $$ (mass of earth)

    $$ \Rightarrow g_{moon} = \dfrac{GM}{R^{2}6} = \dfrac{g_{earth}}{6} $$

    Thus, weight of man on moon is 

    $$ = mg_{moon} = \dfrac{mg_{earth}}{6} = \dfrac{72}{6} = 12 N $$ 
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