Gravitation Test

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Gravitation Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

The atmosphere is held to the earth by:

A
gravity

B
wind

C
clouds

D
earth's magnetic field

Solution

$$\textbf{Hint:}$$ Use the concept of gravity.
$$\textbf{Explanation:}$$
The earth pulls all the objects towards the centre due to gravity. In fact the air inside our earth is held around due to the gravity and the envelope of air around the earth is known as the atmosphere.
Question 2
1 / -0

The force of attraction between the two bodies (A, B) depend upon:

A
mass of $$A$$

B
mass of $$B$$

C
distance between them

D
all of the above

Solution

As per Newton's law of gravitation, the gravitational force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Hence, the force of attraction between the two bodies (A, B) depends upon all the three.
Question 3
1 / -0

The weight of a rock on the moon is $$200.6\ N$$. What is its mass on the earth? (Take $$g$$ of earth $$= 9.8 \ ms^{-2}$$ and $$g$$ of moon $$= 1.7\ m s^{-2}$$)

A
$$20\ kg$$

B
$$118\ kg$$

C
$$200\ kg$$

D
$$1180\ kg$$

Solution

Given,
Weight of the rock on the moon, $$W_m=200.6\ N$$
Acceleration due to o gravity on the surface of the earth, $$g_m=9.8\ m/s^2$$
Acceleration due to o gravity on the surface of the moon, $$g_m=1.7\ m/s^2$$

We know,
Weight, $$W=m\times g$$

$$\implies m=\dfrac Wg$$

$$\implies m=\dfrac {W_m}{g_m}$$

$$ m=\dfrac {200.6}{1.7}$$

$$m= 118\ kg$$

Mass of the rock on the earth $$=$$ Mass of the rock on the moon $$118\ kg$$
The mass of an object is constant and does not change from place to place.
Question 4
1 / -0

A student listed applications of some principles as follows
Submarines
Lactometers

Hydrometers
Barometers
p
q

r
s
Identify the applications of Archimedes' principle from the list.

A
Only $$p,\ q$$ and $$r$$

B
Only $$q,\ r$$ and $$s$$

C
Only $$r,\ s$$ and $$p$$

D
Only $$q,\ p$$ and $$s$$

Solution

According to Archimedes' principle, when a body is immersed fully or partially in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it.
Archimedes’ principle has many applications. It is used in designing ships and submarines. Lactometers, which are used to determine the purity of a sample of milk, and hydrometers used for determining the density of liquids, are based on this principle.
Question 5
1 / -0

A body is at rest on the surface of earth. Which of the following statements is correct?

A
Only weight of the body acts on it.

B
Only upward force acts on the body

C
Frictional force acts on the body

D
Net upward force is equal to the net downward force

Solution
Question 6
1 / -0

Does force of gravity act on dust particles?

A
Yes

B
No

C
May be

D
None of the above

Solution

Yes.
Dust has mass. All mass experiences gravitational attraction. Dust is carried by air currents but eventually settles.
Question 7
1 / -0

The weight of any person on the moon is about $$\dfrac{1}{6}$$ times that on the earth. He can lift a mass of $$15 kg$$ on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

A
2.5 kg

B
90 kg

C
15 kg

D
0 kg

Solution

Given that mass $$= 15\ kg$$ and weight experienced by the person is directly proportional to gravitation acceleration $$g$$ and $$m$$.
$$\dfrac{W_2}{W_1} \propto \dfrac {m_2 g_2} {m_1 g_1} $$
So, $$ {m_2 g_2} = {m_1 g_1} $$
or, $$m_2 \times \dfrac{g}{6} = 15 \times g$$
or, $$m_2 = 90\ kg $$
Question 8
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What will be the acceleration due to gravity on the surface of moon if its radius is $$\dfrac{1}{4}^{th}$$ the radius of the earth and its mass is $$\dfrac{1}{80}^{th}$$ the mass of earth?

A
$$\dfrac{g}{2}$$

B
$$\dfrac{g}{3}$$

C
$$\dfrac{g}{7}$$

D
$$\dfrac{g}{5}$$

Solution

We know, $$g = \dfrac{GM_e}{{R_e}^2}$$
and $$g' = \dfrac{GM_m}{{R_m}^2}$$
$$\therefore \dfrac{g'}{g} = \dfrac{M_m}{M_e}(\dfrac{R_e}{R_m})^2$$
$$ = \dfrac{1}{80}\times (\dfrac{4}{1})^2 = \dfrac{1}{5}$$
$$\Rightarrow g' = \dfrac{g}{5}$$
Question 9
1 / -0

For the moon, its mass is $$\dfrac{1}{81}$$ of earth's mass and its diameter is $$\dfrac{1}{3.7}$$ of earth's diameter.If acceleration due to gravity of earth surface is $$9.8 \ m/s^2$$, then at the moon its value is:

A
$$2.86\ m/s^2$$

B
$$1.65\ m/s^2$$

C
$$8.65\ m/s^2$$

D
$$5.16\ m/s^2$$

Solution

Acceleration due to gravity, $$g = \dfrac{GM}{R^2}$$

At Earth, $$g_e = \dfrac{GM_e}{R^2_e}$$,

and at Moon, $$g_m = \dfrac{GM_m}{R_m^2}$$

$$\therefore \dfrac{g_e}{g_m} = \dfrac{M_e}{M_m}(\dfrac{R_m}{R_e})^2$$

$$\Rightarrow g_m = g_e\times \dfrac{M_m}{M_e}\times (\dfrac{R_e}{R_m})^2$$

$$ = 9.8\times \dfrac{1}{81}\times 3.7\times 3.7$$

$$ = 1.65$$ $$m/s^2$$
Question 10
1 / -0

Experimental value of G is

A
$$6.67\times 10^{-11} Nm^2/kg^2$$

B
$$66.7\times 10^{-11} Nm^2/kg^2$$

C
$$667\times 10^{-11} Nm^2/kg^2$$

D
None of these

Solution

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Gravitation Test - 37

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Gravitation Test - 37

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Question 1

gravity

wind

clouds

earth's magnetic field

Solution

Question 2

mass of $$A$$

mass of $$B$$

distance between them

all of the above

Solution

Question 3

$$20\ kg$$

$$118\ kg$$

$$200\ kg$$

$$1180\ kg$$

Solution

Question 4

Only $$p,\ q$$ and $$r$$

Only $$q,\ r$$ and $$s$$

Only $$r,\ s$$ and $$p$$

Only $$q,\ p$$ and $$s$$

Solution

Question 5

Only weight of the body acts on it.

Only upward force acts on the body

Frictional force acts on the body

Net upward force is equal to the net downward force

Solution

Question 6

Yes

No

May be

None of the above

Solution

Question 7

2.5 kg

90 kg

15 kg

0 kg

Solution

Question 8

$$\dfrac{g}{2}$$

$$\dfrac{g}{3}$$

$$\dfrac{g}{7}$$

$$\dfrac{g}{5}$$

Solution

Question 9

$$2.86\ m/s^2$$

$$1.65\ m/s^2$$

$$8.65\ m/s^2$$

$$5.16\ m/s^2$$

Solution

Question 10

$$6.67\times 10^{-11} Nm^2/kg^2$$

$$66.7\times 10^{-11} Nm^2/kg^2$$

$$667\times 10^{-11} Nm^2/kg^2$$

None of these

Solution

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