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Gravitation Test - 42

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Gravitation Test - 42
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  • Question 1
    1 / -0
    Relation between buoyant force and the volume of an object immersed in liquid is:
    Given,
    $$\rho_{liq}$$ = Density of liquid 
    $$\rho_{obj}$$ = Density of object
    $$V_{total}$$ = Total volume of object
    $$V_{sub}$$ = Submerged volume of the object

    Solution
    The upward force applied by the fluid on the object when it is submerged in a fluid is known as the Buoyant force. According to the Archimedes' principle, the upward buoyant force is equal to the weight of the fluid that the body displaces .

    Hence, $$F_B = \rho_{liq}V_{sub}g$$

  • Question 2
    1 / -0
    What is the relationship between buoyant force and the weight of liquid displaced?
    Solution
    When a body is partly or completely immersed in water (or any other liquid), then according to archimedes principle.
    Loss in weight of body = Weight of water (liquid) displaced by the body = Buoyant force or upthrust exerted by water (any liquid) on the body.
    Hence, the relationship between buoyant force and the weight of liquid displaced is that they are equal.
  • Question 3
    1 / -0
    If relative density of a substance in $$0.8$$, is it heavier or lighter than water?
    Solution

    The relative density of a substance is a characteristic property of the substance that remains the same under specific conditions. The relative density of water is 1. If a substance has a relative density that is greater than 1, it will sink in water and if its relative density is less than 1, it will float in water.
    In this case, the relative density of a substance is 0.8. Hence, the substance float in water.
  • Question 4
    1 / -0

    Directions For Questions

    The diagram shows an iceberg. Answer the questions relating to it.

    ...view full instructions

    How much of the iceberg has a weight equal to the buoyant force? 

    Solution
    According to Archimedes principle an object immersed in a liquid experience an upward force called buoyant force ,which is equal to the weight of fluid displaced. 
    And if this upward force is equal to weight of object then object keep floating , it do not sink because weight has been cancelled by buoyant force.
    Since the iceberg is shown as floating it means all of it's weight has been canceled by the buoyant force.
    So weight of whole iceberg is equal to buoyant force. 
  • Question 5
    1 / -0
    An apple falls from a tree because of gravitation between the earth and apple. If $$F_1$$ is the magnitude of force exerted by the earth on the apple and $$F_2$$ is the magnitude of force exerted by apple on earth, then
    Solution
    From Newton’s third law of motion: Every action has equal and opposite reaction. Thus, F1 =F2 where, F1 is the magnitude of force exerted by the earth on the apple and F2 is the magnitude of force exerted by apple on earth.
  • Question 6
    1 / -0
    A planet whose mass and radius are both half of that of earth. Acceleration due to gravity(g) at its surface should be:
    Solution
    Acceleration due to gravity on earth,$$g=\dfrac{GM}{R^2}$$
    Acceleration due to gravity on planet,$$g'=\dfrac{G(\dfrac{M}{2})}{(\dfrac{R}{2})^2}=2\dfrac{GM}{R^2}=2g=19.6m/sec^2$$
  • Question 7
    1 / -0
    Two thin circular discs of radii $$3 cm$$ and $$4 cm$$ respectively are placed separately at the bottom of a vessel containing water. The ratio of thrusts, acting on them will be:
    Solution
    Answer is D.

    The thrust acting on the cirular disc is dependent on the area covered by the circular disc and the density of the fluid.
    In this case, the radii of the two circular discs are given as 3 cm and 4 cm and density of the liquid remains the same.
    The area covered is given by $$\pi { r }^{ 2 }$$.
    So, the ratio of their thrust will be given as:  $${ 3 }^{ 2 }:{ 4 }^{ 2 }= 9:16$$
  • Question 8
    1 / -0
    Pick up the correct relationship
    Solution
    Gravitational force between two masses is given by
    $$F=\dfrac{GMm}{d^2}$$
    Where $$M$$ $$m$$ are both masses respectively and $$d$$ is the distance between them.
    Thus,$$G= \dfrac{Fd^2}{Mm}$$
  • Question 9
    1 / -0
    Which of the following statements about weight is/are false ?
    $$1$$. Weight does not change when location changes.
    $$2$$. Weight is a force.
    $$3$$. Weight is measured in kilograms.
    $$4$$. Weight is proportional to the amount of gravity acting on an object.
    Solution
    Answer is B.
    1. Only the mass of an object doesn't change when an object's location changes. Weight, on the other hand does change with location as it the measurement of the pull of gravity on an object.
    2. The unit of measurement for weight is that of force, which in the International System of Units (S.I.) is the newton.

    Hence, the statements 1 and 3 are false.

  • Question 10
    1 / -0
    Any solid will not sink in water if its relative density is
    Solution
    If the reference material is water, then a substance with a relative density (or specific gravity) less than $$1$$ will float in water. For example, an ice cube, with a relative density of about $$0.91$$, will float. A substance with a relative density greater than $$1$$ will sink.
    $$\text{specific gravity} = \dfrac{\text{density of the substance}}{\text{density of the water}}$$
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