Gravitation Test

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Gravitation Test - 44

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Question 1
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Relation between mass of body and its weight is:

A
$$w = mg$$

B
$$\displaystyle w=\frac{m}{g}$$

C
$$g = m - w$$

D
$$w = m + g$$

Solution

Weight $$w$$is the measure of the force of gravity on an object's mass.
While, mass $$m$$ is the measure of how much matter is present in the object.
Weight is given by $$w=mg$$
where, g= acceleration due to gravity.
Question 2
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The force that is primarily responsible for the existence of the solar system is the

A
force of friction

B
gravitational force

C
electrostatic force

D
magnetic force

Solution

The solar system consists of the sun, some planets, their satellites, and some other heavenly objects. All these objects are revolving in their own orbits. This revolution and hence the stability of the solar system is primarily due to the gravitational force between these heavenly bodies.
Question 3
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Weight can be :

A
measured by a spring balance

B
measured by a beam balance

C
measured in kg

D
a scalar quantity

Solution

A beam balance measures the $$mass$$ of a body. $$Mass$$ is measured in kg.
A spring balance is used to measure the $$weight$$ of a body. Weight s a vector.
Question 4
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The SI unit of G is.

A
$$N^2m^2/kg$$

B
$$Nm^2/kg$$

C
$$N \ ml \ kg$$

D
$$Nm^2/kg^2$$

Solution

$$\textbf{Correct option: Option (D).}$$

$$\textbf{Explanation:}$$

$$\bullet$$Gravitational force is the universal force of attraction experienced by all matters.

$$\bullet$$It is given by, $$F=\dfrac{GMm}{{{R}^{2}}}$$ (Where G is the universal gravitational constant whose value remains constant throughout the space, and M and m are the masses of the two objects and R be the distance between the bodies.)

Then, $$G=\dfrac{F{{R}^{2}}}{Mm}$$

For a force of 1 Newton between bodies of mass 1 kg and 1 meter apart, G will be
$$\bullet$$ S.I unit of G

$$\Rightarrow G=\dfrac{N\times {{m}^{2}}}{kg\times kg}$$

$$\Rightarrow G=N{{m}^{2}}/k{{g}^{2}}$$
$$\textbf{Thus, option (D) is correct.}$$
Question 5
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A person stands on a weighing machine kept on the floor of an elevator, if the elevator moves upward with a constant acceleration, the apparent weight of the person

A
is less than their true weight

B
is equal to their true weight

C
is more than their true weight

D
can be more or less than their true weight

Solution

When a person stand on an elevator moving upwards with acceleration $$a$$, he will experience a downward gravitational force equal to $$mg$$ and a downward pseudo force equal to $$ma$$.

We know that a weighing machine measures the net downward force
$$\Rightarrow F_{net downwards} =mg+ma$$

This means the net downward force exerted by the person on the weighing machine will increase by an amount $$ma$$ and the apparent weight of the person will become more than his true weight

Hence correct answer is option $$C $$
Question 6
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If the distance between two masses be doubled, then the force between them will become

A
$$\dfrac{1}{4}$$ times

B
4 times

C
$$\dfrac{1}{2}$$ times

D
2 times

Solution

Gravitational force between two bodies$$F=\frac{Gm_1m_2}{r^2}$$
so gravitational force between two bodies $$F\propto \dfrac{1}{r^2}$$.
Hence $$r$$ is doubled so $$F$$ become $$1/4$$ times
Question 7
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A typical weighing machine measures __________ of an object.

A
Only the weight

B
Only the mass

C
Both mass and weight

D
None of these

Solution

A typical weighing machine only measures weight of an object.
$$\text{weight} = mg$$
$$m$$; mass of the object
$$g$$; acceleration due to gravity
Question 8
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An object has a mass $$m$$ kg on earth. What will be its mass on the moon ?

A
$$m$$ kg

B
$$6m$$ kg

C
$$\dfrac {m}{6}$$ kg

D
$$zero$$

Solution

Mass is a messure of quantity of matters so it is constant for any object anywhere in the universe. Whereas Weight depends on gravitational pull so it varies accordingly.
Hence mass of an object on eath and on moon will be same but Weight will be different
Option A
Question 9
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Choose the correct statement.

A
weight is a vector quantity

B
the weight of a body in interplanetary space is maximum

C
weight increases with height from the earth surface

D
$$1 N = 1 kg \times 1m/s$$

Solution

Weight is nothing but the force of attraction exerted by the earth on a body. Now as we know that the force is a vector quantity and so does the weight as weight has both magnitude and direction towards the centre of the earth.

So statement A is correct

Statement B is incorrect because value of g in interplanetary space is less than that at the surface of the earth

Statement C is incorrect as the value of g decreases with the height and so does the weight.

Statement D is incorrect as $$1N=1kg\times 1m/s^2$$

Hence correct answer is option $$A $$
Question 10
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A body has a mass M kg on the earth. What will be its weight on the earth?

A
Mg newton

B
$$\left ( \dfrac{M}{8} \right ) $$newton

C
M newton

D
zero

Solution

Weight is nothing but the gravitational force on an object which is caused by some celestial body. Heavier the celestial body more the gravitational force applied by it. So a body that has a mass of M kg on the earth will weigh Mg newton on earth, as g is the acceleration due to gravity on earth.

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Re-Attempt Weekly Quiz Competition

Gravitation Test - 44

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Gravitation Test - 44

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SHARING IS CARING

Question 1

$$w = mg$$

$$\displaystyle w=\frac{m}{g}$$

$$g = m - w$$

$$w = m + g$$

Solution

Question 2

force of friction

gravitational force

electrostatic force

magnetic force

Solution

Question 3

measured by a spring balance

measured by a beam balance

measured in kg

a scalar quantity

Solution

Question 4

$$N^2m^2/kg$$

$$Nm^2/kg$$

$$N \ ml \ kg$$

$$Nm^2/kg^2$$

Solution

Question 5

is less than their true weight

is equal to their true weight

is more than their true weight

can be more or less than their true weight

Solution

Question 6

$$\dfrac{1}{4}$$ times

4 times

$$\dfrac{1}{2}$$ times

2 times

Solution

Question 7

Only the weight

Only the mass

Both mass and weight

None of these

Solution

Question 8

$$m$$ kg

$$6m$$ kg

$$\dfrac {m}{6}$$ kg

$$zero$$

Solution

Question 9

weight is a vector quantity

the weight of a body in interplanetary space is maximum

weight increases with height from the earth surface

$$1 N = 1 kg \times 1m/s$$

Solution

Question 10

Mg newton

$$\left ( \dfrac{M}{8} \right ) $$newton

M newton

zero

Solution

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