Gravitation Test

Result

Gravitation Test - 62

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Weekly Quiz Competition

Question 1
1 / -0

A body, the mass and the weight of which were already determined at the Equator, is now placed at the Pole. In this context, choose the correct statement from the following:

A
Mass does not change, weight is maximum

B
Mass does not change, weight is minimum

C
Both mass and weight are maximum

D
Both mass and weight are minimum

Solution
Question 2
1 / -0

If the masses of two bodies are doubled and the distance between them is halved, then the new gravitational force between them is how many times the original?

A
$$2$$

B
$$8$$

C
$$16$$

D
$$1$$

Solution
Question 3
1 / -0

A student is sitting on a chair as shown in figure.
Which statement is correct for the mass of the chair on the Moon and the mass of the chair on the earth ?
Tick the correct statement.

A
The mass of the chair is greater on the moon.

B
The mass of the chair is less on the Moon but not zero.

C
The mass of the chair is the same on the moon.

D
The mass of the chair is zero on the Moon.

Solution

Mass is a measure of quantity of matters, which does not depend on the gravitational force of attraction. Hence the mass of the given chair will be same on earth and moon.
Option D.
Question 4
1 / -0

An oil layer which is 9 cm deep lies above a depth of water. A uniform cylinder of wood of length 25 cm is floating vertically upright in the two liquids as shown in the diagram. If 5 cm of the wooden cylinder lies above the oil surface, what is the density of the wood?
(The density of the oil is 0.9 g $$cm^{-3}$$ and density of water is 1.0 g $$cm^{-3}$$.)

A
$$0.76 g cm^{-3}$$

B
$$0.66 g cm^{-3}$$

C
$$0.80 g cm^{-3}$$

D
$$0.70 g cm^{-3}$$
Question 5
1 / -0

The ratio of SI units to CGS units of g is.

A
$$10^2$$

B
10

C
$$10^{-1}$$

D
$$10^{-2}$$

Solution
Question 6
1 / -0

If the gravitational mass of body on the moon be denoted by $$M_m$$ and that on the earth be $$M_e$$, then.

A
$$M_m=\frac {1}{6}$$

B
$$M_m=M_e$$

C
$$M_m=\sqrt {M_e}$$

D
$$M_m=6M_e$$

Solution

Mass of an object is constant because it is the amount of matter present in the object which is fixed and never change.
Hence mass on earth $$M_e$$ and mass on moon $$M_m$$ will be equal.
$$M_m=M_e$$
Question 7
1 / -0

If a rock is brought from the surface of the moon.

A
its mass will change

B
its weight will change but not mass

C
both mass and weight will change

D
its mass and weight both will remain same
Question 8
1 / -0

Astronomers have discovered a planet orbiting a nearby star. It is estimated that the mass of this planet is 16 times that of our earth and its density is one-fourth of the earth's density. Assume that planets are spheres of uniform density. If your weight on the earth is 1000 N, then your weight on this planet would be

A
5000 N

B
1000 N

C
2000 N

D
4000 N
Question 9
1 / -0

When an object is thrown up, the force of gravity.

A
Acts in the direction of the motion

B
Acts in the opposite direction ofthe motion

C
Remains constant as the body moves up

D
Increases as the body moves up

Solution
Question 10
1 / -0

Formula for density and relative density/ specific gravity respectively are:

A
$$\rho= \dfrac{m}{v}$$, $$\sigma= \dfrac{\rho_{liq}}{\rho_{water}}$$

B
$$\rho= \dfrac{v}{m}$$, $$\sigma= \dfrac{\rho_{water}}{\rho_{liq}}$$

C
$$\rho= \dfrac{m}{v}$$, $$\sigma= \dfrac{\rho_{water}}{\rho_{liq}}$$

D
$$\rho= \dfrac{v}{m}$$, $$\sigma= \dfrac{\rho_{liq}}{\rho_{water}}$$

Solution

Formula of density-
$$\rho = \dfrac{m}{v}$$
$$\rho$$; density
$$m$$; mass of the object
$$v$$; volume of the object

Formula of relative density-
$$\sigma = \dfrac{\text{density of unknown object}}{\text{density of water}}$$