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Work and Energy Test - 24

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Work and Energy Test - 24
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  • Question 1
    1 / -0
    One megawatt is .................... times that of one kilowatt.
    Solution
    One megawatt  $$ = 10^6 $$ Watt
    One Kilowatt $$ = 10^3$$ Watt
    $$\implies \ $$ one megawatt $$ = 1000 $$ kilowatt
  • Question 2
    1 / -0
    If force and displacement of the particle (in direction of force) are doubled, Work should be :
    Solution
    Work done is defined as $$W=Fs$$
    where $$F$$ is the force applied and $$s$$ is the displacement in the direction of force.

    Hence initially work done $$W_1 = Fs$$

    Now, When $$F_2=2F$$ and $$s_2=2s$$

    Then, work done $$W_2=F_2s_2$$

    $$\Rightarrow W_2=(2F)(2s)$$
    $$\Rightarrow W_2 = 4W_1$$

    Hence, work done is quadrupled.
  • Question 3
    1 / -0
    When a force retards the motion of a body, the work done is :
    Solution
    When the force retards the motion of a body, the work done is negative.
  • Question 4
    1 / -0
    The work done in holding $$15\ kg$$ suitcase while waiting for a bus for $$45$$ minutes is :
    Solution
    Work done = force $$\times$$ displacement in force direction
    Work done in holding a suitcase while waiting for a bus i.e. stationary position. 
    So, displacement will be zero.
    Work done = force $$\times$$ zero
    Work done = zero
  • Question 5
    1 / -0
    Choose the correct option.
    Solution
    Electrical Power is measured in watts ($$W$$), kilo-watts ($$kW$$), mega-watts ($$MW$$), and giga-watts ($$GW$$). 

    Electrical Energy is measured in kilowatt-hours ($$kWh$$), megawatt-hours, and sometimes (less commonly) in watt-hours or watt-seconds.  
  • Question 6
    1 / -0
    How much work is done by a force 50 N moving an object through a distance 10 m in the direction of force ?
    Solution
    $$F=50N$$
    $$s=10m$$
    Work done, $$W=F\times s=50\times 10=500J$$
  • Question 7
    1 / -0
    What will be the potential energy of a body of mass 5 kg kept at a height of 10 m ?
    Solution
    Answer is C.

    Potential energy is energy stored in an object. This energy has the potential to do work. Gravity gives potential energy to an object. This potential energy is a result of gravity pulling downwards. The gravitational constant, g, is the acceleration of an object due to gravity. This acceleration is about 10 meters per second on earth. The formula for potential energy due to gravity is PE = mgh. As the object gets closer to the ground, its potential energy decreases while its kinetic energy increases. 
    In this case, a body of mass 5 kg kept at a height of 10 m. So the potential energy is given as 5 * 10 *10 = 500 J.
    Hence, the potential energy of a body of mass 5 kg kept at a height of 10 m is 500 J.
  • Question 8
    1 / -0
    The work done by a force on a body will be positive if the body -
    Solution
    Work done is positive when the force is in the direction of displacement.
    $$\text{work} = \text{Force} \times \text{displacement in the direction of force}$$
  • Question 9
    1 / -0
    An electric toaster draws $$8\ A$$ current in a $$220\ V$$ circuit. It is used for $$2\ hr$$. What is the cost of operating the toaster if the cost of electrical energy is $$Rs.\ 4.5 / kWh$$?
    Solution
    Given,
    $$i=8\ A\\E=220\ v\\t=2\ hr$$

    Energy dissipated is given by:
    $$E = E\ i\ t$$
       $$=220 \times 8 \times 2\ Wh$$ 
       $$=3.52\ kWh$$

    The cost per kWh is $$Rs.\ 4.50$$
    Hence,  the cost of running the kettle for two hours is:
    $$3.52 \times 4.50 = Rs.\ 15.84$$
  • Question 10
    1 / -0
    In our household applications, commercial unit of electricity is used. One unit is equal to:
    Solution
    Electrical Energy is measured in kilowatt-hours (kWh). A unit is the primary measurement used by the utility company to determine your bill each month (although demand and power factor are also sometimes used). Unlike power, energy does not change quickly, but instead accumulates gradually.
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