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Work and Energy Test - 30

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Work and Energy Test - 30
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  • Question 1
    1 / -0
    A rigid body of mass $$m$$ kg is lifted uniformly by a man to a height of one metre in $$30$$ sec. Another man lifts the same mass to the same height in $$60$$ sec. The work done on the body against gravitation in both the cases are in ratio:
    Solution
    $$W=F. S$$
    As work done is independent of time. So, both the man  does same work.
    Hence, the work done on the body against gravitation are in ratio $$1:1$$.
  • Question 2
    1 / -0
    What is work done in holding a body of mass $$20\ kg$$ at a height of $$2\ m$$ above the ground? $$(g = 10\ m/s^2)$$
    Solution
    A body of mass $$20\ kg$$ is held at a height of $$2\ m$$ above the ground means there is no displacement because of which there is no change in its potential energy. Hence work done is zero.
  • Question 3
    1 / -0
    The law of conservation of energy implies that the:
    Solution
    Law of conservation of energy implies that energy can neither be created nor destroyed, but can merely be transfered from one form to other. These forms are varied. Thus, when considering all forms of energy,(including workdone) the total sum never changes.
  • Question 4
    1 / -0
    In which one of the following cases is work done the maximum ?
    Solution
    Work done is defined as  $$W = Fs\cos\theta$$, where $$F$$ is the force applied, $$s$$ is the displacement and $$\theta$$ is the angle between force applied and displacement.

    In cases A, C and D there is no displacement($$s$$) taking place.
    So, $$W=Fs\cos\theta=0$$ (as $$s=0$$)

    In case B: $$s=1.5m$$ so, Mohan does some work.

    Hence, work done in case B is maximum.
    So, option B is correct.
  • Question 5
    1 / -0
    How fast should a girl of 40 kg run so that her kinetic energy is 320J?
    Solution
    Given, mass $$m=40kg , K.E=320J , v=?$$
    $$K.E=\dfrac{1}{2}mv^2$$

    $$320=\dfrac{1}{2}\times 40v^2$$

    $$v^2=\dfrac{640}{40}=16$$

    $$v=4m/s$$
    So, the girl of $$40$$ $$kg$$ should run at $$4m/s$$ so that her kinetic energy is $$320J.$$
  • Question 6
    1 / -0
    A vehicle travelling at $$30 \ m/s$$ stops at a distance of $$50 \ m$$ decelerating uniformly. A force of $$9000 \ N$$ is exerted on it by the brakes. What is the work done by the brakes?
    Solution
    The work done by the brakes is calculated using the relation ,
     $$W=F \times s $$,
    where $$F$$ is the force applied and $$s$$ is the displacement in the direction of force. 

    Hence,  $$W=9000 \times 50=4.5\times 10^5 \ N$$
  • Question 7
    1 / -0
    Work done by static friction force when a person starts running is .......... .
    Solution
    Static friction is the friction force which does not allow the object to move but here the person is running which means that static friction becomes zero. Hence the work done by the static frictional force is also zero.
  • Question 8
    1 / -0
    Which one of the following possesses kinetic energy?
    Solution
    Any moving object must have kinetic energy because of its velocity. So, a moving car possesses kinetic energy.
  • Question 9
    1 / -0
    Energy conservation law says that:
    Solution
    In physics, the law of conservation of energy states that the total energy of an isolated system remains constant—it is said to be conserved over time. Energy can neither be created nor destroyed; rather, it transforms from one form to another.
  • Question 10
    1 / -0
    A body at rest have:
    Solution

    $$\textbf{Step 1-Momentum of body}$$

    Here, body is at rest. So, it is not in motion means its speed and velocity both will be zero. Similarly, momentum is product of mass and velocity, so its value will be also zero.

    $$\textbf{Step 2-Energies of body}$$

    Kinetic energy of body which depends on velocity is also zero but it will have some potential energy which is given by the formula,

    $$U = m\ g\ h$$, where, m is mass, h is the height of body and g is the acceleration due to gravity.

    So, its potential energy will not be zero.

    And total energy is sum of both kinetic energy and potential energy. Which will be also non-zero.

    So, a body at rest will have some energy.


    Hence, option A is the correct answer.

     

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