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Work and Energy Test - 34

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Work and Energy Test - 34
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  • Question 1
    1 / -0
    The number of joules contained in $$1  kWh$$ is
    Solution
    1 KWh =  1000 $$\ast$$ joule/sec $$\ast$$ 60 $$\ast$$ 60 sec

    1KWh = 1000 $$\ast$$ 60 $$\ast$$ 60joue/sec $$\ast$$ sec

    1KWh = 1000 $$\ast$$  60 $$\ast$$ 60 joule

    1KWh = 36,00,000 joule = 3.6 $$\ast$$ 10$$^{6}$$
  • Question 2
    1 / -0
    A body at rest can have:
    Solution

  • Question 3
    1 / -0
    A raised hammer possesses :
    Solution
    A raised hammer possesses P.E
    Energy possessed by a body by virtue of its position is called as potential energy.  Similarly is the case when a hammer is raised. A raised hammer possesses potential energy by virtue of its height above ground level.


  • Question 4
    1 / -0
    An object of mass $$1  kg$$ has a P.E. of $$1  J$$ relative to the ground when it is at a height of
    Solution
    $$P.E$$ is given by $$=mgh$$
    where $$h$$ is the height, $$m$$ is mass and $$g$$ is acceleration due to gravity
    $$1J=1\times 10\times h\\ \\ $$
    $$h=0.1m$$

  • Question 5
    1 / -0
    1 $$hp$$ is equal to:
    Solution
    The horsepower (hp) is a unit in the foot-pound-second ( fps ) or English system, sometimes used to express the rate at which mechanical energy is expended.A power level of 1 hp is approximately equivalent to $$746$$ $$watt(W)$$ or $$0.746$$ $$kilowatt(kW)$$.
  • Question 6
    1 / -0
    Mechanical work done is equal to (symbol have their usual meanings)
    Solution
    Work done is defined as product of the force and the distance over which the force is applied.

  • Question 7
    1 / -0
    The mass of an object $$P$$ is double the mass of $$Q$$. If both move with the same velocity, then the ratio of K.E. of $$P$$ to $$Q$$ is
    Solution
    $$ M_P =2 \times M_Q$$
    $$ V_P = V_Q $$

    $$ K.E_P: K.E_Q = ?$$

    $$\implies  \dfrac{1}{2}M_PV_P^2 : \dfrac{1}{2}M_QV_Q^2 $$
    Since $$V_P$$ =$$V_Q$$
    $$\implies M_P : M_Q $$
    $$\implies 2 \times M_Q : M_Q $$
    $$\implies 2 : 1 $$
  • Question 8
    1 / -0
    Work done upon a body is
    Solution
    Work done due to displacement caused by a force is a scalar quantity, since it has only magnitude and no direction.
  • Question 9
    1 / -0
    A person walks $$100$$ m, holding a suitcase of weight $$100$$ N. The work done by the applied force is ____ J. 
    Solution
    In the given scenario, Direction of force on the suitcase is vertically upward and this force will make $$90^\circ $$ angle with displacement vector.
    So there is no motion in the direction of force applied. So work done by girl on the suitcase will be zero.
    Option C

  • Question 10
    1 / -0
    The product of force and displacement equals:
    Solution
    Work is defined as the dot product of force and displacememt.(F.S)
    Power is defined as work done per unit time.(j/s)
    Momentum is defined as mass into velocity(mv).
    So best possible answer is option A.
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