Self Studies

Work and Energy Test - 49

Result Self Studies

Work and Energy Test - 49
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Directions For Questions

    A body of mass $$2\ kg$$ starts from rest and moves with uniform acceleration. It acquires a velocity $$20\ ms^{-1}$$ in $$4\ s$$

    ...view full instructions

    The power exerted on the body at $$2\ s$$ is:
  • Question 2
    1 / -0
    A man of mass 20 kg is running in a straight line with velocity 10 m/s. What is value of his kinetic energy?
    Solution
    The kinetic energy of the particle is given as-
    $$K.E. = \dfrac{1}{2}mv^2$$
    $$m$$; mass of the object
    $$v$$; speed of the object
    $$\Rightarrow K.E. = \dfrac{1}{2} \times 20 \times 10^2J$$
    $$\Rightarrow K.E. = 1000 J$$
  • Question 3
    1 / -0
    Two bodies traveling with velocity $$20ms^{-1}$$ and $$40ms^{-1}$$ have same K.E. If the mass of the body having velocity $$40ms^{-1}$$ is 8 kg the mass of other body is 
    Solution
    Given
    $$ V_1 = 20 m/s$$  and  $$ V_2 = 40 m/s$$
    $$ M_2 = 8\ kg $$

    $$K.E_1 = K.E_2$$
    $$\dfrac{1}{2}M_1V_1^2 = \dfrac{1}{2}M_2V_2^2 $$
    $$\implies M_1 = M_2 \times \dfrac{V_2^2}{V_1^2} = 8\times \dfrac{40^2}{20^2} = 32\ kg$$
  • Question 4
    1 / -0
    Two men $$A$$ and $$B$$ each weighing $$80\ kg$$, run up the same stair case. While $$A$$ does it in $$20\ s, B$$ does it in $$15\ s$$. The ratio of the powers developed by $$A$$ and $$B$$ is
    Solution
    We know $$Power=\dfrac{work }{time}$$
    work done by both the men is the same = Gain in potential energy = $$m\times g\times h $$ 
    $$m,g,h$$are same for both so work same for both. 
    So $$P \propto \dfrac{1}{t}$$
    Therefore $$\dfrac{P_{a}}{P_{b}}=\dfrac{t_{b}}{t_{a}} \implies\dfrac{P_{a}}{P_{b}}=\dfrac{15}{20}$$=$$\dfrac{3}{4}$$
    Hence Option B is correct
  • Question 5
    1 / -0
    How much height must an object of mass $$5kg$$ be lifted to have potential energy $$5000J$$ ?$$[g=10 m/s^2]$$
    Solution
    Gravitation potential energy is given by $$P.E = mgh $$
    Given:
    Mass $$m=5 \ kg$$
    $$g=10 \ m/s^2$$
    $$5000 = 5 \times 10 \times h $$
    $$ \implies h = 100 m$$ 
  • Question 6
    1 / -0
    A car is accelerated on a levelled road and attains a speed of $$5$$ times its initial speed. In this process , the kinetic energy of the car:
    Solution

    Lets initial velocity of car is $$v$$, final velocity of this car will be $$5\ v$$

    $$K.E  = \dfrac{1}{2}$$ $$ mv ^{2}$$

    $$\therefore \ K.E\propto v^2$$

    $$K.E_{f}=K.E_i \left(\dfrac{v_f}{v_i}\right)^2$$   where   $$f$$ stand for final and $$i$$ for initial.

    $$K.E_{f}=K.E_i \left(\dfrac{5v}{v}\right)^2=25\ K.E_i$$

    So, when the speed increases to 5 times of its initial velocity, the kinetic energy will become 25 times.

    The correct answer is d) becomes $$25$$ times that of initial kinetic energy
  • Question 7
    1 / -0
    A stone is thrown upwards as shown in the diagram. When it reaches $$P,$$ which of the following has the greatest value for the stone?

    Solution
    P is the highest point of the ball during its motion. At this point, its speed will be zero. This makes the kinetic energy to be zero. The acceleration remains constant all through the motion and the weight depends on the value of acceleration due to gravity. So weight will also be constant.

    So, the correct answer is c) its potential energy.
  • Question 8
    1 / -0
    No work is done when:
    Solution
    The formula for work done when the force is applied at an angle to the direction of motion is given by,
    $$W = FS \,cos \theta$$
    When there will be no component of force, parallel to the direction of motion then force F in direction of motion is zero, so work done will also be zero.
  • Question 9
    1 / -0
    Potential energy of a person is minimum when:
    Solution
    Potential energy of a body is defined as energy of a body due to its position in gravitational field. 
    In general,  
    Potential energy $$= M \times g \times h$$         where: h is the height above ground.
    If the person will be lying on ground then it will have minimum height above the ground therefore potential energy of the person will also be minimum.
  • Question 10
    1 / -0
    When a stone of mass 'm' falls through a vertical height 'd', the decrease in the gravitational energy is:
    Solution
    Potential energy stored in a body of mass m and at height 'd' will be given by $$m \times g \times d$$
    This gravitational potential energy keeps on decreasing with the decrease in height of stone, and when the stone falls completely, this potential energy is lost . So when object loses height $$d $$ the corresponding loss in potential Energy is $$= mgd$$
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Selfstudy
Selfstudy
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now