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Work and Energy Test - 51

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Work and Energy Test - 51
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  • Question 1
    1 / -0
    A force applied by an engine of a train of mass $$ 2.05 \times 10^6  \ kg $$  changes it velocity from $$ 5 \ m /s $$ to $$ 25\ m/s $$  in $$ 5\ minutes$$. The power of engine is 
    Solution
    Given,
    Mass of train $$=2.05\times 10^6\ kg$$
    Initial velocity $$u=5\ m/s$$
    Final velocity $$v=25\ m/s$$
    Time required $$t=5\ mint= 5\times 60\ s=300\ s$$
    From conservation of energy,
                        Work done by engine $$=$$ change in kinetic energy of the train
                             $$W=K.E_f-K.E_i$$
    $$Power$$ = $$ \dfrac {work\ done}{time} = \dfrac  {\dfrac {1}{2} m(v^2 -u^2) }{t} $$

    $$ P = \dfrac {1}{2} \times  \dfrac { 2.05 \times 10^6 \times [ (25)^2 -(5^2) ]}{ 5 \times 60 } $$

    $$ P = 2.05 \times 10^6 W = 2.05 MW $$
  • Question 2
    1 / -0
    A car of mass 1000 kg accelerates uniformly from rest to a velocity  of 54 km/hour in 5s. The average power of the engine during this period in watts is (neglect friction)
    Solution
    Power $$ = \dfrac  {Work done}{time} = \dfrac { Increase\ in\ K.E.}{time} $$

    $$ P = \dfrac { \frac {1}{2} mv^2}{t} = \dfrac {\frac {1}{2} \times 10^3 \times (15)^2}{5} = 22500 W $$ 
  • Question 3
    1 / -0
    An electric lamp is marked $$60 \ W$$, $$230 \ V$$. The cost of $$1 \ kilowatt-hour$$ of power is $$Rs \ 1.25$$. The cost of using this lamp for $$8 \ hours$$ is
    Solution
    Total energy consumed is given as $$E=P\times t$$
    where $$P$$ is power and $$t$$ is time for which it is used. 
    Given, $$P=60\,W$$ and $$t=8\,h$$ 
     $$E = 60 \times 8 \ Wh=\dfrac{60\times 8}{1000} = 0.48 \ kWh $$

    Given that, cost of $$1 \ kWh$$ is $$Rs. \ 1.25$$

    Hence, total cost is $$ \text{Cost}=0.48\times 1.25 = Rs. \ 0.6 $$
  • Question 4
    1 / -0
    The power of pump, which can pump $$200 \ kg$$ of water to a height of $$50 \ m$$ in $$10 \ sec$$, will be
    Solution
    $$ Power \ P = \dfrac {Work \ done}{time} = \dfrac { mgh}{t} = \dfrac { 200 \times 10 \times 50}{10} = 10 \times 10^3 W $$
  • Question 5
    1 / -0
    The spring will have maximum potential energy when 
    Solution
    The spring will have maximum potential energy when it is pulled out or compressed in.
  • Question 6
    1 / -0
    Kilowatt hour is unit of
    Solution
    The kilowatt-hour (symbolized kWh) is a unit of energy equivalent to one kilowatt (1 kW) of power expended for one hour. The kilowatt-hour is commercially used as a billing unit for energy delivered to consumers by electric utilities.
  • Question 7
    1 / -0
    When spring is compressed its potential energy........
    Solution
    When a spring is compressed or stretched, potential energy energy of the spring increases in both the cases. This is because work is done by us in compression as well as stretching.
  • Question 8
    1 / -0
    Masses of two bodies are $$1$$ kg and $$4$$ kg respectively. If their kinetic energies are in $$2:1$$ proportion, the ratio of their speeds is .........
    Solution
    We know that,
    $$K.E.=\dfrac{1}{2}mv^2$$
    $$m_1=1kg$$     $$m_2=4kg$$

    $$\therefore \dfrac{K_1}{K_2}=\Bigg(\dfrac{m_1}{m_2}\Bigg)\Bigg(\dfrac{v_1}{v_2}\Bigg)^2$$

    $$\Rightarrow \dfrac{2}{1}=\Bigg(\dfrac{1}{4}\Bigg)\Bigg(\dfrac{v_1}{v_2}\Bigg)^2$$

    $$\Rightarrow \Bigg(\dfrac{v_1}{v_2}\Bigg)^2=\dfrac{8}{1}$$

    $$\Rightarrow \Bigg(\dfrac{v_1}{v_2}\Bigg)=\dfrac{2\sqrt{2}}{1}$$
  • Question 9
    1 / -0
    Some children were trying to find out which of three bulbs was brightest. Which one of these gives the best start toward finding the answer?
    Solution
    Brightness of a ball can be measured and so in turn which can be used to Judge which bulb will light the brightest. 
  • Question 10
    1 / -0
    Calculate the energy possessed by a stone of mass $$10\ kg$$ kept at a height of $$5\ m$$. 
    Take $$g = 9.8\ m/s^{2}$$
    Solution
    The energy that stone may posses = kinetic energy + potential energy 
    Since, stone at rest $$(v = 0)$$ 
    $$KE=\frac{mv^2}{2}$$ So kinetic energy=0 
    $$ \therefore $$ Total energy = Potential energy 
    $$(E) = mgh $$    [$$m$$ : mass , $$h$$ : height , $$g$$ : gravity ] 

    $$m = 10\ kg, g = 9.8\ m/s^{2} $$ 
    and $$h = 5\ m $$ 
    $$E = mgh = 10 \times 9.8 \times 5 $$ Joules 
                      $$ = 490\ J $$ 
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