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Sound Test - 18

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Sound Test - 18
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  • Question 1
    1 / -0
    Sound travels in air if
    Solution
    Sound is a mechanical wave that results from the back and forth vibration of the particles of the medium through which the sound wave is moving. If a sound wave is moving from left to right through air, then particles of air will be displaced both rightward and leftward as the energy of the sound wave passes through it. The motion of the particles is parallel (and anti-parallel) to the direction of the energy transport. Here, the sound wave does not move the particles of the medium from one place to another but only the vibration or the disturbance moves.
  • Question 2
    1 / -0
    The properties of ultrasound that make it useful is/are 
    Solution
    Answer is B.
    The ultrasound waves have a shorter wavelength and thus don't spread out as rapidly. For this reason, the resulting directivity of the ultrasound devices is far higher than physically possible with any loudspeaker system.

    High power ultrasound carry large energy which can break up stony deposits or tissue, accelerate the effect of drugs in a targeted area, assist in the measurement of the elastic properties of tissue, and can be used to sort cells or small particles for research.

    Hence, high directivity and high power make ultrasound to be very useful.

  • Question 3
    1 / -0
    Infrasound can be heard by
    Solution
    Rhinos have extremely good ears, picking up infra-sound far deeper than the range of human hearing.
    Rhinos, can hear down to a frequency of four hertz, whereas even a human baby, with entirely undamaged ears, can normally only pick up sounds as low as 20 hertz. Giraffes and elephants can also hear in this infra-sound range.
  • Question 4
    1 / -0
    An object oscillates 50 times in one second. What would be its frequency?
    Solution
    Frequency is defined as the number of oscillations in one second , as the given object is oscillating , 50 times in one second therefore its frequency is 50 Hz .
  • Question 5
    1 / -0
    A source is producing 15 oscillations (waves) in 3 seconds. Find its frequency?
    Solution
    Frequency of a wave (as sound wave) is defined as the number of oscillations per second,
    $$f=\dfrac{\text{number of oscillations}}{\text{time (in seconds)}}$$
    Given: 
    No. of oscillations $$=15$$, $$time=3s$$
    $$\therefore f=\dfrac{15}{3}=5 \ Hz$$
    Option (B) is correct.
  • Question 6
    1 / -0
    Time taken to complete 6 successive compressions if the time between two successive compressions of a wave is 4 sec is :
    Solution
    The time period of a longitudinal wave is defined as the time between two successive compressions or rarefactions.
    As given the time between two successive compressions is 4s, 
    therefore time period of the wave will be $$T=4 \ s $$. 
    The time between 6 successive compressions will be equal to 5 time periods, 
    i.e. $$=5\times4=20s$$
  • Question 7
    1 / -0
    Which of the following parameters determines the loudness of sound ?
    Solution
    Loudness is the measure of the intensity of sound waves. The intensity of a sound wave is proportional to its amplitude ($$I\propto A^2$$). Hence the loudness of a sound depends on its amplitude.
  • Question 8
    1 / -0
    Fill in the blank.
    The time taken by ___ oscillation  to complete is called time period. 
    Solution
    Time period can be defined as time to complete one full oscillation. Hence A is the correct answer. 
  • Question 9
    1 / -0
    When a wave travels from the one medium to another, the quality which will not change is its
    Solution
    Frequency of a wave is characterised by the source of wave , therefore it does not change when wave travels from one medium to another .
  • Question 10
    1 / -0
    $$Hertz$$ stands for:
    Solution
    Hertz is the unit of frequency and frequency is defined as number of vibrations per second ,
            $$f=$$number of vibrations/ time (in second) ,

    Hence unit of frequency is,

    $$second^{-1}=Hertz$$ 
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