Sound Test

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Sound Test - 25

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Weekly Quiz Competition

Question 1
1 / -0

From the following, where is SONAR used?

A
To measure depth of sea bed

B
To locate scraps

C
To locate submarines

D
All of the above

Solution

SONAR can be used in
1. to measure depth of sea bed
2. to locate scraps
3. to locate submarine
Hence D is the correct answer.
Question 2
1 / -0

A hummingbird beats its wings $$ 3,300$$ times per minute. Find out the frequency produced by the bird?

A
$$0.003\ Hz$$

B
$$0.018\ Hz$$

C
$$6\ Hz$$

D
$$55\ Hz$$

E
$$3300\ Hz$$

Solution

Beat frequency is given by, number of beats per second,
in the given case ,
frequency-
$$ f = 3300\ \text{beats per minute}$$

$$\Rightarrow f = \dfrac{3300}{60}\ \text{beats per second}$$

$$\Rightarrow f = 55\ Hz$$
Question 3
1 / -0

Identify which of the following wave parameter is related to the volume of a sound?

A
amplitude

B
speed

C
wavelength

D
period

E
frequency

Solution

Intensity is perceived as the volume of a sound.
The amplitude of a wave is the measure of the intensity that it carries.
The more the amplitude, the more would be the intensity, and hence more would be the volume of the sound heard.
Question 4
1 / -0

Ultrasonic sound waves are produced by which of the device below?

A
Spectrometer

B
SONAR

C
LUNAR

D
Loud Speaker

Solution

SONAR - Sound navigation and ranging is a technique, that uses ultrasonic sound waves to navigate and to detect objects on or under the surface of water.
Question 5
1 / -0

Elephants communicate with

A
Sonic sound

B
Infrasonic sound

C
Ultrasonic sound

D
None of these

Solution

Elephants can communicate using very low frequency sounds, with pitches below the range of human hearing. These low frequency sounds(frequency less than $$20Hz$$), termed infrasonic sounds, can travel several kilometers, and provide elephants with a private communication channel that plays an important role in elephants complex social life. Their frequencies are as low as the lowest notes of a pipe organ.
Question 6
1 / -0

A wave source produces $$10$$ oscillations in $$100\ ms$$. Find the time period of the wave.

A
$$1\ s$$

B
$$0.01\ s$$

C
$$10\ s$$

D
$$0.1\ s$$

Solution

The number of oscillations per unit time is known as frequency $$f$$.
The time period $$T$$ is the time needed to complete one cycle or vibration.
$$f=\dfrac 1T$$

Given,
Number of oscillations, $$N = 10$$
Time, $$t=100\ ms$$
$$t= 100\times 10^{-3}=0.1\ s$$

Frequency, $$f= \dfrac Nt$$

$$f=\dfrac{10}{0.1}$$

$$f= 100\ Hz$$

Time period, $$T=\dfrac 1f$$

$$T=\dfrac{1}{100}

$$T=0.01\ s$
Question 7
1 / -0

When we increase the loudness of sound of a TV, the property of sound that changes is:

A
Amplitude

B
Frequency

C
Wavelength

D
Speed

Solution

Loudness of sound is proportional to the intensity and amplitude of sound. So when we turn on the volume of TV, the amplitude of sound wave increases hence, loudness of sound increases
So the answer is A.
Question 8
1 / -0

The property of ultrasonic waves used in manufacturing emulsion for photographic films is its ________.

A
High speed

B
High frequency

C
Higher wavelength

D
High amplitude

Solution

Frequencies higher than $$20\ kHz$$ are called ultrasonic sound or ultrasound. The property of ultrasonic waves in manufacturing emulsion for photographic films in its high frequency.
Question 9
1 / -0

A sound wave has a wavelength $$\lambda$$. The distance between the first compression and the third rarefaction is

A
$$\lambda$$

B
$$3\lambda$$

C
$$3\lambda/4$$

D
$$5\lambda/2$$

Solution

$$\because$$ Distance between two consecutive Compression is $$\lambda$$ and the distance between one compression to next rarefection is equal to $$\lambda/2$$.
Hence, distance between first compression and the third rarefaction is $$\lambda + \lambda+\lambda/2=5\lambda/2 $$
Question 10
1 / -0

The audible range in humans is ____________.

A
$$20 Hz$$ to $$2000 Hz$$

B
$$200 Hz$$ to $$20,000 Hz$$

C
$$20 Hz$$ to $$20,000 Hz$$

D
$$200 Hz$$ to $$20 kHz$$

Solution

Audible range of human ear is $$20Hz - 20000Hz$$
so the answer is C

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Re-Attempt Weekly Quiz Competition

Sound Test - 25

Result

Sound Test - 25

Score

-

Rank

-

SHARING IS CARING

Question 1

To measure depth of sea bed

To locate scraps

To locate submarines

All of the above

Solution

Question 2

$$0.003\ Hz$$

$$0.018\ Hz$$

$$6\ Hz$$

$$55\ Hz$$

$$3300\ Hz$$

Solution

Question 3

amplitude

speed

wavelength

period

frequency

Solution

Question 4

Spectrometer

SONAR

LUNAR

Loud Speaker

Solution

Question 5

Sonic sound

Infrasonic sound

Ultrasonic sound

None of these

Solution

Question 6

$$1\ s$$

$$0.01\ s$$

$$10\ s$$

$$0.1\ s$$

Solution

Question 7

Amplitude

Frequency

Wavelength

Speed

Solution

Question 8

High speed

High frequency

Higher wavelength

High amplitude

Solution

Question 9

$$\lambda$$

$$3\lambda$$

$$3\lambda/4$$

$$5\lambda/2$$

Solution

Question 10

$$20 Hz$$ to $$2000 Hz$$

$$200 Hz$$ to $$20,000 Hz$$

$$20 Hz$$ to $$20,000 Hz$$

$$200 Hz$$ to $$20 kHz$$

Solution

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