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Sound Test - 32

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Sound Test - 32
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  • Question 1
    1 / -0
    A wave is moving in air with a velocity of 340 m/s. Calculate the wavelength if its frequency is 512 vibrations/ sec ?
    Solution
    $$V= 340 m/s; f = 512 \ Hz$$
    Now we know ,
    $$V=f\lambda$$
    $$\lambda = \dfrac{V}{f}= \dfrac{340}{512}= 0.67 m$$
  • Question 2
    1 / -0
    Which is the quantity determines the loudness of a sound wave ?
    Solution
    The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases. Loudness is measured in units called decibels. 
  • Question 3
    1 / -0
    Two sounds $$A$$ and $$B$$ are of the same amplitudes, same wave forms, but of frequencies $$f$$ and $$2f$$ respectively. Then:
    Solution
    Amplitude determines the loudness of a sound wave. Frequency determines the pitch or shrillness of the sound. The shrillness of a sound is directly proportional to the frequency of the sound wave. Therefore, sound $$B$$ is shrill and sound $$A$$ is flat as the frequency of $$B$$ is more than that of $$A$$.
  • Question 4
    1 / -0
    A person standing symmetrically between two cliffs claps his hands and starts hearing series of echoes at intervals of 1 sec. If speed of sound in air is 340 m/s, the distance between the parallel cliff must be
    Solution
    Let x be distance of person from each cliff

    $$\therefore x+x=v\times t=340\times 1=340$$

    $$x=170 m$$

    Distance between two cliffs $$= 2\times 170 = 340 m $$
  • Question 5
    1 / -0
    The frequency of light of wave length $$5000\ {\buildrel_{\circ}\over {A}}$$ is:
    Solution
    Given,
    Wavelength, $$\lambda=5000\  {\buildrel_{\circ}\over {A}}$$
    $$\lambda=5000\times 10^{-10}\ m$$
    We know,
    Frequency, $$ f = \dfrac{c}{\lambda } $$
    where, $$ c = $$ velocity of light $$=3\times 10^{-8}\ m/s$$
    $$\lambda  =$$ wavelenght
    $$\therefore f= \dfrac{ 3 \times  10^{8}}{5000 \times  10^{-10} }$$

    $$f= 6 \times 10^{14}\ Hz$$
  • Question 6
    1 / -0
    A progressive sound wave of frequency 500Hz is travelling through air with a speed of $$ 350 ms^{-1} $$. A compression maximum appears at a place at a given instant. The minimum time interval after which the rarefraction maximum occurs at the same point , is
    Solution
    Time period of wave $$T =\dfrac{1}{500}$$

    In one time period there is a maximum of both rarefaction and compression, 

    hence time after which rarefaction occurs is $$\dfrac{T}{2} = \dfrac{1}{1000}$$ 
  • Question 7
    1 / -0
    If the amplitude of a wave is doubled, what will be the effect on its loudness ?
    Solution
    Loudness depends on the square of the amplitude of the wave. 

    That is, $$loudness\propto { \left( amplitude \right)  }^{ 2 }$$

    Thus, when amplitude of the wave is doubled, the loudness becomes four times.
  • Question 8
    1 / -0
    Each of the properties of sound listed in column A primarily depends on one of the quantities in column B. Choose the matching pairs from two columns.
    Column AColumn B
    PitchWaveform
    QualityFrequency
    LoudnessIntensity
    Solution
    The pitch of a note is determined by the frequency. The number of vibrations per second is called frequency.
    The loudness of the sound heard is determined by the amplitude (intensity). The maximum displacement of a point on a vibrating body or wave measured from its equilibrium position is called amplitude.
    The quality of the note is determined by the waveform.
  • Question 9
    1 / -0
     Loudness is proportional to
    Solution
    Loudness is directly proportional to square of the amplitude of vibrating body.
    That is, $$loudness\propto { (amplitude) }^{ 2 }$$.
  • Question 10
    1 / -0
    Choose the correct option. 
    Sound cannot travel in:
    Solution
    Sound is produced when something vibrates. The vibrating body causes the medium (water, air, etc.) around it to vibrate. 
    The mechanical vibrations that can be interpreted as sound are able to travel through all forms of matter: gases, liquids, solids, and plasmas. The matter that supports the sound is called the medium
    Sound cannot travel through a vacuum. Sounds cannot be heard in a vacuum, as waves need a medium to carry them.
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