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Sound Test - 44

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Sound Test - 44
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  • Question 1
    1 / -0
    The frequency of sound waves in water is
    Solution
    Frequency of a wave is characterised by the source of the wave, which produces disturbance, therefore it doesn't change when medium is changed. So frequency will not change in water and will be same as the frequency of source.
  • Question 2
    1 / -0
    The waves produced by a motor boat sailing in water are
    Solution
    When a motor boat sails in water, waves will be produced on the surface of the water. Water waves are a combination of longitudinal and transverse waves as the particles move in a circular path. We can't classify them as purely longitudinal or purely transverse waves.

  • Question 3
    1 / -0
    A stone is dropped from the top of a tower $$500\ m$$ high into a pond of water at the base of the tower. When is the splash heard at the top? (Given $$g = 10 \ ms^{-2}$$ and speed of sound $$ = 340\ ms^{-1}$$)
    Solution
    Given,
    Height of the tower, $$h= 500\ m$$
    Initial velocity, $$u= 0$$
    Acceleration due to gravity, $$g=10\ m/s^2$$
    Speed of sound, $$v_s=340\ m/s$$

    Let $$t_1$$ be the time taken by the stone to reach the surface of the pond.

    Using Newton's second equation of motion,
    $$s=ut+\dfrac 12at^2$$

    $$500=(0\times t_1)+\dfrac 12 (10\times t_1^2)$$

    $$500=5t_1^2$$
    $$\implies t_1=\sqrt{100}$$
    $$t_1=10\ s$$

    Let $$t_2$$ be the time taken by the sound of the stone to reach the top.
    We know,
    $$speed=\dfrac{distance}{time}$$

    $$\implies time=\dfrac{distance}{speed}$$

    $$t_2=\dfrac{h}{v_s}$$

    $$t_2=\dfrac{500}{340}$$

    $$t_2=1.47\ s$$

    Total time after which the splash will be heard, $$T=t_1+t_2$$
    $$T=10+1.47$$
    $$T=11.47\ s$$
  • Question 4
    1 / -0
    Which of the following type of waves is used in the SONAR device?
    Solution
    Answer is D.

    SONAR is the best example that illustrates how a ship on the ocean utilizes the reflecting properties of sound waves to determine the depth of the ocean. A sound wave is transmitted and bounces off the seabed. Because the speed of sound is known and the time lapse between sending and receiving the sound can be measured, the distance from the ship to the bottom of the ocean can be determined. This technique is called sonar (SOund Navigation And Ranging).
    A common use of ultrasound is in SONAR. Ultrasonic waves are used in SONAR instead of audible sound waves.
  • Question 5
    1 / -0
    In a slinky
    Solution
    Slinky is a helical spring toy. By fixing one end on a rigid support and holding the other end waves can be generated. By moving it back and forth, longitudinal waves can be generated. By moving up and down, transverse can be made.

  • Question 6
    1 / -0
    The speed of a sound wave is $$330\ ms^{-1}$$ and its frequency is $$550\ Hz$$. What is its wavelength?
    Solution
    The relation between wavelength $$(\lambda)$$, speed of wave$$(v)$$, and frequency of wave$$(f)$$ is-
    $$v = f \lambda$$
    $$\lambda = \dfrac{ v }{ f }$$
    $$v = 330 ms^{-1}$$
    $$f = 550\ Hz$$
    $$\Rightarrow \lambda = \dfrac{ 330 }{ 550 }$$
    $$\Rightarrow \lambda = 0.6\ m$$
  • Question 7
    1 / -0
    The walls and ceiling of an auditorium are covered with a fibrous material to
    Solution
    The sound created in a big hall will persist by repeated reflection from the walls until it is reduced to a value where it is no longer audible. The repeated reflection that results in this persistence of sound is called reverberation. In an auditorium or big hall excessive reverberation is highly undesirable. To reduce reverberation, the roof and walls of the auditorium are generally covered with sound-absorbent materials like compressed fibreboard, rough plaster or draperies. We know that such soft, porous and fibrous materials are good absorbers of sound. The seat materials are also selected on the basis of their sound absorbing properties. 
  • Question 8
    1 / -0
    The distance between two consecutive compressions and rarefaction is 1.7 m. The wavelength of the wave is.
    Solution
    Wavelength $$\lambda$$ is defined as the distance between two consecutive compressions or rarefactions, therefore the distance between consecutive compression and rarefaction will be $$\lambda/2$$,
    Given,
                       $$\lambda/2=1.7$$
        
    Therefore, 
       Wavelength of the wave,  $$\lambda=2\times1.7=3.4\ m$$
  • Question 9
    1 / -0
    The maximum speed of vibrations which produce audible sound will be in ________.
    Solution
    solids have highest velocity of sound in them among all phases so a metal being a solid has very high velocity of sound.
    so the answer is C.
  • Question 10
    1 / -0
    Which of the following are the properties of a sound produced by a guitar?:
    Solution
    The answer is D.
    • Pitch is the property of a sound which is decided by the frequency of the sound.
    • Loudness is the property of a sound which is decided by the amplitude of the sound.
    • Timbre is the property of a sound which is decided by the waveform of the sound.
    The sound produced by a guitar has a particular amplitude, frequency, and waveform. Therefore, this sound will have a particular pitch, loudness, and timbre.

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