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Sound Test - 45

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Sound Test - 45
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Buzzing of a mosquito is: 
    Solution
    The answer is B.

    The buzzing of a mosquito has a high pitch, though low in intensity. 
    Pitch is that characteristic of a sound by which a shrill sound can be distinguished from a grave one even though the two sounds may be of the same intensity.
  • Question 2
    1 / -0
    The device/instrument which does not work on the multiple reflections of sound waves is:
    Solution
    Except for guitar, all the listed instruments work on multiple reflections of sound. Guitar works on the vibration of strings 
    so the answer is C.
  • Question 3
    1 / -0
    Velocity of sound in a medium is :
    Solution
    Answer is D.

    Sound is a mechanical wave and travels by compression and rarefaction of the medium. Its velocity in an elastic medium is proportional to the square root of Tension in the medium. A higher density leads to more elasticity in the medium and hence the ease by which compression and rarefaction can take place. This way the velocity of sound increases by increase in density. 
    Hence, velocity of sound in a medium is inversely proportional to the square root of its density.
  • Question 4
    1 / -0
    There is no atmosphere on moon. Therefore,
    Solution
    Since sound waves are longitudinal in nature, so it requires a material medium to propagate. As there is no atmosphere on moon, so sound wave cannot propagate on moon. Thus, sound cannot be heard on moon.
  • Question 5
    1 / -0
    SONAR is frequently used by:
    Solution
    Echo sounding is a type of SONAR used to determine the depth of water by transmitting sound pulses into water. The time interval between emission and return of a pulse is recorded, which is used to determine the depth of water along with the speed of sound in water at the time. This information is then typically used for navigation purposes or in order to obtain depths for charting purposes. 
    Hence, SONAR is used by navigators.
  • Question 6
    1 / -0
    The phenomenon of echo of sound waves is due to:
    Solution
    Answer is A.

    Like all waves, sound waves can be reflected. Sound waves suffer reflection from the large obstacles. As a result of reflection of sound wave from a large obstacle, the sound is heard which is named as an echo. Ordinarily echo is not heard as the reflected sound gets merged with the original sound. Certain conditions have to be satisfied to hear an echo distinctly (as a separate sound). 
    Hence, the phenomenon of echo of sound waves is due to reflection.
  • Question 7
    1 / -0
    If the distance between two consecutive crests of a sound wave is $$L$$, then its wavelength is given by :
    Solution
    The wavelength of a sound wave is the distance between two consecutive crests or two consecutive troughs.
    Here it is given that the distance between the two consecutive crests of a sound wave is $$L$$. So, the wavelength is also $$L$$.

  • Question 8
    1 / -0
    If the distance between a crest and its consecutive trough for a sound wave is $$L$$, then its wavelength is given by :
    Solution
    The wavelength of the sound wave is the distance between two consecutive crests or two consecutive troughs. The sound wave is periodic. So the length of the crests or trough are always same. Here, it is given that the distance between a crest and its consecutive trough foe a sound wave is $$L$$. So, its wavelength is $$2L$$.

  • Question 9
    1 / -0
    The frequency of a wave is 5 Hz. It refers to (type of wave) ___________.
    Solution
    The waves below the frequency of 20 Hz are infrasonic waves. So, the wave of 5 Hz is also an infrasonic wave.
  • Question 10
    1 / -0
    If a sound wave of time period $$T$$ travels with a velocity $$V$$, then the wavelength is given by :
    Solution
    Wavelength is the distance travelled by the wave during the time a particle completes one vibration.

    Therefore, if $$\lambda$$ be the wavelength and $$T$$ the time period, then the wave travels a distance $$\lambda$$ in time $$T$$.

    Hence,

    $$Wave\, velocity=\dfrac{Distance}{Time}$$

    $$V=\dfrac{\lambda}{T}$$

    $$\Rightarrow \lambda=VT$$
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