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Sound Test - 59

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Sound Test - 59
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  • Question 1
    1 / -0
    A man produces sound with a trumpet. A wave has a wavelength of 8.75 mm and a frequency of 40kHz. If the man receives an echo after reflecting from the wall 0.4 s later. Calculate the distance between man and the wall.
    Solution
    Given :    $$t =0.4$$ s                 $$\nu = 40 $$ kHz $$ = 40000$$  Hz                  $$\lambda =8.75mm = 0.00875$$ $$m$$
    $$\therefore$$ Speed of sound      $$v = \nu \lambda = 40000 \times 0.00875  = 350$$  m/s
    Let the distance between the man and the wall be  $$x$$. 
    Thus sound wave has to travel  $$2x$$ distance in 0.4 s so that the man hears an echo.
    $$\therefore$$    $$2x = vt$$
    OR       $$2x = 350 \times  0.4$$                         $$\implies x =70$$  m
  • Question 2
    1 / -0
    A tuning fork makes $$256$$ $$vibrations/s$$ in air. When velocity of sound in air is $$330 {m}/{s}$$, then the wavelength of tone emitted is
    Solution
    We know 
    $$v=n\lambda$$
    Where
    $$v$$ is speed of sound.
    $$n$$ is frequency.
    $$\lambda$$ is wavelength.
    Given
    $$n=256vibrations/s=256Hz$$
    $$v=330m/s$$
    $$330=256\times \lambda$$
    $$\lambda=\dfrac{330}{256}=1.29m$$
  • Question 3
    1 / -0
    The loudness and pitch of a sound note depend on :
    Solution
    Pitch is a term used to describe how high or low a note  being played by a musical instrument or sung seems to be. It is dependent upon the frequency of source of sound.

    Loudness depends upon the amplitude of sound wave. Thus it depends upon its intensity.
    The larger the amplitude the more energy the sound wave contains therefore the louder the sound.
  • Question 4
    1 / -0
    Identify the type of waves generated by you when you are jumping with jumping ropes.
    Solution
    Waves in jumping rope are transverse waves since the displacement of each point in the rope is perpendicular to the direction of energy propagation.

  • Question 5
    1 / -0
    Which of the following represent the distance between two consecutive compressions of a longitudinal wave?
    Solution
    A longitudinal wave is one in which the displacement of the medium is in the same direction as, or the opposite direction to, the direction of travel of the wave.  The waves move with compressions and rarefactions along itself. The distance between two consecutive compressions or rarefaction is called the wavelength of the wave.

  • Question 6
    1 / -0
    One sound wave strikes a person's ear every 1/100 of second. The speed of the sound where the person is located is 345 m/s. What is the frequency of the sound?
    Solution
    Time period of wave of striking the person's ear         $$T = \dfrac{1}{100} = 0.01$$ second
    Thus frequency of the sound wave      $$\nu = \dfrac{1}{T} = \dfrac{1}{0.01} = 100$$ Hz
  • Question 7
    1 / -0
    Identify the type of sound wave.
    Solution
    Sound waves are longitudinal waves, that is, they travel by forming compressions and rarefactions from the particles present in the medium through which they travel.
    A pictorial representation of the waves is as shown in the figure.
    The denser regions are called compressions, and the lighter regions are called rarefactions.

  • Question 8
    1 / -0
    One sound wave strikes a person's ear every $$1/100$$ of a second. The speed of sound where the person is located is $$345 m/s$$.
    What is the frequency of the sound?
    Solution
    Time period of sound wave       $$T = \dfrac{1}{100}$$ second

    $$\therefore$$ Frequency of sound wave      $$\nu = \dfrac{1}{T} =100$$  $$Hz$$
  • Question 9
    1 / -0

    Directions For Questions

    In below shown figure, a glass tank of length 9 meters is filled with waters. a longitudinal wave moving through water as shown in figure. The frequency of the wave is 500 Hz.

    ...view full instructions

    This wave could be which of the following types of waves?

    Solution
     Sound is the only longitudinal wave listed. All of the other waves listed are transverse.
  • Question 10
    1 / -0
    A device which is used to find the depth of sea is called:
    Solution
    SONAR (originally an acronym for Sound Navigation And Ranging) is a technique that uses sound propagation (usually underwater, as in submarine navigation) to navigate, communicate with or detect objects on or under the surface of the water, such as other vessels. This technique utilizes ultrasonic waves to estimate and measure the distance, direction and speed of objects underwater.

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