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Sound Test - 65

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Sound Test - 65
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Weekly Quiz Competition
  • Question 1
    1 / -0
    A sound wave whose frequency is 220 Hz has a speed of $$440ms^{-1}$$  in a given medium.  The wavelength of the sound is: 
  • Question 2
    1 / -0
    Which of the following option is incorrect?
    Solution

  • Question 3
    1 / -0
    Sound waves having the following frequency are audible to human beings:
    Solution
    Audible range of frequency is $$ 20 \mathrm{Hz} $$ to $$ 20 \mathrm{kHz} $$
    So, the audible frequency will consist of 5000 cycles/sec.
  • Question 4
    1 / -0
    The device which is not based on the reflection of sound is 
    Solution
    Megaphone: A megaphone, speaking-trumpet, bullhorn, blowhorn, or loudhailer is usually a portable or hand-held, the cone-shaped acoustic horn used to amplify a person's voice or other sounds and direct it in a given direction.

    Galton's whistle: A dog whistle is a type of whistle that emits sound in the ultrasonic range, which most humans cannot hear but some other animals can, including dogs and domestic cats, and is used in their training.

    Sonar: Sonar is a technique that uses sound propagation to navigate, communicate with or detect objects on or under the surface of the water, such as other vessels.

    Stethoscope: The stethoscope is an acoustic medical device for auscultation, or listening to internal sounds of an animal or human body. It typically has a small disc-shaped resonator that is placed against the skin and one or two tubes connected to two earpieces.
  • Question 5
    1 / -0
    An echo is heard only, if the original sound after reflection reaches the ear in
    Solution
    The most important condition for hearing an echo is that the reflected sound should reach the ear only after a lapse of at least $$0.1 \ sec$$ after the original sound dies off. It is because the sensation of sound persists in our brain for about $$0.1 \ s$$.

    $$\therefore$$ Option C is correct.
  • Question 6
    1 / -0
    Ultrasonic signal sent from $$SONAR$$ returns to it after reflection from a rock after a lapse of $$1\, s$$. If the velocity of ultrasound in water is $$1600\, m/s$$, the depth of the rock in water is 
    Solution
    If $$ d $$ is the distance of rock from SONAR then,

    The distance covered by the sound wave is:
    $$2 d= v t $$

    $$\Rightarrow d=\dfrac{v \times t}{2}$$

    $$=\dfrac{1600 \times 1}{2}=800 \ \mathrm{m}$$
  • Question 7
    1 / -0
    The frequency of a rod is $$200\ Hz$$. If the velocity of sound in air is $$340\ ms^{ -1 }$$, the wavelength of the sound produced is 
    Solution
    The relation between frequency, speed, and wavelength of a wave is-
    $$v = f \lambda$$
    $$v$$: Speed of the wave
    $$f$$: Frequency of the wave
    $$\lambda$$: Wavelength of the wave
    $$\Rightarrow \lambda = \dfrac{ v }{ f }$$

    $$\Rightarrow \lambda = \dfrac{ 340 }{ 200 }$$

    $$\Rightarrow = 1.7\ m$$
  • Question 8
    1 / -0
    The speed of sound in air is $$340\ m/s$$, while in water is $$1445\ m/s$$. If the wavelength of sound in water is $$8.5\ cm$$, the wavelength of sound in air is
    Solution
    Frequency does not change due to change pf medium.
        $$\therefore c_{1}=f\lambda_{1}$$

    and $$c_{2}=f\lambda_{2}$$

     $$\therefore \dfrac{\lambda_{2}}{\lambda_{1}}=\dfrac{c_{2}}{c_{1}}$$

      $$\therefore \lambda_1 =\left(\dfrac{340}{1445}\right)\times 8.5=2 \ cm$$
  • Question 9
    1 / -0
    An astronaut can not hear his companion's sound at the surface of moon because:
    Solution
    As there is no atmosphere on the surface of moon so sound wave cannot travel through vacuum as they are mechanical wave and need medium to travel that's why an astronaut cannot hear his companion's sound at the surface of moon.
  • Question 10
    1 / -0
    When a tuning fork vibrates, the waves produced in the stem are:
    Solution
    When a tuning fork is sounded by striking its one end, the prongs vibrate in and out and the stem vibrates up and down. Hence, the vibration of prongs is transverse and those of stem are longitudinal. 
    Hence Option A is correct
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