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Sound Test - 67

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Sound Test - 67
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  • Question 1
    1 / -0
    When a tuning fork vibrates, the waves produced in the fork are
    Solution
    When a tuning fork vibrates, it sets up tiny waves of pressure in the air, which we detect as sound. These waves are compression waves or longitudinal waves in nature because the air gets compressed by the vibrating object and that compression is in the same direction as the wave travels.

  • Question 2
    1 / -0
    Eardrum is a part of 
    Solution
    Eardrum is a part of Hearing organ
  • Question 3
    1 / -0
    The sound in the audible range is called 
    Solution
    The sound in the audible range is called Sonic.
  • Question 4
    1 / -0
    Relation between frequency and time period is 
    Solution
    The relation is $$f =\dfrac 1T$$ or $$frequency = \dfrac{1}{Time \ period}$$
  • Question 5
    1 / -0
    The sound of frequency less than $$20\ Hz$$ is known as:
    Solution
    Sounds with frequencies below $$20\ Hz$$ are called infrasound. Infrasound is too low-pitched for humans to hear.
  • Question 6
    1 / -0
    A pendulum oscillates $$20$$ times in $$2$$ seconds then its time period is 
    Solution
    Time period is $$T=\dfrac 2 {20} = 0.1 / sec$$
  • Question 7
    1 / -0
    The loudness and pitch of a sound depends on:
    Solution
    The magnitude of the maximum disturbance in the medium on either side of the mean value is called the amplitude of the wave. The loudness or softness of a sound depends on its amplitude.

    The number of complete oscillations per unit time is called frequency. The pitch of a sound depends on frequency.
  • Question 8
    1 / -0
    In a clock, the time period of hour hand is :
    Solution
    The hour hand of a clock completes one revolution in $$12\ hr$$. If the hour hand starts from $$12$$ in the noon then it will come back to $$12$$ at night. So it takes $$12\ hours$$ to complete one revolution.
    Hence, the time period of the hound hand is $$12\ hours$$. 
  • Question 9
    1 / -0
    The speed of a wave is $$ 350\, m/s $$ and its wavelength $$ 50\,cm $$ , then the frequency of the wave will be :
    Solution
    Speed $$v$$, wavelength $$\lambda$$ and frequency $$\nu$$ of a wave is related as
    $$v=\nu\times{\lambda}$$     $$\lambda=50cm$$ = $$0.5m$$
      $$v=350m/s$$ 
     so $$\nu=$$ $$\frac{v}{\lambda}$$ = $$\frac {350}{0.5}$$ = $$700Hz$$
  • Question 10
    1 / -0
    In longitudinal waves, the vibration of the particles of the medium:
    Solution

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