Sound Test

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Sound Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

Children can hear sound of frequency up to

A
25,000 Hz

B
20,000Hz

C
20Hz

D
30,000Hz

Solution

Children under the age of five can hear sound up to 25,000Hz which is more than normal adult hearing range. As people grow older their ears become less sensitive to higher frequency.
Question 2
1 / -0

A wave moves a distance of 10 m in 0.05 second. Find the wavelength of the wave if frequency is 200 Hz?

A
0.1 m

B
1 m

C
0.8 m

D
0.5 m

Solution

We know that, velocity = distance travelled /time taken

=10 m/0.05 s

= 200m/s.

Now,

Wavelength = wave speed / frequency

⟹ 200 ms⁻¹/ 200Hz = 1m.

Therefore,the wavelength of the wave is 1 m.
Question 3
1 / -0

Statement A: Speeds greater than the speed of sound in air are called infrasonic speed.
Statement B: The amount of sound energy, passing each second through unit area is called intensity of sound.
Which of the above two statement is true?

A
Statement A

B
Statement B

C
Both A and B

D
Neither A nor B.

Solution

The speed that is greater than the speed of sound is known as supersonic.
The amount of sound energy, passing each second through unit area is called intensity of sound.
So, statement B is true statement and statement A is false statement.
Question 4
1 / -0

The frequency of a source of sound is 546 Hz. It vibrates ___________ times in a second

A
1/546

B
1092

C
546

D
223

Solution

Frequency is defined as the number of vibrations or waves produced per second.

If a source of sound has a frequency of 546 Hz, it means that it vibrates 546 times in one second.
Question 5
1 / -0

A sound wave travels at a speed of 344 ms^-1. If its wavelength is 0.02m, what is the frequency of wave?

A
1700Hz

B
17820Hz

C
17200 Hz

D
none of these.

Solution

Frequency of wave = wave speed / wavelength.

Frequency =344ms⁻¹/ 0.02 m = 17200 Hz
Question 6
1 / -0

Which of the following condition is not favourable for producing higher pitch?

A
Length of the vibrating portion should be small.

B
Length of the vibrating column should be shorter.

C
Vibrating string should be very thin

D
Vibrating string should be thick.

Solution

The sound of high pitch cannot be produced by vibrating string of thicker diameter. This is because thick strings vibrate with lower frequency. For example,thin strings of a guitar or sitar give out sound of higher pitch as they vibrate with a greater frequency than the thick strings.
Question 7
1 / -0

The frequency of sound is 100 Hz. How many times does it vibrate in a minute?

A
60 Hz

B
5000 Hz

C
6000 Hz

D
600 Hz

Solution

Frequency of sound is the number of vibration per second.

Here, frequency = 100Hz. One minute = 60 seconds.

So, number of vibrations in one minute = 60 × 100 = 6000 Hz.
Question 8
1 / -0

Calculate the wavelength of a sound wave whose frequency is 220 Hz and speed is 440 ms^-1 in a given medium.

A
2 m

B
4 m

C
0.5 m

D
8 m

Solution

Frequency = 220Hz

Wave speed = 440 ms^-1.

Since, wavelength= wave speed / frequency

=>Wavelength = 440/220 = 2 m.
Question 9
1 / -0

Statement A: Sound travel faster in summer season than in winter season
Statement B: Speed of sound does not depend on the pressure of the medium. If temperature of the medium remains constant
Which of the two statement is true

A
Statement A

B
Statement B

C
Both A and B

D
Neither A nor B

Solution

Speed of sound increases with temperature.So,sound travel faster in summer than winter season.

At a constant temperature, the gas pressure has no effect on the speed of sound, since the density will increase, and since pressure and density (also proportional to pressure) have equal but opposite effects on the speed of sound, and the two contributions cancel out exactly.
Question 10
1 / -0

Match the following with correct response.
(1) Amplitude
(2) Time period
(3) Frequency
(4) Velocity

(A) Duration to complete one oscillation
(B) Distance covered by sound in unit time
(C) Number of oscillation in one second
(D) Maximum displacement from mean position

A
1-D, 2-A, 3-C, 4-B

B
1-A, 2-C, 3-B, 4-D

C
1-B, 2-D, 3-A, 4-C

D
1-C, 2-B, 3-D, 4-A

Solution

The maximum displacement of the particles of a medium from their mean positions during the propagation of a wave is called the amplitude of the wave.

The time required to produce one complete wave (or wave cycle) is called the time period of the wave.

The frequency of a wave is defined as the number of waves produced per second.

The distance travelled by a wave in one second is called the velocity of the wave.

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Re-Attempt Weekly Quiz Competition

Sound Test - 7

Result

Sound Test - 7

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Rank

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SHARING IS CARING

Question 1

25,000 Hz

20,000Hz

20Hz

30,000Hz

Solution

Question 2

0.1 m

1 m

0.8 m

0.5 m

Solution

Question 3

Statement A

Statement B

Both A and B

Neither A nor B.

Solution

Question 4

1/546

1092

546

223

Solution

Question 5

1700Hz

17820Hz

17200 Hz

none of these.

Solution

Question 6

Length of the vibrating portion should be small.

Length of the vibrating column should be shorter.

Vibrating string should be very thin

Vibrating string should be thick.

Solution

Question 7

60 Hz

5000 Hz

6000 Hz

600 Hz

Solution

Question 8

2 m

4 m

0.5 m

8 m

Solution

Question 9

Statement A

Statement B

Both A and B

Neither A nor B

Solution

Question 10

1-D, 2-A, 3-C, 4-B

1-A, 2-C, 3-B, 4-D

1-B, 2-D, 3-A, 4-C

1-C, 2-B, 3-D, 4-A

Solution

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