Is Matter Around Us Pure Test

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Is Matter Around Us Pure Test - 44

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Question 1
1 / -0

How can we obtain coloured component from blue/black ink?

A
By distillation

B
By evaporation

C
By sedimentation

D
By centrifugation

Solution

Ink is a mixture of dye in water. So, a volatile component can be separated from its non-volatile component by evaporation.
Question 2
1 / -0

Seperation of dye from blue/black ink via evaporation is:

A
solute-solute separation

B
solvent-solvent separation

C
solute-solvent separation

D
all of the above

Solution

A volatile component (solvent) can be separated from its non-volatile component by evaporation. So, it is a solute-solvent separation. Here dye is solute while water is the solvent.
Question 3
1 / -0

Pure copper sulphate $$(CuSO_4)$$ can be obtained from an impure sample by :

A
crystallization

B
galvanization

C
centrifugation

D
sedimentation

Solution

Crystallisation is a method used to purity solids. Pure $$CuSO_4$$ in the form of cystals can be obtained from an impure sample by crystallisation.
Question 4
1 / -0

While separating dye from blue/black ink, what do you think which has got evaporated from watch glass?

A
Solute, i.e. dye

B
Solvent, i.e. dye

C
Solute, i.e. water

D
Solvent, i.e. water

Solution

Water is the volatile component in the ink-water mixture so, it evaporates on heating.
Question 5
1 / -0

What is the basic concept used in separating a dye from blue/black ink?

A
A volatile component can be separated from a non-volatile component

B
Two substances that differ in their molecular weight can be separated

C
Two substances which differ in their densities can be separated

D
All of the above

Solution

Dye is a mixture of ink in water. Thus, we can separate the volatile component from its non-volatile component by evaporation.
Option A is correct.
Question 6
1 / -0

While doing chromatography using black ink, the results seen is/are:
(a) black ink is a mixture of red, green, and blue colours.
(b) ink is a mixture of dye and water.

A
a only

B
b only

C
Both A and B

D
None of these

Solution

The ink that we use has water as the solvent and the dye(solute) is soluble in it.
While doing chromatography, the water rises on the filter paper and it takes the dye particles along with it. Usually, a dye is a mixture of two or more colours. The coloured component that is more soluble in water, rises faster and in this way, the colours get separated and we can see red, green, blue and pink colours.
Question 7
1 / -0

In the experiment that we do for separating dyes in black ink using chromatography, which component of colour rises faster on the filter paper?

A
Coloured component that is comparatively less soluble in water

B
Coloured component that is more soluble in water

C
The one which is lighter in weight

D
The one that has less affinity for water

Solution

The principle of chromatography is based on the fact that the two substances are dissolved in the same solvent but their solubilities can be different.
According to the principle of chromatography, the coloured component that is more soluble in the water rises faster and in this way, colours get separated.
Since the ink is a mixture of two or more colours so the more soluble colour rises faster and gets separated.
Hence, the correct option is $$B$$.
Question 8
1 / -0

Mark the correct statement regarding "solution".

A
Particle of a solution are larger than 1 nm in diameter.

B
They do not scatter a beam of light passing through them.

C
The path of light is visible in a solution.

D
None of the above

Solution

A solution is a homogeneous mixture. The particles of a solution are smaller than 1 nm in diameter. So, they cannot be seen by naked eyes. Because of their small particle size they do not scatter a beam of light passing through the solution. So, the path of light is not visible in a solution.
So, option B is correct.
Question 9
1 / -0

How can you prove that dye in a black ink is a mixture of many colors?

A
By evaporation

B
By sedimentation

C
By chromatography

D
All of the above

Solution

Ink is a mixture of dye in water and it can be proved by evaporation. The fact that dye is a mixture of many colours can be proven by chromatography.
Black ink that we normally use contains water as a solvent. By chromatography, we can see that the coloured component which is more soluble in water rises faster, and in this way, colours get separated.
Hence, option $$C$$ is correct.
Question 10
1 / -0

A liquid is contaminated with non-volatile impurities. Suggest method of purification.

A
Sedimentation

B
Distillation

C
Centrifugation

D
Evaporation

Solution

Distillation is a process used for separating into miscible liquids having difference in their boiling points of 20$$^o$$C approx. containing non-volatile impurities.

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Is Matter Around Us Pure Test - 44

Result

Is Matter Around Us Pure Test - 44

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SHARING IS CARING

Question 1

By distillation

By evaporation

By sedimentation

By centrifugation

Solution

Question 2

solute-solute separation

solvent-solvent separation

solute-solvent separation

all of the above

Solution

Question 3

crystallization

galvanization

centrifugation

sedimentation

Solution

Question 4

Solute, i.e. dye

Solvent, i.e. dye

Solute, i.e. water

Solvent, i.e. water

Solution

Question 5

A volatile component can be separated from a non-volatile component

Two substances that differ in their molecular weight can be separated

Two substances which differ in their densities can be separated

All of the above

Solution

Question 6

a only

b only

Both A and B

None of these

Solution

Question 7

Coloured component that is comparatively less soluble in water

Coloured component that is more soluble in water

The one which is lighter in weight

The one that has less affinity for water

Solution

Question 8

Particle of a solution are larger than 1 nm in diameter.

They do not scatter a beam of light passing through them.

The path of light is visible in a solution.

None of the above

Solution

Question 9

By evaporation

By sedimentation

By chromatography

All of the above

Solution

Question 10

Sedimentation

Distillation

Centrifugation

Evaporation

Solution

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