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Is Matter Around Us Pure Test - 66

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Is Matter Around Us Pure Test - 66
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  • Question 1
    1 / -0
    Which of the following statement are false regarding colloidal solution?

    P. Colloidal solutions are homogeneous in nature.

    Q. Colloidal particles pass through an ordinary filter paper.

    R. Colloidal particles can be seen with naked eyes.

    S. Colloidal particles do not settle under gravity.
    Solution
    Colloids are relatively stable in nature. The particles of the dispersed phase are in a state of continuous motion and remain suspended in the solution. 
    Colloids require specialized filters known as ultrafilters for filtration.
    Colloidal solutions are heterogeneous in nature.
    Colloidal particles do not settle under gravity and they can't be seen with naked eyes.

    Hence, option $$A$$ selects the false statements about colloids.
  • Question 2
    1 / -0
    The particles of a suspension will be of size ___.
    Solution
    The particles of a suspension are of a size greater than 100nm , hence option $$A$$ is correct
  • Question 3
    1 / -0
    Identify the pure substance containing only one type of element.
    Solution
    Here sugar $$(C_{12}H_{22}O_{11})$$ , silica $$(SiO_2)$$ and water $$(H_2O)$$  are compounds that contain more than one element. 
    Therefore, they are not pure substances. 
    While the diamond is an isotope of carbon only. Therefore diamond is a pure substance.

    So, the correct answer is $$B$$.
  • Question 4
    1 / -0
    A colloidal system is a two-phase system. Point out which of the following combination can not be considered a colloidal system?
    Solution
    A solid-solid combination can be considered as a colloidal solution and the nature of the solution is solid sol. For example, colorful stone.

    A liquid-liquid solution can be considered as a colloidal solution and the nature of the solution is an emulsion. Example, milk

    A liquid-gas combination can be considered as a colloidal solution and the nature of the solution is aerosol. For example, cloud.

    A gas-gas combination $$\text {can not be}$$ considered as a colloidal solution because this is homogeneous mixture and a colloidal solution is always a heterogeneous mixture.

    Hence, option $$C$$ is correct.
  • Question 5
    1 / -0
    Select the correct statements.
    Solution
    A) All gums are soluble in water. When Lampblack in water is passed, gums in the water get hydrolyzed to yield a number of monosaccharides that are smaller in size. Thus, a colloidal sol is obtained. This is a correct statement.
    B) Formation of a white precipitate of $$BaSO_{4}$$  that is insoluble in water but continuously washing with a large amount of water gives $$BaSO_{4}$$ solution. This is a correct statement.
    C) Electrodialysis has been studied worldwide for the separative removal of various contaminants, such as nitrate, bromide, sodium, zinc, etc. This is also a correct statement.

    Therefore all are correct statements.
  • Question 6
    1 / -0
    Aqueous solution of a mixture contains $$LiCl, CuCl, NaCl$$ and $$AlCl_3$$. This is shaken with ether. What is/are left in water?
    Solution
    1) $$LiCl$$ ,$$NaCl$$ are alkali halides.
    2) Mostly aqueous solution of alkali halides are extracted when ethers are added.
    so, in this case $$AlCl_3$$ and $$CuCl$$ will be eliminated.Thus, answer turns out to be $$LiCl$$ and $$NaCl$$.
    Hence, option $$A$$ is correct.
  • Question 7
    1 / -0
    A student was given a mixture of sulphur and iron fillings. He was told to heat the mixture and observe. What will be the colour of the compound formed?
    Solution
    When sulphur and iron filings are mixed and heated they form a compound $$FeS$$ (ferrous sulphide). $$FeS$$ is black in colour.

    $$Fe+S\longrightarrow FeS$$ (Black coloured compound)

    So, the correct option is (B)
  • Question 8
    1 / -0
    A compound can be a mixture of:
    Solution
    A compound consists of atoms of two or more different elements bound together.
    So, option $$A$$ is correct.
  • Question 9
    1 / -0
    Which of the following compounds do not exist?
    Solution
    In $$B_2Cl_4, BCl_2$$ & $$Cl_2B$$, chlorine due to its large size can not fit in between boron atoms. So, these compounds do not exist.
    Hence, option $$A$$ is correct.
  • Question 10
    1 / -0
    Find out a separating technique to separate the following mixture and write a note on it.
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