Is Matter Around Us Pure Test

Result

Is Matter Around Us Pure Test - 74

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Weekly Quiz Competition

Question 1
1 / -0

The pH of a sample of $$H_{2}SO_{4}$$ is 1.3979. The percentage of the solution is $$73.5\%$$ (W/W), the density of the solution is

A
$$2.66\times10^{-3} g/cc$$

B
$$5.32\times10^{-3} g/cc$$

C
$$1.33\times10^{-3} g/cc$$

D
$$0.01 g/cc$$

Solution
Question 2
1 / -0

Potassium hydroxide solution is used to absorb $${ CO }_{ 2 }$$. How many litres of $${ CO }_{ 2 }$$ at 1.00 atm and $${ 22 }^{ \circ }C$$ would be absorbed by an aqueous solution containing 15.0 g of KOH?

$$2KOH+{ CO }_{ 2 }\rightarrow { K }_{ 2 }{ CO }_{ 3 }+{ H }_{ 2 }O$$

A
3.24 L

B
1.62 L

C
6.48 L

D
0.324 L

Solution
Question 3
1 / -0

Choose the incorrect option

A
$$CHC{I_3}$$ and $$CC{I_4}$$ can be separated by fractional distillation

B
Acetone and benzene can be separated by fractional distillation

C
Aniline is separated from a mixture of aniline and water by the method of steam distillation

D
Glycerol cannot be separated from spent-lye in soap industries by distillation under reduce pressure.

Solution

$$A:$$ $$CHCl_3$$ and $$CCl_4$$ can be separated by fractional distillation- $$True$$.

$$B:$$ $$Acetone$$ and $$Benzene$$ can be separated by fractional distillation - $$True$$.

$$C:$$ $$Aniline$$ is separated from a mixture of aniline and water by steam distillation - $$True$$.

$$D:$$ $$Glycerol$$ cannot be separated from spent-lye in soap industries by distillation under the reduced pressure. - $$False$$.

We know that glycerol is a high boiling point liquid. It is found that glycerol can be separated from spent-lye by the process of fractional distillation under reduced pressure.

Hence, option $$D$$ is correct.
Question 4
1 / -0

Egg albumin is :

A
Reversible colloid

B
Lyophilic colloid

C
Protective colloid

D
All

Solution

Egg albumin is a type of reversible colloid, lyophilic colloid and as well as protective colloid.
Hence the correct option is $$D$$.
Question 5
1 / -0

What is the concentration of chloride ion in the mixture of $$500ml,1 M\ NaCl$$ solution and $$500ml,1M \ CaCl_2$$ solution?

A
2.5

B
1.5

C
1.0

D
3.0

Solution

Mole of $$NaCl$$ = $$\dfrac{500}{1000} \times 1$$ = 0.5 mol $$NaCl$$ or 0.5 mol $$Cl^-$$ ions

Mole of $$CaCl_2$$ = $$\dfrac{500}{1000} \times 1$$ = 0.5 mol $$CaCl_2$$ or 1 mole of $$Cl^-$$ ions

Total mole of $$Cl^-$$ ion 0.5 + 1 = 1.5 mol
Total volume = 500 ml + 500 ml = 1000 ml or 1 L
So concentration of $$Cl^-$$ ion is 1.5 in 1000 mL.
Question 6
1 / -0

Which of the following will form negatively charged colloidal solution ?

A
100 ml 0.1 M AgNO$$_{3}$$ + 100ml 0.1 M KI

B
100 ml 0.2 M AgNO$$_{3}$$ + 100ml 0.1 MKI

C
100ml 0.1 MAgNO$$_{3}$$ + 100ml 0.2 M KI

D
100ml 0.2 M AgNO$$_{3}$$ + 200 ml 0.1 M KI

Solution
Question 7
1 / -0

Homogeneous mixture is formed by mixing

A
sand and water

B
iron filing and sand

C
silver chloride and water

D
ethanol and water

Solution

A homogeneous mixture is a mixture in which compostion remains uniform throughout the mixture.
Mixture of sand and water, iron filings and sand, silver chloride and water are all heterogeneous mixtures.
Only ethanol and water is a homogeneous mixture because ethanol is soluble in water and it is not possible to distinguish between the two.
Hence, option $$D$$ is correct.
Question 8
1 / -0

Gelatin protects :

A
Gold sol

B
$${ As }_{ 2 }{ S }_{ 3 }$$ sol

C
$$Fe\left( OH \right) _{ 3 }sol$$

D
All of these
Question 9
1 / -0

$$K_{sp}$$ of $$ { Mg }(OH)_{ 2 }$$ is $$4.0\times { 10 }^{ -12 }$$, the number of moles of $$ { Mg }^{ 2+ }$$ ions in one litre of its salurated solution in $$0.1 M\ NaOH $$ is:

A
$$4.0\times { 10 }^{ -10 }$$

B
$$1.0\times { 10 }^{ -4 }$$

C
$$2.0\times { 10 }^{ -6 }$$

D
$$8.10\times { 10 }^{ -6 }$$

Solution
Question 10
1 / -0

The amount of electrolytes required coagulate a given amount of AgI colloidal solution (-ve charge) will be in the order

A
$$Na{ NO }_{ 3 }>A{ l}_{ 2 }(N{ O })_{ 3 }>Ba(N{ O }_{ 3 }{ ) }_{ 2 }$$

B
$$A{ 1 }_{ 2 }(N{ O })_{ 3 }>Ba(N{ O }_{ 3 }{ ) }_{ 2 }>NaN{ O }_{ 3 }$$

C
$$A{ 1 }_{ 2 }(N{ O })_{ 3 }>NaN{ O }_{ 3 }>Ba(N{ O }_{ 3 }{ ) }_{ 2 }$$

D
$$NaN{ O }_{ 3 }>Ba(N{ O }_{ 3 }{ ) }_{ 2 }>A{ 1 }_{ 2 }(N{ O }_{ 3 }{ ) }_{ 3 }$$

Solution