Atoms and Molecules Test

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Atoms and Molecules Test - 17

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Weekly Quiz Competition

Question 1

1 / -0

Use the following information to answer the next question.

Galactose (C₆H₁₂O₆), a form of sugar, is commonly found in dairy products, sugar beets, and gums. It is also synthesized by the body, where it forms a part of glycolipids and glycoproteins in several tissues. Galactose is less sweet than glucose, and is not very soluble in water.

The number of atoms present in 0.8 g of galactose is

2.670 × 10²¹

3.204 × 10²²

6.432 × 10²¹

6.023 × 10²³

Solution

The molar mass of galactose = {(12 × 6) + (12 × 1) + (6 × 16)} = 180 g moL⁻¹

i.e., 180 g of galactose contains 6.022 × 10²³ molecules

0.8 g of galactose will contain {(6.022 × 10²³)/180} × 0.8 = 0.268 × 10²² molecules

One molecule of galactose contains 24 atoms.

2.67 × 10²¹ molecules of galactose = 24 × (2.68 × 10²¹)

= 6.432 × 10²¹atoms

The correct answer is C.

Question 2
1 / -0

Which of the following compounds contains the maximum number of atoms per molecule?

A
CH₄

B
NaOH

C
H₂SO₄

D
NaHCO₃

Solution

Compound

Number of Atoms Per Molecule

CH₄

5

NaOH

3

H₂SO₄

7

NaHCO₃

6

The correct answer is C.

Question 3

1 / -0

Use the following information to answer the next question.

A glass jar contains one molecule each of rock salt (NaCl), washing soda (Na₂CO₃), sodium sulfate (Na₂SO₄), and chalk (CaCO₃).

The maximum number of atoms is present in

rock salt

sodium sulfate

washing Soda

chalk

Solution

Substance	Number of Atoms Per Molecule
Rock salt	2
Sodium sulfate	7
Washing Soda	6
Chalk	5

The correct answer is B.

Question 4
1 / -0

Four boxes A, B, C, and D contain the number of atoms which are present in one formula unit each of sugar (C₁₂H₂₂O₁₁), carbon dioxide (CO₂), sodium carbonate (Na₂CO₃), and glucose (C₆H₁₂O₆) respectively. If the boxes are arranged in the increasing order of the number of atoms they contain, then the correct order will be

A
A < B < D < C

B
B < D < C < A

C
B < C < D < A

D
C < D < B < A

Solution

Sugar contains 12C, 22H, 11O. Total 45 atoms. CO₂contains 3 atoms. Sodium carbonate contains 6 atoms and glucose containe 24 atoms. Therefore the number of atom in the boxes A, B, C, and D are 45, 3, 6, and 24 respectively.

Hence, the correct answer is option C.
Question 5
1 / -0

The elements present in magnesium nitrate are

A
Mg, N, and H

B
Mn, N, and H

C
Mg, N, and O

D
Mn, N, and O

Solution

The molecular formula of magnesium nitrate is Mg (NO₃)₂. Thus, the elements present in it are Mg, N, and O.

The correct answer is C.

Why alternatives A, B and D are wrong:

The elements present in magnesium nitrate are Mg, N, and O. Hence, alternatives A, B, and D are incorrect.
Question 6
1 / -0

Which of the following gases contains the maximum number of atoms per molecule?

A
Oxygen

B
Argon

C
Neon

D
Ozone

Solution

Gas

Number of Atoms Per Molecule

Oxygen

2

Argon

1

Neon

1

Ozone

3

The correct answer is D.
Question 7
1 / -0

What is the molecular formula of table sugar?

A
C₆H₁₂O₆

B
C₁₂H₂₂O₁₁

C
C₆H₁₂N₃O₃

D
C₁₂H₂₂N₆O₃

Solution

Table sugar i.e., sucrose is represented as C₁₂H₂₂O₁₁.

The correct answer is B.

Why alternative A is wrong:

C₆H₁₂O₆ is the molecular formula of glucose. Hence, this alternative is incorrect.

Why alternative C is wrong:

C₆H₁₂N₃O₃ is not the molecular formula of sugar as sugar does not contain nitrogen. Hence, this alternative is incorrect.

Why alternative D is wrong:

C₁₂H₂₂N₆O₃ is not the molecular formula of sugar as sugar does not contain nitrogen. Hence, this alternative is incorrect.
Question 8
1 / -0

The elements that constitute sugar are

A
C, H, and O

B
H, C, and N

C
O, N, and C

D
N, H, and O

Solution

Sugar is a compound whose molecular formula is C₁₂H₂₂O₁₁. Therefore, the elements that constitute it are C, H, and O.

The correct answer is A.

Why alternatives B, C and D are wrong:

The elements that constitute sugar are C, H, and O. Hence, alternatives B, C, and D are incorrect.
Question 9
1 / -0

The number of moles present in one atom of an element is

A
1.66 × 10⁻²⁴

B
1

C
10²³

D
6.023 × 10²³

Solution

1 mole of an element contains 6.023 × 10²³ atoms of an element.

1 atom of an element = {1/(6.023 × 10²³)} = 1.66 × 10⁻²⁴ mol

The correct answer is A.

Question 10

1 / -0

Use the following information to answer the next question.

Calciumcarbonate (CaCO₃), also known as calcite, is commonly used as a calcium supplement or as an antacid. Apart from being an important component of seashells, it is actively used in agricultural lime.

The number of mole present in 38 g of calcite is

0.19

0.38

0.57

0.76 Solution

The molecular mass of CaCO₃= {40 + 12 + (16 × 3)}= 100 g

1 mole of calcium carbonate will weigh 100 g.

38 g of CaCO₃will contain 0.38 mole.

The correct answer is B.

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Compound	Number of Atoms Per Molecule
CH₄	5
NaOH	3
H₂SO₄	7
NaHCO₃	6

Gas	Number of Atoms Per Molecule
Oxygen	2
Argon	1
Neon	1
Ozone	3

Atoms and Molecules Test - 17

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Atoms and Molecules Test - 17

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Question 1

2.670 × 1021

3.204 × 1022

6.432 × 1021

6.023 × 1023

Solution

Question 2

CH4

NaOH

H2SO4

NaHCO3

Solution

Question 3

rock salt

sodium sulfate

washing Soda

chalk

Solution

Question 4

A < B < D < C

B < D < C < A

B < C < D < A

C < D < B < A

Solution

Question 5

Mg, N, and H

Mn, N, and H

Mg, N, and O

Mn, N, and O

Solution

Question 6

Oxygen

Argon

Neon

Ozone

Solution

Question 7

C6H12O6

C12H22O11

C6H12N3O3

C12H22N6O3

Solution

Question 8

C, H, and O

H, C, and N

O, N, and C

N, H, and O

Solution

Question 9

1.66 × 10−24

1

1023

6.023 × 1023

Solution

Question 10

0.19

0.38

0.57

0.76

Solution

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2.670 × 10²¹

3.204 × 10²²

6.432 × 10²¹

6.023 × 10²³

CH₄

H₂SO₄

NaHCO₃

C₆H₁₂O₆

C₁₂H₂₂O₁₁

C₆H₁₂N₃O₃

C₁₂H₂₂N₆O₃

1.66 × 10⁻²⁴

10²³

6.023 × 10²³