Atoms and Molecules Test

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Atoms and Molecules Test - 21

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Weekly Quiz Competition

Question 1
1 / -0

The chemical properties of an atom depend upon:

A
valency

B
atomic number

C
number of isotopes

D
atomic weight

Solution

The chemical properties of an atom depend upon the atomic number. From the atomic number, we can get valence electrons that determines the chemical properties of it.
Question 2
1 / -0

The mass number of sulfur atom is:

(Given: Atomic number = 16 and number of neutrons = 16)

A
18

B
32

C
24

D
16

Solution

Atomic number = number of protons = $$16$$

Mass number = Number of protons + number of neutrons

So the mass number of sulfur = $$32$$
Question 3
1 / -0

Mass of atom expressed in atomic mass unit is :

A
Atomic mass

B
Molecular mass

C
Atomic number

D
None of the above

Solution

The mass of an atom expressed in amu is known as atomic mass. atomic mass unit defined as a unit of mass used to express atomic and molecular weights, equal to one-twelfth of the mass of an atom of carbon-12.
Question 4
1 / -0

What is the atomic mass (u) of calcium?

A
10

B
20

C
30

D
40

Solution

Atomic mass (u) of Calcium is 40 u.

Hence, the correct option is $$\text{D}$$
Question 5
1 / -0

One a.m.u is defined as mass of :

A
$$\frac{1}{16}^{th}$$ mass of one oxygen atom

B
$$\frac{1}{14}^{th}$$ mass of one atom of nitrogen

C
$$\frac{1}{12}^{th}$$ mass of one carbon-12 atom

D
None of above

Solution

One a.m.u. is defined as mass of $$\frac1{12}^{th}$$ the mass of one carbon-12 atom.
Question 6
1 / -0

What is the atomic mass (u) of sodium?

A
22

B
23

C
23.5

D
24

Solution

Sodium is a chemical element with the symbol $$Na$$ and atomic number $$11$$. Atomic mass (u) of sodium = $$23u$$.
It is a soft, silvery-white, highly reactive metal.
Question 7
1 / -0

The sum of mass of all the atoms in a molecule is known as :

A
molecular mass

B
mass number

C
atomic weight

D
None of above

Solution

The sum of the atomic masses of all the atoms present in a molecule is known as molecular mass. It is therefore a relative mass of a molecule expressed in atomic mass units (u).
For example- molecular mass of carbon dioxide is 44 u and it is calculated as below
The atomic mass of carbon = $$12\ u$$ and
The atomic mass of oxygen = $$16\ u$$
$$\therefore$$ molecular mass of $$CO_2 = (1\times atomic\ mass\ of\ C) + (2\times atomic\ mass\ of\ O)$$
Molecular mass of $$CO_2 = (1\times \ 12) + (2\times 16) = 44\ u$$
The correct option is A.
Question 8
1 / -0

The unit, mole, was accepted in the year?

A
1962

B
1965

C
1967

D
1969

Solution

The term 'mole' was introduced around 1896 by Wilhelm Ostwald. But, it was accepted as a unit to report the large number of atoms and molecules in 1967.
Question 9
1 / -0

The symbol of potassium is taken from :

A
kalium

B
kappa

C
kamenikeia

D
kassandrenos

Solution

Many elements have their symbols derived from their Greek or Latin names and, potassium is one such element. The symbol of potassium is taken from the Greek letter kalium. Hence option A is correct.
Question 10
1 / -0

The cation in $$CaCl_2$$ is:

A
$$Ca^{+}$$

B
$$Cl^{2-}$$

C
$$Ca^{2+}$$

D
$$Cl^{2+}$$

Solution

$$CaCl_2$$ is made up of $$Ca^{2+}$$ and $$2Cl^-$$.
A cation contains is a positively charged ion, so the cation in $$CaCl_2$$ is $$Ca^{2+}$$

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Atoms and Molecules Test - 21

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Atoms and Molecules Test - 21

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Question 1

valency

atomic number

number of isotopes

atomic weight

Solution

Question 2

18

32

24

16

Solution

Question 3

Atomic mass

Molecular mass

Atomic number

None of the above

Solution

Question 4

10

20

30

40

Solution

Question 5

$$\frac{1}{16}^{th}$$ mass of one oxygen atom

$$\frac{1}{14}^{th}$$ mass of one atom of nitrogen

$$\frac{1}{12}^{th}$$ mass of one carbon-12 atom

None of above

Solution

Question 6

22

23

23.5

24

Solution

Question 7

molecular mass

mass number

atomic weight

None of above

Solution

Question 8

1962

1965

1967

1969

Solution

Question 9

kalium

kappa

kamenikeia

kassandrenos

Solution

Question 10

$$Ca^{+}$$

$$Cl^{2-}$$

$$Ca^{2+}$$

$$Cl^{2+}$$

Solution

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