Atoms and Molecules Test

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Atoms and Molecules Test - 41

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Weekly Quiz Competition

Question 1
1 / -0

Calculate the formula unit mass (u) of $$\displaystyle { Na }_{ 2 }O$$ .
$$Atomic \ mass \ of \ Na = 23 \ u, O=16 \ u$$

A
$$60 $$

B
$$ 62 $$

C
$$ 61 $$

D
$$ 59 $$

Solution

Formula unit mass (u) of $$\displaystyle { Na }_{ 2 }O$$ = 2 x atomic mass of sodium + atomic mass of oxygen
$$= 2 \times 23 + 16 = 62 \ u $$
Question 2
1 / -0

Calculate the formula unit mass (u) of $$\displaystyle NaCl$$:
$$ [Na=23u, Cl=35.5u]$$

A
$$54.5 u$$

B
$$55.5 u$$

C
$$56.5 u$$

D
$$58.5 u$$

Solution

Formula unit mass of $$\displaystyle NaCl$$ = atomic mass of $$Na$$ + atomic mass of $$ Cl$$
$$= 23u + 35.5u = 58.5u$$
Question 3
1 / -0

Who stated the law of constant proportion?

A
Archimedes

B
Dalton

C
Proust

D
Antony Lavoisier

Solution

The law of constant proportion was given by Joseph L. Proust.
Option C is correct.
Question 4
1 / -0

When $$3\ g$$ of carbon is burnt in $$8\ g$$ of oxygen, $$11 g$$ of carbon dioxide is produced. What mass of carbon dioxide will be formed when $$3\ g$$ of carbon is burnt in $$50\ g$$ oxygen?

A
$$12\ g$$

B
$$13\ g$$

C
$$11\ g$$

D
$$10\ g$$

Solution

This is governed by the law of definite proportion. Carbon and oxygen combine in $$3:8$$ ratio. So $$11 \ g$$ of carbon dioxide is formed.

Hence, in the latter case too, only $$8 \ g$$ of $$O_2$$ will be reacted with 3g of carbon (because carbon is the limiting reagent here ) to form 11g of $$CO_2$$ and $$42 \ g$$ of oxygen will remain unreacted.

Hence, the correct option is C.
Question 5
1 / -0

Which of the following symbol of elements is not taken from Latin names?

A
$$K$$

B
$$Na$$

C
$$Cu$$

D
$$Zn$$

Solution

$$K, Na, Cu$$ is derived from Latin names namely Kalium, Natrium, and Cuprum.
The symbol of Zinc is not taken from Latin names.
So the correct answer is $$D$$.
Question 6
1 / -0

In ammonia, nitrogen and hydrogen always combine in $$14:3$$ ratio by mass. This is in agreement with :

A
Law of conservation of mass

B
Law of definite proportion

C
Law of multiple proportion

D
Law of combining volume

Solution

The Law of definite proportion states that elements always combine in the definite ratio by mass. So it is in agreement with the law of definite proportion.
Question 7
1 / -0

Which is not the method used for creating the symbols of elements?

A
Some symbols of elements were taken from names of elements in Latin, Greek or German

B
Symbols of some elements were taken from names of places

C
Some symbols of elements were taken from specific colours

D
Symbols of some elements were taken from the letters of elements written in reverse order

Solution

Some symbols have been derived from Greek, Latin, or German names of elements. For example, sodium (Na, from natrium), gold (Au, from aurum).

Some symbols have been derived from place names. E.g. francium (Fr).

Some symbol names have also been derived from colours of the elements. E.g. chlorine (Cl, from chloros, meaning yellow green).

No symbol is taken from letters of elements in reverse order.
Question 8
1 / -0

The cation and anion present in $$HNO_3$$ are :

A
$$H^+, NO_3^-$$

B
$$H^-, NO_3^+$$

C
$$H^+, NO_3^+$$

D
$$H^-, NO_3^-$$

Solution

The cation and anion present in $$HNO_3$$ are $$H^+$$ (Hydrogen ion) and $$NO_3^-$$ (Nitrate ion) respectively.
Question 9
1 / -0

Which of the following statement is true about mole?

A
It is used to calculate number of particles.

B
1 mole is equal to $$6.023\times10^{23}$$ particles.

C
It is the chemist's counting unit

D
All of the above

Solution

Mole is used to find number of particles. 1 mole is equal to Avogadro number of atoms/molecules. It is chemist's counting unit.
Question 10
1 / -0

Which Indian philosopher was the first one to postulate the idea of matter divisibility around 500 B.C?

A
Democritus

B
Leucippus

C
Pakudha Katyayama

D
Maharishi Kanad

Solution

The idea of divisibility of matter was considered long back in India, around 500 BC. An Indian philosopher Maharishi Kanad, postulated that if we go on dividing matter (apart), we shall get smaller and smaller particles.

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Atoms and Molecules Test - 41

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Atoms and Molecules Test - 41

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Question 1

$$60 $$

$$ 62 $$

$$ 61 $$

$$ 59 $$

Solution

Question 2

$$54.5 u$$

$$55.5 u$$

$$56.5 u$$

$$58.5 u$$

Solution

Question 3

Archimedes

Dalton

Proust

Antony Lavoisier

Solution

Question 4

$$12\ g$$

$$13\ g$$

$$11\ g$$

$$10\ g$$

Solution

Question 5

$$K$$

$$Na$$

$$Cu$$

$$Zn$$

Solution

Question 6

Law of conservation of mass

Law of definite proportion

Law of multiple proportion

Law of combining volume

Solution

Question 7

Some symbols of elements were taken from names of elements in Latin, Greek or German

Symbols of some elements were taken from names of places

Some symbols of elements were taken from specific colours

Symbols of some elements were taken from the letters of elements written in reverse order

Solution

Question 8

$$H^+, NO_3^-$$

$$H^-, NO_3^+$$

$$H^+, NO_3^+$$

$$H^-, NO_3^-$$

Solution

Question 9

It is used to calculate number of particles.

1 mole is equal to $$6.023\times10^{23}$$ particles.

It is the chemist's counting unit

All of the above

Solution

Question 10

Democritus

Leucippus

Pakudha Katyayama

Maharishi Kanad

Solution

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