Atoms and Molecules Test

Result

Atoms and Molecules Test - 42

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Weekly Quiz Competition

Question 1
1 / -0

What is the old symbol for mercury?

A

B

C

D
None of the above

Solution

The old symbol of mercury is above :
Question 2
1 / -0

One gross : One mole : : 144 : ?

A
$$6.023\times10^{23}$$

B
$$6\times10^{20}$$

C
$$10^{23}$$

D
None of the above

Solution

A gross refers to a group of 144 items.
Similarly, there are $$6.023\times 10^{23}$$ particles in one mole of any substance.
So, option A is correct.
Question 3
1 / -0

A positively charged ion is called :

A
molecule

B
atom

C
anion

D
cation

Solution

A positively charged ion, that gets attracted towards the cathode during the electrolysis of salts, is known, as a cation. Eg. $$Na^+, H^+, Ca^{2+}$$

Hence the correct option is D.
Question 4
1 / -0

The symbol of silver proposed by Dalton is

A

B

C

D

Solution

The symbol of silver proposed by Dalton is shown above.
Option $$D$$ is correct.
Question 5
1 / -0

What is the old symbol of copper?

A

B

C

D

Solution

It is the old symbol of copper.
Question 6
1 / -0

The anion in $$CaCl_2$$ is :

A
$$Ca^{2-}$$

B
$$Cl^-$$

C
$$Ca^{2+}$$

D
$$Cl^+$$

Solution

$$CaCl_2$$ is made up of two ions, The cation is $$Ca^{2+}$$ and the anion is $$Cl^-$$
Question 7
1 / -0

Avogadro number is the number of atoms present in exactly:

A
$$16\ g$$ of oxygen

B
$$12\ g$$ of carbon

C
$$2\ g$$ of hydrogen

D
None of the above

Solution

Avogadro number is the number of atoms in exactly 12 g of carbon-12. It is equal to $$6.022 \times 10^{23}$$.
Question 8
1 / -0

Which of the following configuration is most likely to form an anion?

A
$$2,\,6$$

B
$$2,\,8,\,1$$

C
$$2,\,1$$

D
$$2,\,2$$

Solution

The electronic configuration of $$2,\,6$$ will accept two electrons to become an anion or negatively charged ion.
For all the other configurations, losing electrons would lead to a more stable state and would form cations instead.
So, option A is correct.
Question 9
1 / -0

Atom : .................... : : Electrons : Negatively charged

A
No charge

B
Positively charged

C
Negatively charged

D
None of the above

Solution

Electrons are negatively charged. The analogy is being made based on the charges present on the given entities. An atom has no charge.
So, the correct option is A.
Question 10
1 / -0

Which of the following configuration will form a cation?

A
$$2,\,8,\,7$$

B
$$2,\,7$$

C
$$2,\,8,\,8$$

D
$$2,\,8,\,2$$

Solution

The electronic configuration of $$2,\,8,\,2$$ will lose two electrons to become positively charged ion i.e cation.