Diversity in Living Organisms Test

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Diversity in Living Organisms Test - 88

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Weekly Quiz Competition

Question 1
1 / -0

In which of the following, segmentation in the body is first observed?

A
Aschelminthes

B
Arthropoda

C
Annelida

D
Platyhelminthes

Solution

Segmentation is division or differentiation of the body into distinct portions called segments. It is first observed in Phylum Annelida.
Question 2
1 / -0

Given below are three statements regarding Aschelminthes.
(i) They are bilaterally symmetrical and triploblastic.
(ii) They are dioecious.
(iii) All are plant or animal parasites.
Select the option that has both the correct statements.

A
(i) and (ii)

B
(i) and (iii)

C
(ii) and (iii)

D
None of these

Solution

Aschelminthes are bilaterally symmetrical, triploblastic and dioecious animals. They may be free-living, aquatic and terrestrial or parasitic on plants and animals.
Question 3
1 / -0

Which of the following statements are incorrect?
(i) Parapodia are lateral appendages in arthropods used for swimming.
(ii) RaduIa in molluscs are structures involved in excretion.
(iii) Aschelminthes are dioecious.
(iv) Echinoderm adults show radial symmetry.
(v) Ctenophorans are diploblastic.

A
(i) and (ii)

B
(i) and (iii)

C
(i), (iv) and (ii)

D
(iii) and (v)

Solution

Parapodia are present in some annelid worms.These area pair of flattened flesh lobes bearing numerous bristles. Radula (rasping organ) in molluscs is a structure involved in feeding.
Question 4
1 / -0

Which of the following vertebrates have 4 chambered heart but no sinus venosus, they also have metanephric kidneys, Heterocoelous vertebrae and Auditory openings.

A
Rana, Chameleon, columba

B
Crocodylus and Alligator

C
Struthio, Aptenodytes and Neophron

D
Ornithorhynchus, Pteropus and Delphinus

Solution

Crocodiles and alligators have 4-chambered heart but no sinus venosus, they also have metanephric kidneys, heterocoelous cervical vertebrae and auditory openings.
So,, the correct answer is 'Crocodylus and Alligator'.

Question 5

1 / -0

Study the following table carefully and select the correct option for 1, 2, 3 and 4.

Characters	Monera	Protista	Fungi	Plantae	Animalia
Cell type	1	Eukaryotic	Eukaryotic	Eukaryotic	Eukaryotic
Cell wall	2	Present in some	Present	Present	Absent
Nuclear membrane	Absent	Present	Present	Present	3
Body organisation	Cellular	Cellular	4	Tissue/ organ	Tissue/organ/ organ system

1 - Prokaryotic, 2 - Absent, 3 - Absent, 4 - Unicellular

1 - Prokaryotic, 2 - Present, 3 - Present, 4 - Multicellular

1 - Eukaryotic, 2 - Present, 3 - Present, 4 - Multicellular

1 - Eukaryotic, 2 - Absent, 3 - Absent, 4 - Unicellular

Solution

1) Kingdom Monera has prokaryotic cells.

2) Monera (bacteria) shows the presence of a cell wall.

3) All animal cells have a nuclear membrane around the nucleus.

4) Kingdom fungi have multicellular members included in it.

So, the correct answer is option B- "1-Prokaryotic, 2-Present, 3- Present, 4-Multicellular".

Question 6
1 / -0

Which one of the following statements about certain given animals is correct?

A
Roundworms are pseudocoelomates

B
Molluscs are acoelomates

C
Annelids are pseudocoelomates

D
Flatworms are coelomates

Solution

A body cavity can mean any internal space, or a series of spaces present inside body, whereas coelom or true body cavity generally refers to a large fluid-filled space (cavity) lying between the outer body wall and the inner digestive tube. In acoelomates, no body cavity or coelom is present. Embryonic mesoderm remains as a solid layer, space between endoderm (gut wall) and ectoderm (body wall) is filled with mesenchyme and muscle fibres. In pseudocoelomates, body space is a pseudocoelom or false coelom. In coelomates or eucoelomates, body space is a true coelom, enclosed by mesoderm on both sides.
Roundworms are pseudocoelomates; Molluscs and annelids are coelomates while flatworms are acoelomates.
So, the correct answer is A.
Question 7
1 / -0

Identify the figures A, B, and C given above and select the correct option.

A
A - Locust, B - Scorpion, C - Prawn

B
A - Locust, B - Prawn, C - Scorpion

C
A - Scorpion, B - Locust, C - Prawn

D
A - Butterfly, B - Scorpion, C - Prawn

Solution

A - Locust
B - Scorpion
C - Prawn
They are all arthropods.
So, the correct answer is A.
Question 8
1 / -0

You have discovered an animal having characters like bilateral symmetry, chitinous exoskeleton, head, thorax and abdomen as body parts, and jointed appendages.
You should place the animal under:

A
Mollusca

B
Arthropoda

C
Annelida

D
Echinodermata
Solution
Correct Option: B

Explanation:
- Arthropoda phylum of animals’ organization possesses chitinous exoskeleton as their main supporting structure which sheds off during growth.
- They have segmented bodies including the head, thorax, and abdomen.
- Also, they have jointed appendages and are classified on the basis of a number of legs and segments.
- They have bilateral symmetry and possess a dorsal nervous system which can be observed in butterflies, locusts, scorpions, etc.
Hence, the correct option is Arthropoda.
Question 9
1 / -0

Which of the following is incorrectly matched?

A
Spiny tailed lizard - Uromastyx hardwickii

B
Garden lizard - Hemidactylus flaviviridis

C
Gila monster - Heloderma

D
Monitor lizard - Varanus
Solution
A. Correct option B
B. Explanation for correct option -
Scientific name for garden lizard is Calotes versicolor.
Hemidactylus flaviviridis is yellow-bellied house gecko.
So the correct option is B.

Question 10

1 / -0

Match column I with column II and select the correct option from the given codes.

	Column I		Column II
A.	Amphibia	(i)	Air bladder
B.	Mammals	(ii)	Cartilaginous notochord
C.	Chondrichthyes	(iii)	Mammary glands
D.	Osteichthyes	(iv)	Pneumatic bones
E.	Cyclostomata	(v)	Dual habitat
F.	Aves	(vi)	Sucking and circular mouth without jaws

A-(i), B-(iii), C-(iv), D-(v), E-(ii), F-(vi)

A-(ii), B-(v), C-(iv), D-(vi), E-(iii), F-(i)

A-(v), B-(iii), C-(ii), D-(i), E-(vi), F-(iv)

A-(vi), B-(ii), C-(iii), D-(i), E-(iv), F-(v)

Solution

Amphibian lives on both aquatic and terrestrial habitat. Thus, they have dual habitats.
Mammals have a characteristic feature of mammary glands to feed their young ones.
Chondrichthyes (cartilaginous fishes) have a cartilaginous notochord.
Osteichthyes are bony fish that have a sac-like outgrowth, the swim bladder (air bladder) arising from the dorsal wall of the esophagus which is an air-filled organ used to maintain balance and to swim up and down.
Cyclostomata have sucking and circular mouth without jaws.
Aves have pneumatic bones. These bones are long and hollow with air cavities to reduce weight.
So, the correct answer is option C.

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Diversity in Living Organisms Test - 88

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Diversity in Living Organisms Test - 88

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SHARING IS CARING

Question 1

Aschelminthes

Arthropoda

Annelida

Platyhelminthes

Solution

Question 2

(i) and (ii)

(i) and (iii)

(ii) and (iii)

None of these

Solution

Question 3

(i) and (ii)

(i) and (iii)

(i), (iv) and (ii)

(iii) and (v)

Solution

Question 4

Rana, Chameleon, columba

Crocodylus and Alligator

Struthio, Aptenodytes and Neophron

Ornithorhynchus, Pteropus and Delphinus

Solution

Question 5

1 - Prokaryotic, 2 - Absent, 3 - Absent, 4 - Unicellular

1 - Prokaryotic, 2 - Present, 3 - Present, 4 - Multicellular

1 - Eukaryotic, 2 - Present, 3 - Present, 4 - Multicellular

1 - Eukaryotic, 2 - Absent, 3 - Absent, 4 - Unicellular

Solution

Question 6

Roundworms are pseudocoelomates

Molluscs are acoelomates

Annelids are pseudocoelomates

Flatworms are coelomates

Solution

Question 7

A - Locust, B - Scorpion, C - Prawn

A - Locust, B - Prawn, C - Scorpion

A - Scorpion, B - Locust, C - Prawn

A - Butterfly, B - Scorpion, C - Prawn

Solution

Question 8

Mollusca

Arthropoda

Annelida

Echinodermata

Solution

Question 9

Spiny tailed lizard - Uromastyx hardwickii

Garden lizard - Hemidactylus flaviviridis

Gila monster - Heloderma

Monitor lizard - Varanus

Solution

Question 10

A-(i), B-(iii), C-(iv), D-(v), E-(ii), F-(vi)

A-(ii), B-(v), C-(iv), D-(vi), E-(iii), F-(i)

A-(v), B-(iii), C-(ii), D-(i), E-(vi), F-(iv)

A-(vi), B-(ii), C-(iii), D-(i), E-(iv), F-(v)

Solution

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