Motion Test

Result

Motion Test - 46

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Weekly Quiz Competition

Question 1
1 / -0

According to the following graph, what happens to the distance covered by the body from 0 -10 minutes?

A
It goes on increasing

B
It goes on decreasing

C
It first increases and then decreases

D
It first decreases and then increases

Solution

We know that distance traveled by an object is the area under it speed time graph.
Now, in this case, as the area under the speed-time graph is increasing from 0-10 minutes. So, the distance will keep on increasing from 0-10 minutes.

Hence, correct answer is option $$A$$
Question 2
1 / -0

The odometer of a car reads $$57321.0\ km$$ when the clock shows the time 8:30 AM. The distance moved by car if, at 8:50 AM, the odometer reading has changed to $$57336.0\ km$$ and also the speed will be:

A
$$15\ km ,\ 45\, km/h$$

B
$$10km ,$$ $$45\, km/h$$

C
$$15km ,$$ $$55\, km/h$$

D
$$20km ,$$ $$45\, km/h$$

Solution

Time from $$8.30$$ $$AM$$ to $$8.50$$ $$AM$$ = $$20$$ $$min$$
$$20min=(20/60)h=(1/3)h$$
(a) Distance covered = Second reading - First reading = $$57336.0$$ $$km$$ - $$57321.0$$ $$km$$ = $$15$$ $$km$$
(b) $$Speed=\dfrac{Distance}{Time}$$=$$\dfrac{15}{1/3}$$=$$45km/h$$
Question 3
1 / -0

Which of the following is NOT matched correctly?

A
Speedometer: Speed

B
Odometer : Odour

C
Anemometer : Wind speed

D
Stopwatch : Time

Solution

Odometer indicates the distance travelled by the vehicle.
Question 4
1 / -0

The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 m/s. The driver sees in his rear view mirror the image of a truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be ________________.

A
1 m/s

B
2 m/s

C
4 m/s

D
8 m/s

Solution

Since the object and its image always remain at the same distance from the mirror, therefore, when the car is reversed at a speed of 2 m/s, its image also appears to move towards the mirror at the same speed, i.e., 2 m/s. Hence, the speed at which the image of the truck will appear to approach the car will be 2 m/s + 2 m/s = 4 m/s.
Question 5
1 / -0

A 1,000 kg vehicle moving with a speed of $$20\ ms^{-1}$$ is brought to rest in a distance of 50 m. Find the acceleration.

A
$$-4 ms^{-2}$$

B
$$4 ms^{-2}$$

C
$$-8 ms^{-2}$$

D
$$8 ms^{-2}$$

Solution

$$v^2-u^2=2as$$
$$a=\dfrac {v^2-u2}{2s}=\dfrac {0-(20)^2}{2(50)} = -4\ ms^{-2}$$
Question 6
1 / -0

A $$2\ kg$$ object has an initial velocity of $$u=10\ ms^{-1}$$. The retardation due to friction is $$2\ ms^{-2}$$. After what time does the object stop?

A
$$5\ s$$

B
$$2\ s$$

C
$$10\ s$$

D
$$8\ s$$

Solution

Given:
Initial velocity,
$$u = 10\ ms^{-1}$$
Final velocity,
$$v = 0\ ms^{-1}$$
Acceleration,
$$a = -2\ ms^{-2}$$

Using first equation of motion:
$$v=u+at$$
$$\Rightarrow 0 = 10 - 2t $$
$$\Rightarrow t=5\ s$$
Question 7
1 / -0

With what speed should a car travel so that it can cover a distance of 5 km in 5 min?

A
1 km/h

B
5 km/h

C
12 km/h

D
60 km/h

Solution

Given,
Distance cover $$d=5\ km$$
Time $$t=5\ min$$ or $$t=5/60\ hr$$
Speed $$v=\dfrac{5}{5/60}=60\ km/hr$$
Option D
Question 8
1 / -0

A man runs $$10 \ km$$ in $$30 \ min.$$ What is his speed?

A
$$5 \ km/h$$

B
$$10 \ km/h$$

C
$$15 \ km/h$$

D
$$20 \ km/h$$

Solution

We know that,
$$Speed = \dfrac{distance}{time}$$
Given:
Distance $$=10 \ km$$
Time $$=30 min= \dfrac{30}{60} \ hr=0.5 \ hr$$
Speed $$=\dfrac{10 \ km}{0.5 \ hr} = 20 \ km/h$$

Option D is the answer.
Question 9
1 / -0

From the displacement-time graph shown here, find the velocity of the body as it moves from B to C.

A
$$0\ ms^{-1}$$

B
$$2\ ms^{-1}$$

C
$$4\ ms^{-1}$$

D
$$8\ ms^{-1}$$

Solution

We know that,
Area under the graph
Displacement during $$6^{th}$$ sec
$$d= 4\times 1 = 4m$$
$$Velocity = \dfrac {Displacement}{Time}$$
$$\Rightarrow v= \dfrac {4}{1}$$
$$\Rightarrow v= 4 ms^{-1}$$
$$\therefore$$ Option (C) is correct.
Question 10
1 / -0

Graph : Distance vs Time

A
Zero Speed

B
Constant Speed

C
Uniformly Increasing Speed

D
Uniformly Decreasing Speed

Solution

Slope of distance-time graph tells speed of object.The given graph has horizontal line so slope is zero.Hence speed of object is zero , that is , object is at rest.