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Motion Test - 50

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Motion Test - 50
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  • Question 1
    1 / -0
    A driver is driving his car along a road as shown in Figure. The driver makes sure that the speed-o-meter reads exactly 40 km/h. What happens to the velocity of the car from P to Q ? 

    Solution
    Since the speed-o-meter of the car reads exactly 40 km/h speed. This means that speed of the car remains constant always. also, from P to Q, the car moves in a straight line i.e. direction of motion of car does not change.  So, velocity of the car, which is speed and direction combined,  from P to Q remains constant.
  • Question 2
    1 / -0
    In Fig. 2.8

    Solution
    From the velocity-time graph, we can say that the velocity of the body is decreasing. Also, up to time M, its velocity is positive and beyond M, its velocity is negative.
    Also, the slope of the velocity-time graph gives the acceleration of the body. Since the slope of the graph is negative and constant. So, the body has constant acceleration in the negative direction. In other words, the body is uniformly retarding.
    Thus, option D is correct.
  • Question 3
    1 / -0
    A body cannot have a
    Solution
    Speed of body is magnitude of velocity. So if velocity is only changing direction then speed is constant.
    But if speed is changing then velocity have to be varying.
    When a body starts moving the incident when t=0 then it have zero velocity but some acceleration is there.
    Object moving with constant velocity has zero acceleration but non zero speed. 
    So only option C is not possible.
  • Question 4
    1 / -0
    Which of the following decreases in motion along a straight line with constant retardation? 
    Solution
    • Option A:
    By first equation of motion,
    $$v=u-at$$
    Since it is retardation, then $$a \rightarrow negative$$
    Let us assume the moving body has some initial speed $$u$$ in $$+x$$ axis.
    So we can see, as time $$t$$ increases, final speed $$v$$ decreases.
    So option A is correct.

    • Option B:
    Acceleration can't decrease because it is given in the question itself that it is constant retardation, i.e, constant acceleration opposite in direction to the speed.

    • Option C:
    Displacement will also keep on increasing towards $$+x$$ axis as long as final speed $$v$$ doesn't become zero.

  • Question 5
    1 / -0
    The slope of a distance-time graph of a moving body gives its
    Solution
    The speed can be determined from the slope of the Distance-time graph.
    Slope = $$=\frac{rise}{run}
               =\frac{distance}{time}$$

  • Question 6
    1 / -0
    A stone tied to a string is whirled in a circle. As it is revolving, the rope suddenly breaks.Then :
    Solution
    When a stone is going around a circular path, the instantaneous velocity of stone is acting as tangent to the circle. When the string breaks, the centripetal force stops to act. Due to inertia, the stone continues to move along the tangent to circular path. So, the stone flies off tangentially to the circular path
  • Question 7
    1 / -0
    Choose the incorrect statement:
    Solution
    Velocity is a quantity that has magnitude as well as direction so it can be negative and positive but the speed is a quantity that does not have any direction but has magnitude, there is no chance of getting negative. so the speed is always positive. so velocity can never be greater than the speed (maximum it can be equal to the speed if it travel in a straight line where direction does not matters )
    Because speed is distance upon time and velocity is displacement upon time 
    and displacement can never be greater than distance so velocity can never be greater than speed.
    Remaining options are true .
    Speedometer reads speed at an instant. Position -time graph for variable speed is a curve because speed (slope of position -time graph) is changing.
    And velocity-time graph for uniform motion will be horizontal line parallel to time-axis as velocity is fixed and does not change with time.
  • Question 8
    1 / -0
    A body whose speed in a particular direction is constant :
    Solution
    Speed with direction is called Velocity.
    A body whose speed in a particular direction is constant means it has a constant speed and it has a particular constant direction . Hence it has a constant velocity in that direction.
  • Question 9
    1 / -0
     A truck running along a straight line increases its speed uniformly from 30 m/s to 60 m/s over a time interval 1-min. The distance travelled during this time interval is 
    Solution
    Here, $$\displaystyle a=\dfrac { v-u }{ t } =\frac { 60-30 }{ 60 } =0.5{ m }/{ { s }^{ 2 } }$$
    and $$\displaystyle s=\dfrac { { v }^{ 2 }-{ u }^{ 2 } }{ 2a } =\dfrac { { \left( 60 \right)  }^{ 2 }-{ \left( 30 \right)  }^{ 2 } }{ 2\times 0.5 } $$
    $$\displaystyle =2700m$$
  • Question 10
    1 / -0
    The SI unit for the resultant velocity is
    Solution
    velocity is given by $$\dfrac{displacement}{time}$$
    SI unit of displacement is meter and that of time is sec.
     so SI unit of velocity is meter/sec.
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