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Motion Test - 7...

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  • Question 1
    1 / -0

    A body falls from rest, its velocity at the end of first second is $$ ( g =  32 \,ft / s^2) $$ 

  • Question 2
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    A body thrown with an initial speed of $$ 96\, ft / sec $$  reaches the ground after $$ ( g = 32 ft / sec^2 )$$

  • Question 3
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    The variation of velocity of a particle with time moving along a straight line is shown in the figure. The distance traveled by the particle in $$4\ s$$ is :

  • Question 4
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    Time taken by an object falling from rest to cover the height of $$ h_1 $$ and $$ h_2 $$ is respectively $$ t_1 $$ and $$ t_2 $$ then the ratio of $$ t_1 $$ to $$ t_2 $$ is 

  • Question 5
    1 / -0

    The horizontal straight line obtained from the distance-time graph is related to which of the following velocity ?

  • Question 6
    1 / -0

    An object moving in upward direction opposite to the gravitational force of earth performs

  • Question 7
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    Four alternatives are given to each of the following incomplete statements/questions, choose the right answer.
    Uniform circular motion is called continuously accelerated motion mainly because 

  • Question 8
    1 / -0

    A lift performs the first part of its ascent with uniform acceleration, $$a$$, and the remaining with uniform retardation, $$2a$$. If, $$t$$, is the time of ascent, the depth of the shaft is

  • Question 9
    1 / -0

    Using the table given below where the values of velocity at the end of t seconds for a body under linear motion are given

    $$V (m\:s^{-1})$$
    0

    6
    12
    24
    30
    36
    42
    $$t (s)$$
    0

    2
    4
    8
    10
    12
    14
    What can be concluded about the motion of the body?

  • Question 10
    1 / -0

    Directions For Questions

    A determined student waited to test the law of gravity himself and jumps off the top of CN Tower in Toronto ($$553\ m$$ high) and falls freely. His initial velocity is zero. A rocketeer arrives at the scene $$5.0\ s$$ later and dives off the top of the tower to save him. The rocketeer leaves the tower with an initial speed $${ v }_{ 0 }$$. In order to catch the student and to prevent injury to him, the rocketeer should catch the student at a sufficiently great height above the ground so that the rocketeer and student slow down and arrive at the ground with zero velocity. The upward acceleration that accomplishes this is provided by the rocketeer's jet pack, which he turns on when he catches the student, before that rocketeer is in free fall. To prevent discomfort to the student, the magnitude of acceleration should not exceed $$5g$$.

    ...view full instructions

    What is the minimum height above the ground at which the rocketeer should catch the student?

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