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Ethyl benzene CANNOT be prepared by ______
Wurtz reaction is used to prepare alkanes with even number of carbon atoms.To prepare ethylbenzene,Wurtz Fittig reaction has to be used.
The hydrocarbon which can react with sodium in liquid ammonia is------------?
Terminal alkynes react with Na in the presence of liquid NH3 to form higher alkynes. The alkyne , CH2CH2C ≡ CH contains acidic H at the end ( ie.the H bonded to C1 of the chain ) . Therefore , it is easily replaced with highly electropositive metals such as Na in liquid ammonia , to form sodium alkylinide ion which can react furher in presence of suitable catalyst to yield higher alkynes / hydrocarbons .
Among the following compounds the one that is most reactive towards electrophilic nitration is
Methyl group is electron donating group, hence it increases the electron density in benzene ring thereby increasing the reactivity of the ring towards electrophilic substitution.
Presence of a nitro group in a benzene ring
This is because the Nitro is electron withdrawing group,it pulls the electron density from the ring towards itself thereby decreasing the electron density in the ring and deactivating the ring towards attack by the electrophile.
Arrange the following hydrogen halides in order of their decreasing reactivity with propene.
As we move from Cl to I,the atomic size increases,bond length increases,bond strength decreases,hence it becomes easier to release halogen and hence the order.I- is the a better leaving group.
Which branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?
(CH3)3CCH3 + HX(X = Cl,Br,I) ------------> (CH3)3CCH2X Hence a monosubstituted derivative is formed.
n-propyl bromide when treated with alcoholic KOH produces ........... ?
n- bromide when when treated with alcoholic KOH produces propene as shown below,
Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of
The presence of double bond on terminal carbon will give formaldehyde as one of the products.
The non-aromatic compound among the following is
The compound B does not satisfy the (4n+2)pi electron rule and is therefore not an aromatic compound.
The general formula of a cycloalkane with one benzene ring is
Cycloalkane wth one benzene ring has a formula C6H12∴ The formula becomes= CnH2n
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