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Structure of Atom Test - 4

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Structure of Atom Test - 4
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  • Question 1
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    in the Thomson Model of Atom

    Solution
    • J. J. Thomson, who discovered the electron in 1897, proposed the plum pudding model of the atom in 1904 before the discovery of the atomic nucleus in order to include the electron in the atomic model.
    • In Thomson's model, the atom is composed of electrons surrounded by a soup of positive charge to balance the electrons' negative charges, like negatively charged "plums" surrounded by positively charged "pudding".
    • The 1904 Thomson model was disproved by Hans Geiger's and Ernest Marsden's 1909 gold foil experiment.
  • Question 2
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    Photoelectric effect established that light

    Solution

    The emission of free electrons from a metal surface when light is shone on it is called the photoemission or the photoelectric effect. This effect led to the conclusion that light is made up of packets or quantum of energy. Einstein already associated the light quantum with momentum. This strongly supported the particle nature of light and these particles were named photons. Thus, the wave-particle duality of light came into picture. Einstein won the Nobel Prize for Physics not for his work on relativity, but for explaining the photoelectric effect.

  • Question 3
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    Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers, l = 1 and 2 are, respectively

    Solution

    Azimuthal quantum number l = 1 is for p and l = 2 is for d

    Now Cr has configuration.
    1s2,2s2,2p6,3s2,3p6,3d5,4s1

    Hence there are 12, p-electrons and 5, d-electrons

  • Question 4
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    The de Broglie wavelength ratio of two electron waves is 1 : 3. The ratio of kinetic energies of electrons will be:
  • Question 5
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    Correct expression for mass number A is

    Solution

    Mass number. The mass number (symbol A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus.

    mass No. = no. of protons + no. of neutrons.

  • Question 6
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    Mg2+ is isoelectronic with

    Solution

    Isoelectronic species refers to the elements that have the same number of electrons.
    Mg2+ is a 10 electron species (1s2,2s2,2p6).Its configuration is like that of Ne.
    Thus it is isoelectronic with any element having 10e- or we can say 8e- in its valence shell.
    Atomic number of Sodium (Na) is 11 after loosing one electron it became Na+ and have 10 electron.
    Thus Mg2+ is isoelectronic with Na+.

  • Question 7
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    If x is the radius of the first orbit of hydrogen atom, then the de Broglie wavelength of the third orbit is:
  • Question 8
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    Rutherford’s α–particle scattering experiment supported the discovery of

    Solution

    Rutherford's model of an atom: Ernest Rutherford was interested in knowing how the electrons are arranged within an atom. Rutherford designed an experiment for this. In this experiment, fast-moving alpha (α)-particles were made to fall on a thin gold foil.

    On the basis of his experiment, Rutherford put forward the model of an atom, which had the following features:

    • There is a positively charged centre in an atom called the nucleus.
    • Nearly all the mass of an atom resides in the nucleus. The electrons revolve around the nucleus in well-defined orbits.
    • The size of the nucleus is very small as compared to the size of the atom.

  • Question 9
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    What is the minor axis length in the L-shell of the hydrogen atom?
  • Question 10
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    An ion with mass number 37 possesses one unit negative charge. If it contains 11.1% more zero charge subatomic particles than the negative charge subatomic particles, the symbol of ion is
  • Question 11
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    Cathode rays or cathode ray particles are

    Solution

    Cathode rays - In 1897, British physicist J. J. Thomson showed the rays were composed of a previously unknown negatively charged particle, which was later named the electron.

  • Question 12
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    If an electron is moving with a kinetic energy of 3.96 x10-34 J, calculate its de Broglie wavelength.

    (Given: m = 9.1 x 10-31 kg and h = 6.6 x 10-34 kgm2s-1)
  • Question 13
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    According to Dalton’s atomic theory

    Solution

    Dalton has developed the theory of the structure of matter and this theory is known as Dalton’s atomic theory. His research was based on experiments and also from law of chemical combination. Dalton’s atomic theory was quickly explained the many heretofore unexplained chemical phenomena. Dalton’s atomic theory quickly became the theoretical foundation in chemistry.

    Dalton’s atomic theory stated that:

    • All the matter is made of atoms which are tiny particles and indivisible.
    • All the given atom of the element is identical in mass, size, shape, and in other properties.
    • All different elements have different types of atoms and also different in their mass, size, shape, and in other properties.
    • All the atom of an element cannot be made or destroyed.

  • Question 14
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    The threshold frequency of a metal is 2.8 eV. If the radiation 2500  falls on the metal, then the kinetic energy of the emitted electron is:
  • Question 15
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    An element 'X' has 16 electrons. Calculate the number of electrons present in the M-shell of the element in X2- state.
  • Question 16
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    An electron revolves around the nucleus with a velocity of 3.05 x 107 ms-1. What is the wavelength of the electron?
  • Question 17
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    The radial distance between two peaks in the radial probability distribution curve of 2s-orbital is
  • Question 18
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    If the speed of a tennis ball is measured as 0.76 ms-1 and mass as 35 g, then find the uncertainty in position.
  • Question 19
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    The ratio of the radii of the 3rd orbits of He+ and Li2+ is:
  • Question 20
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    Charge on the electron was determined by

    Solution

    In 1909, Robert Millikan and Harvey Fletcher conducted the oil drop experiment to determine the charge of an electron. They suspended tiny charged droplets of oil between two metal electrodes by balancing downward gravitational force with upward drag and electric forces.

    The experiment helped earn Millikan a Nobel prize in 1923

  • Question 21
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    Isobars are the atoms with

    Solution

    Isobars are atoms (nuclides) of different chemical elements that have the same number of nucleons. Correspondingly, isobars differ in atomic number (or number of protons) but have the same mass number.

  • Question 22
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    When an electric discharge is passed through gaseous hydrogen, the H2 molecules dissociate and the energetically excited hydrogen atoms produced emit electromagnetic radiation of discrete frequencies. The hydrogen spectrum consists of

    Solution

    The emission spectrum of hydrogen consists of several series of sharp emission lines in the ultraviolet (Lyman series). in the visible (Balmer series). and in the infrared (Paschen series, Brackett series, etc,) regions of the spectrum. These series are named after their discoverer.

  • Question 23
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    A 100-watt bulb emits light having wavelength 5 x 10-7 m. Calculate the number of photons emitted per second by the bulb.
  • Question 24
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    Emission spectrum of a material results from the material's (atom or molecules)

    Solution

    The emission spectrum of a chemical element or chemical compound is the spectrum of frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state. The photon energy of the emitted photon is equal to the energy difference between the two states. There are many possible electron transitions for each atom, and each transition has a specific energy difference. This collection of different transitions, leading to different radiated wavelengths, make up an emission spectrum.

  • Question 25
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    A gas absorbs a photon having wavelength 400 nm and then re-emits two photons. If the wavelength of one photon is 800 nm, then the wavelength of the second photon will be:
  • Question 26
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    The wave number of line in the Paschen series of hydrogen emission spectrum is:
  • Question 27
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    Absorption spectrum, seen as dark lines in an otherwise continuous spectrum, for a given material results from the material's (atom or molecules)

    Solution

    In an absorption spectrum, portions of a continuous spectrum (light containing all wavelengths) are missing because they have been absorbed by the medium through which the light has passed; the missing wavelengths appear as dark lines or gaps.

  • Question 28
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    The relation between the energies of two different radiations whose wavelengths are 800 nm and 400 nm is:
  • Question 29
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    The total energy of an electron in the first excited state of the hydrogen atom is about −3.4 eV. What is the kinetic energy of the electron in this state?

    Solution

    Total energy of the electron, E = −3.4 eV
    Kinetic energy of the electron is equal to the negative of the total energy.
    K = −E = − (− 3.4) = +3.4 eV
    Hence, the kinetic energy of the electron in the given state is +3.4 eV.

  • Question 30
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    Correct expression for all series of lines in the hydrogen spectrum is (n1 = 1, 2, 3... and n2 = n1 + 1, n1 +2, ... , and is the wavenumber)

    Solution

    In an amazing demonstration of mathematical insight, in 1885 Balmer came up with a simple formula for predicting the wavelength of any of the lines in atomic Hydrogen in what we now know as the Balmer series.

    Three years later, Rydberg generalized this so that it was possible to determine the wavelengths of any of the lines in the hydrogen emission spectrum. Rydberg suggested that all atomic spectra formed families with this pattern (he was unaware of Balmer's work).

    It turns out that there are families of spectra following Rydberg's pattern, notably in the alkali metals, sodium, potassium, etc., but not with the precision the hydrogen atom lines fit the Balmer formula, and low values of n2 predicted wavelengths that deviate considerably.

    Rydberg's general equation is as follows:

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