p-Block Elements Test

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p-Block Elements Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following compounds is/are obtained by heating boric acid?
a. HBO₂
b. H2B₄O₇
c. B₂O₃

A
a only

B
a and b

C
a and c

D
All of the above
Question 2
1 / -0

The maximum oxidation state shown by any p-block element is

A
the sum of the s electrons

B
the sum of the p-electrons

C
half of the sum of the s and p-electrons

D
the sum of the s and p-electrons

Solution

Maximum oxidation state of any p block element is the number of ionisable electrons which is equal to the sum of s and p electrons present in valence shell. For example valance shell electronic configuration of group 15 element is ns²np³ so max oxidation state is +5
Question 3
1 / -0

As we move from B to Al in the p-block elements the sum of the first three ionisation enthalpies

A
considerably decreases

B
remains the same

C
slightly decreases

D
increases

Solution

On moving from B to Al size of the atom increases. So ionisation enthalpy decreases. Thus as we move from B to Al in the p-block elements the sum of the first three ionisation enthalpies considerably decreases.

This is the reason aluminium forms Al3+ ion.
Question 4
1 / -0

In the given question, two statements are provided which are labeled as Assertion (A) and Reason (R). Read both of them carefully and select the alternative that most suitably follows the statements.
Assertion (A): Diamond is a bad conductor of electricity.
Reason (R): All C-C bond lengths in diamond are of 154 pm.

A
Both (A) and (R) are true and (R) is the correct reason for (A).

B
Both (A) and (R) are true and (R) is not the correct reason for (A).

C
Both (A) and (R) are false.

D
(A) is false and (R) is true
Question 5
1 / -0

There are six groups of p-block elements in the periodic table numbering from

A
14 to 19

B
11 to 16

C
13 to 18

D
12 to 17

Solution

After two s block and 10 d block, p block elements starts from group 13 to group 18.
Question 6
1 / -0

One of the following p-block elements has unusually low melting point

A
Indium

B
aluminium

C
gallium

D
boron

Solution

Ga does not do not follow any of the simple crystal structures. And two nearest Ga atoms are bonded by covalent bond which leads to low melting point.
Question 7
1 / -0

The stability of the dihalides of Si, Ge, Sn and Pb increases steadily in the sequence

A
SiX₂<< GeX₂ << PbX₂ << SnX₂

B
SiX₂ << GeX₂ << SnX₂<< PbX₂

C
PbX₂<< SnX₂ << GeX₂ << SiX₂

D
GeX₂<< SiX₂ << SnX₂ << PbX₂
Question 8
1 / -0

The valence shell electronic configuration of p-block elements is ns2np1-6. But this is not true in the case of

A
nitrogen

B
Helium

C
carbon

D
carbon

Solution

He has 1s² configuration. It is a noble gas.
Question 9
1 / -0

Aluminium should not be washed with materials containing washing soda as

A
washing soda is expensive

B
washing soda is easily decomposed

C
washing soda reacts with aluminium to form insoluble oxide

D
washing soda forms soluble metal aluminate
Question 10
1 / -0

Graphite is a smooth lubricant that is extremely difficult to melt. The reason for this anomalous behaviour is that graphite

A
has carbon atoms arranged in large plates of rings of strongly bonded carbon atoms with weak interpolate bonds

B
is a non-crystalline substance

C
is an allotrope of carbon

D
has molecules of variable molecular masses like polymers

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p-Block Elements Test - 1

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Question 1

a only

a and b

a and c

All of the above

Question 2

the sum of the s electrons

the sum of the p-electrons

half of the sum of the s and p-electrons

the sum of the s and p-electrons

Solution

Question 3

considerably decreases

remains the same

slightly decreases

increases

Solution

Question 4

Both (A) and (R) are true and (R) is the correct reason for (A).

Both (A) and (R) are true and (R) is not the correct reason for (A).

Both (A) and (R) are false.

(A) is false and (R) is true

Question 5

14 to 19

11 to 16

13 to 18

12 to 17

Solution

Question 6

Indium

aluminium

gallium

boron

Solution

Question 7

SiX2 << GeX2 << PbX2 << SnX2

SiX2 << GeX2 << SnX2 << PbX2

PbX2 << SnX2 << GeX2 << SiX2

GeX2 << SiX2 << SnX2 << PbX2

Question 8

nitrogen

Helium

carbon

carbon

Solution

Question 9

washing soda is expensive

washing soda is easily decomposed

washing soda reacts with aluminium to form insoluble oxide

washing soda forms soluble metal aluminate

Question 10

has carbon atoms arranged in large plates of rings of strongly bonded carbon atoms with weak interpolate bonds

is a non-crystalline substance

is an allotrope of carbon

has molecules of variable molecular masses like polymers

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SiX₂<< GeX₂ << PbX₂ << SnX₂

SiX₂ << GeX₂ << SnX₂<< PbX₂

PbX₂<< SnX₂ << GeX₂ << SiX₂

GeX₂<< SiX₂ << SnX₂ << PbX₂