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Group 15 Elements Test - 1

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Group 15 Elements Test - 1
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  • Question 1
    1 / -0.25
    Electronic configuration of nitrogen atom is
    Solution

    Concept:

    Electronic configuration :

    • The arrangement of electrons in the electronic levels of an atom is called its electronic configuration.
    • The electrons are arranged according to their energies and space availability.
    • There are a few sets of rules which we follow while arranging the electrons in an atom.

    They are-

    • Aufbau principle-
      • It states that the atomic orbitals which have lower energies are filled first.
      • Then the electron goes to occupy the higher atomic energy levels.
      • This ruled is followed to write the electronic configuration of atoms in their ground state.
      • When in the excited state, the electrons might vacant the lower energy state and move on to a higher energy state.
      • The order in which atomic orbitals are filled are: 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p.
      • The order follows that the lower ( n + l ) value of atomic orbital will have lower energy, where n = principal quantum number and l = azimuthal quantum number.
    • Pauli's exclusion principle:
      • ​An electron is characterized by four quantum numbers n, m, l, and s.
      • Pauli's exclusion principle states that every electron must have its unique set of these four quantum numbers.
      • No two electrons can have the same set of quantum numbers.
      • Simplifying, we may say that an orbital can contain a maximum of two electrons and the two electrons should have opposite spins ( + ½, - ½ ).
    • Hund's rule of maximum spin multiplicity:
      • While filling up the orbitals of the same energy, or degeneracy, electrons will first singly occupy the subshell.
      • After each subshell has been singly occupied, electron pairing will start.
      • This rule thus implies that maximum spin should be maintained while filling up electrons in a subshell.
      • The maximum spin state involves maximum exchange energy and yields a more stable state.
    • Modern periodic law:
      • ​The modern period table involves the arrangement of the elements according to their increasing Atomic number.
      • The law states that the physical and chemical properties of an element are characteristics of its Atomic number.

    Explanation:

    • The expected electronic configuration of N 1s2, 2s2, 2px2 2py1 but the actual electronic configuration of Nitrogen is 1s2, 2s2, 2px1 2py1 2pz1.
    • This is in co-relation with Hund's rule of maximum spin multiplicity.​
    • The electronic configuration has 2p subshells (which are the same in energy) singly occupied.
    • The total spin of the electrons is

    \(S = ½ + ½ + ½ =3/2\)

    • Then the maximum spin multiplicity

    \(​⇒ 2S + 1 = 3 +1 = 4 \)

    • If Hund's rule was being disobeyed, the electronic configuration would have been 1s22s22px22py1.
    • In that case, the total spin should have been,

    Spin multiplicity \( = 1 + 1 = 2\).

    Hence, in order to have maximum spin multiplicity, the electronic configuration of Nitrogen becomes 1s2, 2s2, 2px1 2py1 2pz1.

    Important Points

    • 1s2, 2s1, 2px2 2pythis electronic configuration of Nitrogen in ground state is not possible because it does not obey the Aufbau filling of orbitals energy series which is :

    \(1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p<8s\)

  • Question 2
    1 / -0.25
    Of the following the most acidic is:
    Solution

    Key Points

    • All the elements of the group 15 elements form tri oxides and pentoxides having the general formula M2O3 or M2O5.
    • The oxides of Nitrogen, Phosphorus, and Arsenic are acidic.
    • The trioxide of antimony Sb2O3 is amphoteric while that of bismuth Bi2O3 is basic.
    • As2O3 is acidic in nature.
    • The pentoxides of all these elements are acidic but acidic character decreases down the group.
    • Thus, P2O5 is the strongest acidic oxide whereas Bi2O3  is the weakest acidic oxide.
    • The acidic character of the same element increases with an increase in the oxidation state.

    Hence, the most acidic oxide among the following is P2O5.

    Important Points

    Facts about P2O5:

    •  It is also written as P4O10 and is called phosphorus pentoxide.
    • It is prepared by burning phosphorus in excess of air or oxygen. It is a white solid which sublimes on heating.
    • It is a strong dehydrating agent and dehydrates nitric acid as well as sulphuric acid.
    • The structure is:

    Phosphorus Pentoxide (P2O5): Structure, Preparation, Properties, Uses

    Additional Information

    • N2O5 is the most acidic of group 15 elements. 
  • Question 3
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    Which one of the given hydrides of group 15 elements has the lowest boiling point?
    Solution

    Explanation:

    PH3 has lowest boiling point because NHhas intermolecular hydrogen bonding and other hydrides have higher van-der wall forces.

    Except NH3 boiling point smoothly increases down the group due to increase in magnitude of vander Waal's force. Ammonia shows intermolecular H bonding. Its boiling point is higher than AsH3 , but lower than SbH3.

    Order of Boiling Point:

    SbH3> NH3> AsH3> PH3

    Additional Information Most basic is ammonia because of highest electron density on nitrogen.

    Highest bond angle is in ammonia as nitrogen has highest electron density , repulsion between lone pairs and bond pairs will be more resulting into more bond angle due to small size of nitrogen.

  • Question 4
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    Which one of the following oxides of nitrogen is known as ‘anhydride’ of nitric acid?
    Solution

    The correct answer is option 2 i.e.N2O5

    Acid anhydride

    • Anhydride means ‘without water’ It can be defined as the chemical compound formed by eliminating water from another compound.
    • Anhydrides react with water to produces either base or an acid.
    • Acid anhydrides are the molecules that are capable of forming acidic solutions in water.
    • Dinitrogen pentoxide (N2O5) is the anhydride of nitric acid. 
    • It means Hydration of Dinitrogen pentoxide (N2O5) gives Nitric acid.
    • N2O5 + H2O → 2HNO3
  • Question 5
    1 / -0.25
    which trihydride has most thermal stability ?
    Solution

    Explanation:

    • PH3, ASH3, NH3, SbH3 - these are the hydrides of group 15 elements.
    • One thing which is important to note is the hydrides of these elements are basic (Lewis Bases) in nature due to the presence of a lone pair of electrons.
    • Because electrons diffuse over a larger volume, basicity decreases with the size of the core atom.
    • The M-H bond decreases when the size of central atoms increases. (Where M can be any group 15 element - P, N, As, Bi, Sb)
    • As a result, as the size of hydrides grows larger as we move down the group, their stability declines and their decreasing character increases.
    • In simple words - The thermal stability of hydrides decreases as we move down the group. 
    • Hence, the order of their stability is - 
      • NH3 > PH> AsH3 > SbH3 
    • Hence, the chemical compound ammonia (NH3 ) is the most thermally stable.
  • Question 6
    1 / -0.25

    Ammonium dichromate on heating gives:

    Solution

    Explanation:

     When we heat ammonium dichromate, (NH4)2Cr2O7 it decomposes to give the following products:

    (NH4)2Cr2O7 → 4H2O + N2 + Cr2O3

    From the reaction, we can say that on heating we get Chromium Oxide and Nitrogen.

    Additional Information

    Decomposition reaction:

    • Those reactions in which a compound splits up into two or simpler substances are known as decomposition reactions.
    • The decomposition reactions are carried out by applying heat, light, or electricity.
    • Heat, light, or electricity provide energy that breaks a compound into two or simpler compounds
    • decomposition reaction is the opposite of a combination reaction. 

    The types of decomposition reaction are:

    Thermal decomposition:

    • When a decomposition reaction is carried out by heating, it is called thermal decomposition.

    Example: CaCO3 → CaO + CO2

    • When limestone (CaCO) is heated then it changed to Quick lime (CaO) and carbon dioxide gas.      

    Electrolytic decomposition:

    • When current passed through an aqueous solution of a substance it breaks down into ions.

    Example: 2H2O → 2H2 + O2

    Photo decomposition reaction:

    • When a compound is broken down by photons or absorption of light, it is called a photodecomposition reaction.

    Example: 2AgCl → 2Ag + Cl2

  • Question 7
    1 / -0.25

    The correct order of acidic nature of oxides is in the order:

    Solution

    Explanation: 

    Nitrogen Family elements form oxides of the types X2O3, X2O4, and X2O5,

    The acidic strength of oxides :

    N2O < NO < N2O3 2O4 < N2O5 -

    The decreasing order of stability of oxides of group 15 follows.

    P2O5 > As2O5 > Sb2O5 > Bi2O5

    The nature of oxides of group 15 elements is as follows,

    N2O3, and P2O3, (acidic): As2O3, and Sb2O3, (amphoteric); Bi2O3 (basic)

    The acidic character of oxides increase with increase in oxidation number of element. However,

    (N2O, NO) → (Neutral)

    N2O3, NO2, and N2O3 → Acidic character increases

  • Question 8
    1 / -0.25
    The number of P-O-P bridges in the structure of phosphorous pentoxide and phosphorous trioxide is respectively:
    Solution

    Explanation:

    Structures of phosphorous pentoxide and phosphorous trioxide

    From the figure it is clear that

    P - O - P bridge in both the structures are 6

    Additional Information Oxides of phosphorus:

    Phosphorus is quite reactive and forms number of compounds in station states of -3, +3 and +5.

    Phosphorus forms two common oxides namely, phosphorus trioxide (P4O6) and phosphorus penta oxide (P4O10)

    I. Phosphorus trioxide (P4O6): It is formed when P is burnt in a limited supply of air.

    P4 + 3O2 → P4O6

    II. Phosphorus penta oxide (P4O10): It is prepared by heating white phosphorous in excess of air 

    P4 + 5O2 → P4O10

  • Question 9
    1 / -0.25
    Identify the correct statement regarding oxidation state of Group 15 elements.
    Solution

    The correct answer is option 2, i.e., The stability of +5 oxidation state decreases down the group.

    • Out of the given options, the correct statement regarding the oxidation state of Group 15 elements (Nitrogen family) is the stability of +5 oxidation state decreases down the group.
    • The stability of +5 oxidation state decreases down the group and that of +3 oxidation state increases, with BiFbeing the only well-characterized Bi (V) compound. Hence, Option 1 is NOT correct while Option 2 is correct.
      • This is because of the 'inert-pair effect'. 
    • Inert-pair effect is the tendency of the two s-electrons to not participate in bonding due to the high energy needed for unpairing them.
      • This phenomenon is seen in compounds of post-transition metals (Group 13, 14, 15, and 16).
    • The tendency of -3 oxidation state decrease down the group.
    • This happens due to the increase in size and metallic character of elements down the group.
    • The last member of the Nitrogen family, Bismuth hardly forms any compound with -3 oxidation state.
    • Nitrogen is restricted to maximum covalency of 4 because it has 4 orbitals (one s and three p) available for bonding.
    • The most common oxidation states exhibited by the Group 15 elements is -3, +3, and +5.
    • Nitrogen exhibits +1, +2, and +4 oxidation states also when it reacts with oxygen.
    • Phosphorous exhibits +1 and +4 oxidation states in some oxoacids.
  • Question 10
    1 / -0.25
    Which is true with regard to the properties of PH3
    Solution

    Explanation:

    Phosphorus is quite reactive and forms a number of compounds in station states of -3, +3, and +5.

    Phosphine (PH3) is prepared by the reaction of calcium phosphide with water or dilute HCl

    Properties

    → It is a colorless gas with a rotten fish smell and is highly poisonous.

    → It explodes in contact with traces of oxidizing agents like HNO3, Cl2, and Br2 vapours.

    → It is slightly soluble in water.

    → The solution of PH3 in water decomposes in presence of light giving red phosphorus and H2 .

    → Phosphine is weakly basic and like ammonia, gives phosphonium compounds with acids

    e.g., PH3 + HBr →  PH4Br


    Additional Information

    PH3, ASH3, NH3, SbH3 - these are the hydrides of group 15 elements.

    One thing which is important to note is the hydrides of these elements are basic (Lewis Bases) in nature due to the presence of a lone pair of electrons.

    Because electrons diffuse over a larger volume, basicity decreases with the size of the core atom.

    The M-H bond decreases when the size of central atoms increases. (Where M can be any group 15 element - P, N, As, Bi, Sb)

    As a result, as the size of hydrides grows larger as we move down the group, their stability declines and their decreasing character increases.

    In simple words - The thermal stability of hydrides decreases as we move down the group. 

    Hence, the order of their stability is - 

    NH3 > PH> AsH3 > SbH3 

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