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Atoms, Nuclei & Radioactivity Test - 6

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Atoms, Nuclei & Radioactivity Test - 6
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  • Question 1
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    In Geiger-Marsden experiment very small deflection of the beam was expected because

     

    Solution

     

     

    In the Geiger-Marsden experiment very small deflection of the beam was expected because positive charge and the negative electrons are distributed through the whole atom reducing electric field inside the atom.

     

     

  • Question 2
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    Fluorescence is

     

    Solution

     

     

    Fluorescence is the emission of light by a substance that has absorbed light or other electromagnetic radiation. It is a form of luminescence. In most cases, the emitted light has a longer wavelength, and therefore lower energy, than the absorbed radiation. The most striking example of fluorescence occurs when the absorbed radiation is in the ultraviolet region of the spectrum, and thus invisible to the human eye, while the emitted light is in the visible region, which gives the fluorescent substance a distinct color that can be seen only when exposed to UV light. Fluorescent materials cease to glow nearly immediately when the radiation source stops, unlike phosphorescent materials, which continue to emit light for some time after.

     

     

  • Question 3
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    Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?

     

    Solution

     

     

    In the alpha-particle scattering experiment, if a thin sheet of solid hydrogen is used in place of a gold foil, then the scattering angle would not be large enough. This is because the mass of hydrogen (1.67 ×10 −27) is less than the mass of incident α−particles (6.64 ×10 −27). Thus, the mass of the scattering particle is more than the target nucleus (hydrogen). As a result, the α−particles would not bounce back if solid hydrogen is used in the α−particle scattering experiment.

     

     

  • Question 4
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    It is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?

     

  • Question 5
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    An electron collides with a hydrogen atom in its ground state and excites it to a state of n = 3. How much energy was given to the hydrogen atom in this inelastic collision?

     

    Solution

     

     

    Energy at ground state E1 ​ =−13.6 eV
    Energy at n=3: E3 ​ =−13.6/9 ​=1.5 eV
    To excite it to n=3 energy given to electron is E3 ​−E1 ​=12.1 eV

     

     

  • Question 6
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    Which of these statements correctly describe the atomic model according to classical electromagnetic theory ?

     

    Solution

     

     

    In classical electromagnetic theory, atoms and molecules are considered to contain electrical charges (i.e. electrons, ions) which are regarded as oscillating about positions of equilibrium, each with its appropriate natural frequency, v0 . When placed in a radiation field of frequency v , each oscillator in the atom or molecule is set into forced vibration with the same frequency as that of the radiation. The amplitude of the forced vibration is small, but as v approaches v0 , the amplitude of the forced vibration increases rapidly. To account for the absorption of energy from the radiation field, it is necessary to assume that the oscillator in the atom or molecule must overcome some frictional force proportional to its velocity during its forced motion. For small amplitudes of forced oscillation, the frictional force, and therefore the absorption of energy, is negligible. Near resonance , the amplitude of oscillation becomes large, with a correspondingly large absorption of energy to overcome the frictional force. Therefore, the radiation of frequencies near the natural frequency of the oscillator corresponds to an absorption band.

     

     

  • Question 7
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    Reason why there are many lines in an atomic spectrum is because

     

    Solution

     

     

    Lines in the spectrum were due to transitions in which an electron moved from a higher-energy orbit with a larger radius to a lower-energy orbit with smaller radius. The orbit closest to the nucleus represented the ground state of the atom and was most stable; orbits farther away were higher-energy excited states.

     

     

  • Question 8
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    In the ground state of which model electrons are in stable equilibrium with zero net force?

     

    Solution

     

     

    In Thomson 's model, the atom is composed of electrons surrounded by a soup of positive charge to balance the electrons 'negative charges, like negatively charged “plums ”surrounded by positively charged “pudding ”. The 1904 Thomson model was disproved by Hans Geiger and Ernest Marsden 's 1909 gold foil experiment.

     

     

  • Question 9
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    A triply ionized beryllium ion Be3+ , (a beryllium atom with three electrons removed), behaves very much like a hydrogen atom except that the nuclear charge is four times as great. For the hydrogen atom, the wavelength of the photon emitted in the n =2 to n=1 to transition is 122 nm. What is the wavelength of the photon emitted when a Be3+  ion undergoes this transition?

     

    Solution

     

     

    1/ λ=Z2 . (both have same transition so same value of n)
    λ/122=1/16
    λ=122/16
    =7.62nm

     

     

  • Question 10
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    In Geiger-Marsden experiment, at the point of closest approach

     

    Solution

     

     

    In the Geiger-Marsden experiment, at the point of closest approach the kinetic energy is zero and the electrical potential equals the initial kinetic energy supplied.

     

     

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