Production Engineering Test 8

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Production Engineering Test 8

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Weekly Quiz Competition

Question 1
1 / -0

Two readings taken by a slip gauge on a flatness interferometer count 10 and 14 fringes. Second reading is obtained by rotating the set up at 180°. Assuming the wavelength of radiation is 0.8065 μm, the parallelism error b/w two faces of slip gauge is

A
0.5085 μm

B
0.8065 μm

C
0.4032 μm

D
1.7012 μm

Solution

Concept:
Parallelism error \(= \left( {\frac{{{n_2} - {n_1}}}{2}} \right) \times \frac{\lambda }{2}\)
Calculation:
Parallelism error \(= \left( {\frac{{14 - 10}}{2}} \right) \times \frac{{0.8065}}{2}\)
∴ Parallelism error = 0.8065 μm

Question 2

1 / -0

Match the List-I (Measuring instruments) with List-II (Applications) and select the correct from the codes given in the lists below:

List 1	List 2
Talysurf	T slots
Telescopic gauge	Flatness
Transfer calipers	Internal diameter
Auto collimator	Roughness

A-1, B-2, C-3, D-4

A-4, B-3, C-1, D-2

A-4, B-2, C-3, D-4

A-3, B-4, C-1, D-2

Solution

Explanation:

Various devices and their properties are mentioned in the table below.

Devices	Properties
Autocollimator	An autocollimator is an optical instrument which is used to measure small angles with high sensitivity. It is also used for plane surface inspection i.e. to measure straightness, flatness and alignment of a plane surface.
Vernier calliper	It is used to measure outer dimensions of the objects (using the main jaws), inside dimension (using the smaller jaws at the top) and depth (using stem).
Height gauge	It is used for measuring the width of the slot and external dimensions. It is used with a dial indicator to check hole location, pitch dimensions, concentricity and eccentricity.
Tool maker’s microscope	This is designed for measurement on parts of complex forms e.g. profile of external threads, tools, templates and gauges. It can also be used for measuring centre-to-centre distances of holes in any planes.
Talysurf	Talysurf is an electronic equipment which is used to measure surface roughness. It works on carrier modulating principle.
Telescopic gauge	It is an indirect measuring gauge and used to measure any hole, slot or bore. The shape of this gauge is as T (English letter) with knurling on the backside of the handle.
Transfer callipers	The parts which cannot be measured directly by scale are measured by callipers. Transfer callipers are the callipers which have adjustable legs so that it can be used to measure confined or recessed areas. for example, T shape, U shape etc.

Question 3
1 / -0

A hole of nominal diameter 30 mm with a hole tolerance of ± 0.020 mm is used to design a GO – NO GO plug gauge. If gauge tolerance is 10 % of work tolerance and no wear condition, the dimension of GO plug gauge as per unilateral tolerance system is

A
\(29.984_{ - 0.010}^{ + 0.01}\)

B
\(29.98_{ + 0.0}^{ + 0.004}\)

C
\(30.01_{ - 0.00}^{ - 0.02}\)

D
\(30_{ - 0.020}^{ - 0.016}\)

Solution

Concept:
Work tolerance = 30.020 – (30 – 0.02)
∴ Work tolerance = 0.04 mm
Now,
Gauge tolerance = 10% of work tolerance.
∵ No wear allowance on GO gauge
Lower limit of GO guage = Lower limit of Hole
Higher limit of GO gauge = Lower limit of GO + Gauge tolerance
Calculation:
Gauge tolerance = 10 % of 0.04
Gauge tolerance = 0.004 mm
Lower limit of GO gauge = 29.98 mm
Higher limit of GO gauge = 29.98 + 0.004
Higher limit of GO gauge = 29.984 mm
∴ Go gauge = 29.98^+0.004 or \({30^{\begin{array}{*{20}{c}} { - 0.016}\\ { - 0.020} \end{array}}}\)
Question 4
1 / -0

A cylindrical standard of 31.5 mm diameter and two wires of 2 mm diameter each used to measure the effective diameter of an external metric thread having included angle as 60° and pitch 4.5 mm. If the micrometer reading over the standard wires are 17.532 mm and 16.398 mm. What is the effective diameter (mm) of thread?

A
24-26

B
244-261

C
247-266

D
249-262

Solution

Concept:
Wire diameter, \(d = \frac{P}{2}\sec \alpha\)
\(\alpha = \frac{{60}}{2} = 30^\circ \)
P = pitch
Taken as best wire
m = s + (R₂ + R₁)
s = standard, R₁ and R₂ are reading over the wires.
Effective diameter = \(M - \left( {d + \frac{P}{2}\sec \alpha } \right)\)
Calculation:
Given:
s = 31.5 mm, α = 30°, P = 4.5 mm, R₁ = 17.532 mm, R₂ = 16.398 mm
Now,
\(d = \frac{P}{2}\sec \alpha = 2.598\;mm\)
M = 31.5 + (16.398 – 17.532) = 30.366
\(M - \left( {d + \frac{P}{2}\sec \alpha \;} \right)\)
∴ Effective diameter = 25.17 mm
Question 5
1 / -0

A graph is drawn to a vertical magnification of 10000 and horizontal magnification of 100, and the areas above and below the datum line are as follows:
Above
150 mm²
80 mm²
170 mm²
40 mm²
Below
80 mm²
60 mm²
150 mm²
120 mm²

The average roughness R_a for sampling length of 0.8 mm will be

A
1.14 mm

B
1.10 mm

C
1.06 mm

D
1.02 mm

Solution

Concept:
The average roughness is
\({\rm{Ra\;}} = {\rm{\;}}\frac{{\sum U + \;\sum L}}{L}\; \times \;\frac{1}{V}\; \times \;\frac{1}{H}\)
Where,
\(\sum U + \;\sum L\)= sum of area above and below of datum line, L = sampling length
V and H are vertical and horizontal magnification respectively
Calculation:
\(\sum U + \;\sum L\)= 150 + 80 + 170 + 40 + 80 + 60 + 150 + 120 = 850 mm²
\({\rm{Ra\;}} = {\rm{\;}}\frac{{850}}{{0.8}}\; \times \;\frac{1}{{{{10}^4}}}\; \times \;\frac{1}{{{{10}^2}}}\)
∴ R_a = 1.06 mm