Internal Combustion Engine Test 1

Result

Internal Combustion Engine Test 1

Score
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out of -
Rank
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out of -

TIME Taken - -

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Question 1
1 / -0

The mean effective pressure of an Otto cycle is 1 MPa. The displacement of engine is 3.8 liters if the engine is operated as a 4-stroke cycle engine at 4000 rpm. What is power in kW.

A
253.33

B
126.67

C
63.33

D
506.67

Solution

Concept:
\({\rm{Power\;}} = \frac{{{P_m} \times \;Volume \times N}}{{60}}\)
N = 4000 rpm
For 4 stroke engine:
\(N = \frac{n}{2} = 2000\;rpm\)
For 2 stroke engine:
N = n = 4000 rpm
Calculation:
\({\rm{Power\;}} = \frac{{{P_m} \times \;Volume \times N}}{{60}}\)
\(P = \frac{{1000\; \times \;3.8\; \times \;{{10}^{ - 3}}\; \times \;2000}}{{60}}\)
∴ P = 126.67 kW