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Civil Engineering Test - 2

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Civil Engineering Test - 2
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  • Question 1
    2 / -0.66

    In a beam of 300 mm wide and 500 mm effective depth, the value of the design shearing force at the critical section is 300 kN. The permissible shear stress in concrete is 0.4 N/mm2 depending on the percentage of steel content. The shear reinforcement will be designed for a shear force of ____ kN

    Solution

    Concept:

    Recent laboratory experiments confirmed that reinforced concrete in beams has shear strength even without any shear reinforcement. This shear strength (τc) depends on the grade of concrete and the percentage of tension steel in beams and this is known as the permissible shear stress in concrete.

    On the other hand, the shear strength of reinforced concrete with the reinforcement is restricted to some maximum value τcmax depending on the grade of concrete.

    The amount of shear reinforcement to be provided is determined to carry a shear force Vus equal to

    Vus = Vu – τc ×  b × d

    Where b is the breadth of rectangular beams or bw in the case of flanged beams.

    d = effective depth of beam

    Vus = Design shear force

    Vu = Factored shear force and τc = permissible shear stress in concrete.

    Calculation:

    Given,

    b = 300 mm

    d = 500 mm

    Vu = 300 kN = 300,000 N

    τc = 0.4 MPa

    Design shear force is 

    Vus = 300,000 – (0.4 × 300 × 500) = 240,000 N = 240 kN

  • Question 2
    2 / -0.66

    Calculate the spacing between contraction joints by using the following data:

    Width of slab = 4.52 m

    The thickness of the slab = 25 cm

    Coefficient of friction = 1.5

    Allowable tensile stress in steel = 1400  kg/cm2

    Diameter of bar = 12 mm

    Spacing between the bar = 300 mm

    Take γc = 2400 kg/m3

    Solution

    Concept:

    In the Case of the dowel bar in the contraction joint, all the tensile load will be carried by the reinforcement only.

    Force resisted by reinforcement = friction force by the ground on slab


  • Question 3
    2 / -0.66

    Spot speed studies were conducted on a certain stretch of a highway and consolidated data collected are given below:

    Speed range, Kmph No. of vehicles observed
                 0 - 10   10
               10 - 20 40
               20 - 30 50
               30 - 40 50
               40 - 50 150
               50 - 60 250
               60 - 70 300
               70 - 80 90
               80 - 90 40
               90-100 20

    Determine the upper and lower values of speed limits for the regulation of mixed traffic flow.

    Solution

    Concept:

    (1) 98Th percentile speed – It is the speed at or below which 98% of vehicles are moving and only 2% exceeds this limit.

    As per IRC, this speed is considered as design speed for geometric design.

    (2) 85Th percentile speed – This speed is considered the upper safe limit for vehicle movement.

    (3) 15Th percentile speed - This speed is considered the lower safe limit in order to avoid congestion.

    Calculation:

    Total no.of vehicle = 1000 

    Speed range Average speed number of vehicle % frequency Cumulative % frequency
         0 - 10           5            10       1 %               1 %
       10 - 20          15            40       4  %               5 %
       20 - 30         25            50       5 %             10 %
       30 - 40         35            50       5 %             15 %
       40 - 50          45          150      15 %             30 %
       50 - 60         55          250      25 %              55 %
       60 - 70         65          300      30 %             85 %
       70 - 80         75            90        9 %             94 %
       80 - 90         85            40        4 %             98 %
       90 - 100         95            20        2 %             100 %

    Lower speed limit = Speed corresponding to 15 % Cumulative % frequency = 35 kmph.

    Upper speed limit = Speed corresponding to 85 % Cumulative % frequency = 65 kmph.

    Design speed = Speed corresponding to 98 % = 85 kmph.

  • Question 4
    2 / -0.66

    The width of the elementary gravity dam as shown below is -

    Take specific gravity of dam material 2.2 and seepage coefficient at the base C = 0.8

    Solution

  • Question 5
    2 / -0.66

    A city with a population of 4 lakh generates municipal solid waste(MSW) at the rate of 160 g/capita/day. The MSW will be decomposed by incineration method which produces 9 kg of ashes per 50 kg of MSW. These ashes will be further used in the cement industry. The amount of Portland cement that can be produced per day if 1kg of cement requires 200 gm of ash.

    Solution

    Calculation:

    Given:

    Population = 4 lakh,

    MSW rate = 160 g/capita/day

    Total MSW = 160x10-3 kg x 4 x 105 = 64000 kg/day

    50 kg MSW produce = 9 kg ash

  • Question 6
    2 / -0.66

    The evaluation of the definite integral  by using Simpson’s 1/3rd (one –third) rule with step size h = 0.6 yields

    Solution


  • Question 7
    2 / -0.66

    The stress state at a point in a material under plane stress condition is equi-biaxial tension with a magnitude of 10 MPa. If one unit on the σ - τ plane is 1 MPa, the Mohr’s circle representation of the state-of-stress is given by

    Solution

    Concept:

    General Mohr Circle for biaxial stress condition:



  • Question 8
    2 / -0.66

    A problem in Mathematics is given to three students A, B and C. The probability of A solving the problem is 1/2 and B not solving is 1/4. The whole probability of the problem being solved is 63/64. What is the probability of solving it by C?

    Solution

  • Question 9
    2 / -0.66

    Which of the following cement is recommended mostly in 

    (i) Concrete to be used in marine condition.

    (ii) Concrete to be used in the construction of sewage treatment works.

    (iii) Concrete used for fabrication of pipes which are likely to be buried in marshy region

    Solution

    Concepts:

    Sulphate Resisting Cement (SRC): In this cement, the amount of tricalcium aluminate (C3A) is restricted to a low value generally less than 5%.

    The application of SRC:

    1. It should be used in concrete used for the fabrication of pipes that are likely to be buried in the marshy regions or sulfate-bearing soils because it has the risk of deterioration due to sulfate attack.
    2. It should be used in concrete to be used in the construction of sewage treatment works because sewage water contains excessive sulfates.
    3. It is recommended for use in aggressive sulfate-rich areas such as marine environments where the concrete is exposed to the risk of deterioration and spalling due to sulfate attack.

    Additional Information:

    The different type of cement and their usage is given below in the tabulated form:

    Type of Cement

    Where to Use

    Rapid hardening Cement

    Road work where it is a must to open the road with minimum delay.

    Extra Rapid hardening

    Concreting in cold weathers

    Low Heat Cement

    Mass Constructions like Dams, abutments, etc.

    Portland Pozzolana Cement

    Marine and Hydraulic constructions, Mass concrete structures.

    Quick Setting Cement

    Concrete to be laid under normal water.

    High Alumina Cement

    Where early removal of formwork is required.

    Hydrophobic Cement

    Where long storage or transportation is required.

  • Question 10
    2 / -0.66

    The Poisson’s ratio for a perfectly incompressible linear elastic material is

    Solution

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