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Electronics & Communications Test - 5

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Electronics & Communications Test - 5
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Weekly Quiz Competition
  • Question 1
    2 / -0.66

    A half-wave rectifier circuit using ideal diode has an input voltage of 20 sin ωt Volt. Then average and rms values of output voltage respectively, are

    Solution

    Concept:

    For the half-wave rectifier, the output is present is only for one half of the input signal and clipped for the other half.

    Positive half-wave rectifier clips the negative half of the input signal and only a positive part of the input signal is present.

    Negative half-wave rectifier clips the positive half of the input signal and only negative part of the input signal is present

    In a half-wave rectifier circuit, the average value of output voltage is:

  • Question 2
    2 / -0.66

    The RMS value of the signal shown in the figure is:

    Solution

  • Question 3
    2 / -0.66

    Consider the circuit shown in the figure below:

    If Rx = ∞, then the potential differences between two terminal a and b is equal to

    Solution

    Vab = Va – Vb

    For Rx = ∞ (Open-circuit), the circuit is redrawn as:

  • Question 4
    2 / -0.66

    The output (X) waveform for the combinational circuit shown below for the inputs A and B (waveform shown in the figure) will be –

    (Assume no propagation delay)

    Solution


  • Question 5
    2 / -0.66

    The Transmission Parameter of the given network are:

    Solution

  • Question 6
    2 / -0.66

    Two Hertzian dipole antennas are placed at a separation of d = λ/4 on z-axis to form an antenna array. The current fed to the two antennas are I1 and I2. If I2 lays behind I1 by an angle of π/2 then the resultant field pattern of antenna array will be:

    Solution

    Explanation:




  • Question 7
    2 / -0.66

    From the four options given below, identify which of the given equation is invertible?

    Solution

    Invertibility: If the output is uniquely reproduced by input, then it called invertibility.

    Analysis:

    1) y(t) = x2(t)

    For the input as x(t) and -x(t), the output is the same, i.e.


  • Question 8
    2 / -0.66

    Solution

  • Question 9
    2 / -0.66

    For the figure given above if,  then the steady state error will be:

    Solution

    Concept:

    Steady-state error is defined as the difference between the input and the output of a system in the limit as time goes to infinity (i.e. when the response has reached steady state).

    The steady-state error will depend on the type of input (step, ramp, etc.) as well as the system type (0, I, or II).

    The steady-state error of a unity feedback stable system



  • Question 10
    2 / -0.66

    A bandlimited Gaussian white noise PSD is given by

    Solution

    PSD is the Fourier transform of autocorrelation function.


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