Quantitative Aptitude Test

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Quantitative Aptitude Test - 11

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Weekly Quiz Competition

Question 1

1 / -0.25

Directions For Questions

Study the following table carefully and answer the question given below.
Number (N) of six types of electronic products sold by six different stores in a month and the price per product (P) (price in Rs. '000) charged by each store:

Store	A		B		C		D		E		F
Product	N	P	N	P	N	P	N	P	N	P	N	P
L	54	135	48	112	60	104	61	124	40	136	48	128
M	71	4.5	53	308	57	5.6	49	49.	57	5.5	45	4.7
N	48	12	47	18	52	15	54	11.5	62	10.5	56	11
O	52	53	55	48	48	50	54	49	59	47	58	51
P	60	73	61	68	56	92	44	94	46	76	59	78
Q	43	16	44	15	45	14.5	48	15.6	55	19.2	55	14.9

...view full instructions

The number of L-type products sold by store F is ______ percent of the number of the same type of products sold by store E.

76.33

124

83.33

120 Solution

Number of L-type products sold by $E=40$
Number of L-type products sold by $F=48$
Required Percentage $=\frac{48}{40} \times 100=\frac{6}{5} \times 100=120 \%$

Hence, the correct option is (d).

Question 2

1 / -0.25

Directions For Questions

Store	A		B		C		D		E		F
Product	N	P	N	P	N	P	N	P	N	P	N	P
L	54	135	48	112	60	104	61	124	40	136	48	128
M	71	4.5	53	308	57	5.6	49	49.	57	5.5	45	4.7
N	48	12	47	18	52	15	54	11.5	62	10.5	56	11
O	52	53	55	48	48	50	54	49	59	47	58	51
P	60	73	61	68	56	92	44	94	46	76	59	78
Q	43	16	44	15	45	14.5	48	15.6	55	19.2	55	14.9

...view full instructions

What is the ratio of the total number of N and L-type products together sold by store D to that of the same type of products sold by store A? What is the ratio of the total number of N and L-type products together sold by store D to that of the same type of products sold by store A?

119 : 104

102 : 115

117 : 103

None of these

Solution

Total number of N and L-type products together sold by store D = 61 + 54 = 115

Total number of N and L-type products together sold by store A = 54 + 48 = 102

Ratio = 115 : 102

Hence, the correct option is (b).

Question 3

1 / -0.25

Directions For Questions

Store	A		B		C		D		E		F
Product	N	P	N	P	N	P	N	P	N	P	N	P
L	54	135	48	112	60	104	61	124	40	136	48	128
M	71	4.5	53	308	57	5.6	49	49.	57	5.5	45	4.7
N	48	12	47	18	52	15	54	11.5	62	10.5	56	11
O	52	53	55	48	48	50	54	49	59	47	58	51
P	60	73	61	68	56	92	44	94	46	76	59	78
Q	43	16	44	15	45	14.5	48	15.6	55	19.2	55	14.9

...view full instructions

What is the approximate average price of product Q charged by all the stores together?

Rs. 14,800

Rs. 15,800

Rs. 15,300

Rs. 14,300

Solution

Average price =
{(43 x 16) + (44 x 15) + (45 x 14.5) + (48 x 15.6) + (55 x 18.2) + (55 x 14.9)} x $\frac{1000}{(43 + 44 + 45 + 48 + 55 + 55)}$

= {688 + 660 + 652.5 + 748.8 + 1001 + 819.5} x $\frac{1000}{(43 + 44 + 45 + 48 + 55 + 55)}$

= 4569.8 x $\frac{1000}{290}$ = 15,800 (approx.)

Hence, the correct option is (b).

Question 4

1 / -0.25

Directions For Questions

Store	A		B		C		D		E		F
Product	N	P	N	P	N	P	N	P	N	P	N	P
L	54	135	48	112	60	104	61	124	40	136	48	128
M	71	4.5	53	308	57	5.6	49	49.	57	5.5	45	4.7
N	48	12	47	18	52	15	54	11.5	62	10.5	56	11
O	52	53	55	48	48	50	54	49	59	47	58	51
P	60	73	61	68	56	92	44	94	46	76	59	78
Q	43	16	44	15	45	14.5	48	15.6	55	19.2	55	14.9

...view full instructions

What is the difference between the amount earned by store A through the sale of P-type products and that earned by store B through the sale of Q-type products?

Rs. 38.4 lakh

Rs. 0.384 lakh

Rs. 3.84 lakh

Rs. 384 lakh

Solution

Amount earned by store A through the sale of P-type products = Rs. 60 x 75 x 1000 = Rs. 45 lakh

Amount earned by store B through the sale of Q-type products = Rs. 44 x 15 x 1000 = Rs. 6.6 lakh

Difference = Rs. 45 lakh - Rs. 6.6 lakh = Rs. 38.4 lakh

Hence, the correct option is (a).

Question 5

1 / -0.25

Directions For Questions

Store	A		B		C		D		E		F
Product	N	P	N	P	N	P	N	P	N	P	N	P
L	54	135	48	112	60	104	61	124	40	136	48	128
M	71	4.5	53	308	57	5.6	49	49.	57	5.5	45	4.7
N	48	12	47	18	52	15	54	11.5	62	10.5	56	11
O	52	53	55	48	48	50	54	49	59	47	58	51
P	60	73	61	68	56	92	44	94	46	76	59	78
Q	43	16	44	15	45	14.5	48	15.6	55	19.2	55	14.9

...view full instructions

What is the total amount earned by store C through the sale of product types M and O together?

Rs. 2719.2 lakh

Rs. 271.92 lakh

Rs. 2.7192 lakh

Rs. 27.192 lakh

Solution

Total amount earned by store C through the sale of product types M and O together = (57 x 5.6 + 48 x 50) x 1000

= 2719.2 x 1000 = Rs. 27.192 lakh

Hence, the correct option is (d).

Question 6
1 / -0.25

In an arithmetic series, the sum of the second term and the fifth term is 24. The sixth term is greater than the third term by 12. What is the first term of the series?

A
1

B
2

C
3

D
4

Solution

Since difference between 6th and 3rd term is 12
Common difference = $\frac{12}{3}$ = 4
Let 2nd term be x
Therefore, 5th term = x + 12
As per question, x + x + 12 = 24
Therefore, x = $\frac{12}{2}$ = 6
So, 2nd term = 6
Therefore, 1st term = 6 - 4 = 2.

Hence, the correct option is (b).
Question 7
1 / -0.25

In a triangle XYZ, P is any point on YZ such that YP : PZ = 1 : 2. Similarly, Q is any point on XY such that XQ : QY = 1 : 2. If R is the midpoint of PQ, find the ratio of the area of $∆$ XRZ and the area of $∆$ XYZ. Given that the area of $∆$ YPQ = $\frac{2}{9}$ (area of $∆$ XYZ).

A
1 : 2

B
1 : 3

C
1 : 4

D
1 : 5

Solution

For triangles YRQ and YRP, RQ and RP are equal because R is the mid-point of PQ.
Also, because these two triangles are formed on a straight plane—PQ by joining it to a common point—Y, the height of the 2 triangles would also be the same.
Hence with the same height and equal base, the 2 triangles have the same area.
Let the area of these two triangles be 2 units each.
Then, ΔYPQ = 4 units.
Also, ΔYPQ = $\frac{2}{9}$ ΔXYZ.
So 4 = $\frac{2}{9}$ ΔXYZ.
Hence ΔXYZ = 18 units.
Now, because Q is dividing XY in the ratio of 1 : 2,
the area of the triangle XQR would be half of the area of triangle YQR.
Hence, area of triangle XQR = 1 unit.
Similarly, area of triangle ZRP would be double the area of triangle YRP.
Hence, area of triangle ZRP = 2 units.
Now, - ΔYRP = ΔYRQ = 2 units, ΔXQR = 1 unit, ΔZRP= 4 units and balance ΔXRZ = 9 units (18 - 2 - 2 - 1- 4)
So, desired ratio - ΔXRZ : ΔXYZ = $\frac{9}{18}$ = $\frac{1}{2}$ = 1 : 2.

Hence, the correct option is (a).
Question 8
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Using the letters from the word 'TRAPEZIUM', how many combinations of 5 letters can be formed such that they have exactly 3 consonants?

A
120

B
600

C
3,600

D
7,200

Solution

TRAPEZIUM has 5 consonants (TRPZM) and 4 vowels (AEIU).

Now, the total number of ways of selecting 3 consonants from 5 = ⁵C₃
And, the total number of ways of selecting 2 consonants from 4 = ⁴C₂
Thus,the total groups of 5 letter words = ⁵C₃ × ⁴C₂ = 10 × 6 = 60
Note that each of these groups contains 5 letters (3 consonants and 2 vowels).
These 5 letters can be arranged amongst themselves in 5! ways = 5 × 4 × 3 × 2 × 1 =120 ways.

Therefore, total number of possible combinations = 60 × 120 = 7200.

Hence, the correct option is (d).
Question 9
1 / -0.25

If two supplementary angles are in the ratio 7: 11, then what are these angles?

A
70º, 110º

B
80º, 110º

C
90º, 110º

D
100º, 110º

Solution

Let the two angles be 7x and 11x
Now, we know that supplementary angles add up to 180°
Therefore, 7x + 11x = 180
Or, 18x = 180
Or, x = $\frac{180}{18}$ = 10
Therefore, the two angles are 70° (7 × 10) and 110° (11 × 10).

Hence, the correct option is (a).
Question 10
1 / -0.25

Directions: This problem consists of a question and two statements, labelled (1) and (2), in which certain data are given. Using the information provided and general knowledge, decide whether the information given is sufficient to solve the problem.

What is the number of trailing zeros when P! is converted to base ‘x’?

(1) 100 < P < 105

(2) ‘x’ can be 53 or 59.

A
Statement (1) ALONE is sufficient, but statement (2) ALONE is not sufficient.

B
Statement (2) ALONE is sufficient, but statement (1) ALONE is not sufficient.

C
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D
EACH statement ALONE is sufficient.

Solution

Using statement 1 alone:
We cannot answer the question as we must be knowing to which base we need to convert P!
Using statement 2 alone:
We cannot answer the question as we need to know the value of P
Using both statements together:
We know P can have values from 101 to 104 & x is 53 or 59. Now, using no. of pairs of 2 & 5 (as 10 = 2 × 5) we can find the required solution.

Hence, the correct option is (c).

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Re-Attempt Weekly Quiz Competition

Quantitative Aptitude Test - 11

Result

Quantitative Aptitude Test - 11

Score

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Rank

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SHARING IS CARING

Question 1

76.33

124

83.33

120

Solution

Question 2

119 : 104

102 : 115

117 : 103

None of these

Solution

Question 3

Rs. 14,800

Rs. 15,800

Rs. 15,300

Rs. 14,300

Solution

Question 4

Rs. 38.4 lakh

Rs. 0.384 lakh

Rs. 3.84 lakh

Rs. 384 lakh

Solution

Question 5

Rs. 2719.2 lakh

Rs. 271.92 lakh

Rs. 2.7192 lakh

Rs. 27.192 lakh

Solution

Question 6

1

2

3

4

Solution

Question 7

1 : 2

1 : 3

1 : 4

1 : 5

Solution

Question 8

120

600

3,600

7,200

Solution

Question 9

70º, 110º

80º, 110º

90º, 110º

100º, 110º

Solution

Question 10

Statement (1) ALONE is sufficient, but statement (2) ALONE is not sufficient.

Statement (2) ALONE is sufficient, but statement (1) ALONE is not sufficient.

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

EACH statement ALONE is sufficient.

Solution

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